Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress \(50 \%\), or 2 seconds to compress \(60 \%\). (a) Calculate the bandwidth at which each compression option takes the same total compression + transmission time. (b) Explain why latency does not affect your answer.

Short Answer

Expert verified
The bandwidth is 0.1 MB/sec. Latency does not affect the comparison as it is constant.

Step by step solution

01

Understand the Problem

We need to calculate the file transfer times for two compression options and find the bandwidth at which these times are equal.
02

Define Variables

Let the original file size be 1 MB. Define the bandwidth as B MB/sec.
03

Calculate Time for 50% Compression

For 50% compression, the file size becomes 0.5 MB. The time taken for compression is 1 second. The transmission time is \(\frac{0.5}{B}\). The total time is 1 + \(\frac{0.5}{B}\) seconds.
04

Calculate Time for 60% Compression

For 60% compression, the file size becomes 0.4 MB. The time taken for compression is 2 seconds. The transmission time is \(\frac{0.4}{B}\). The total time is 2 + \(\frac{0.4}{B}\) seconds.
05

Set Equations Equal

Set the total times from both methods equal to find B: \[ 1 + \frac{0.5}{B} = 2 + \frac{0.4}{B} \]
06

Solve for Bandwidth (B)

Rearrange to get: \[ 1 - 2 = \frac{0.4}{B} - \frac{0.5}{B} \] \[ -1 = \frac{-0.1}{B} \] \[ B = 0.1 \text{ MB/sec} \]
07

Explain Why Latency Doesn't Affect the Answer

Latency is a constant delay that does not change with compression. Therefore, it cancels out when comparing total times.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

File Transfer
File transfer refers to the process of moving digital files from one computer to another across a network. Whether you are sending an email with attachments, uploading documents to a cloud service, or transferring data between servers, the efficiency of file transfer is paramount.
The performance of file transfer is influenced by factors such as file size, compression methods, and network bandwidth. By compressing files before sending, we can significantly reduce the transfer time.
In the provided exercise, we have two compression options: 50% and 60%. Compressing files to a smaller size reduces the amount of data transmitted over the network, which can be beneficial in terms of speed and resource utilization. Understanding and optimizing these parameters is crucial for effective data communication.
Bandwidth Calculation
Bandwidth is the maximum rate at which data can be transmitted over a network connection, usually measured in megabytes per second (MB/sec) or megabits per second (Mbps).
In the exercise, we calculated the bandwidth at which the total time for compressing and transferring a file would be the same for two different compression options.
Here's how we solved it:
- For 50% compression, the file size becomes 0.5 MB. The time taken for compression is 1 second, and the transmission time is \(\frac{0.5}{B}\). So, the total time is 1 + \(\frac{0.5}{B}\) seconds.
- For 60% compression, the file size is reduced to 0.4 MB. The time taken for compression is 2 seconds, and the transmission time is \(\frac{0.4}{B}\). Thus, the total time is 2 + \(\frac{0.4}{B}\) seconds.
By setting the total times equal, we get the equation:
\[ 1 + \frac{0.5}{B} = 2 + \frac{0.4}{B} \]
Solving this, we find that the bandwidth \( B \) is 0.1 MB/sec.
This calculation helps us understand how changing compression and transmission rates impacts overall file transfer efficiency.
Latency in Networks
Latency refers to the delay between the sender sending a packet of data and the receiver receiving it. It's measured in milliseconds (ms). High latency can negatively impact the speed of data transmission, making real-time applications, like video calls or online gaming, challenging.
However, in the context of our exercise, latency doesn't affect the result as it remains constant for both compression options. Latency only adds a fixed delay, independent of file size or bandwidth.
For instance, if the network latency is 100 ms, this delay will be the same whether the file is 0.5 MB or 0.4 MB. Hence, when comparing the total times for different compression methods, the latency cancels out.
Understanding the concept of latency helps us design and manage networks more effectively, ensuring that data transfer is as efficient as possible.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that a certain communications protocol involves a per-packet overhead of 100 bytes for headers and framing. We send 1 million bytes of data using this protocol; however, one data byte is corrupted and the entire packet containing it is thus lost. Give the total number of overhead + loss bytes for packet data sizes of \(1000,5000,10,000\), and 20,000 bytes. Which size is optimal?

Calculate the total time required to transfer a \(1000-\mathrm{KB}\) file in the following cases, assuming an RTT of \(100 \mathrm{~ms}\), a packet size of \(1 \mathrm{~KB}\) and an initial \(2 \times\) RTT of "handshaking" before data is sent. (a) The bandwidth is \(1.5 \mathrm{Mbps}\), and data packets can be sent continuously. (b) The bandwidth is \(1.5 \mathrm{Mbps}\), but after we finish sending each data packet we must wait one RTT before sending the next. (c) The bandwidth is "infinite," meaning that we take transmit time to be zero, and up to 20 packets can be sent per RTT. (d) The bandwidth is infinite, and during the first RTT we can send one packet \(\left(2^{1-1}\right)\), during the second RTT we can send two packets \(\left(2^{2-1}\right)\), during the third we can send four \(\left(2^{3-1}\right)\), and so on. (A justification for such an exponential increase will be given in Chapter \(6 .)\)

Consider a closed-loop network (e.g., token ring) with bandwidth \(100 \mathrm{Mbps}\) and propagation speed of \(2 \times 10^{8} \mathrm{~m} / \mathrm{s}\). What would the circumference of the loop be to exactly contain one 250 -byte packet, assuming nodes do not introduce delay? What would the circumference be if there was a node every \(100 \mathrm{~m}\), and each node introduced 10 bits of delay?

How "wide" is a bit on a 1-Gbps link? How long is a bit in copper wire, where the speed of propagation is \(2.3 \times 10^{8} \mathrm{~m} / \mathrm{s}\) ?

Calculate the latency (from first bit sent to last bit received) for the following: (a) 1-Gbps Ethernet with a single store-and-forward switch in the path, and a packet size of 5000 bits. Assume that each link introduces a propagation delay of \(10 \mu \mathrm{s}\) and that the switch begins retransmitting immediately after it has finished receiving the packet. (b) Same as (a) but with three switches. (c) Same as (b) but assume the switch implements "cut-through" switching: It is able to begin retransmitting the packet after the first 128 bits have been received.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free