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In this problem, you will derive the efficiency of a CSMA/CD-like multiple access protocol. In this protocol, time is slotted and all adapters are synchronized to the slots. Unlike slotted ALOHA, however, the length of a slot (in seconds) is much less than a frame time (the time to transmit a frame). Let \(S\) be the length of a slot. Suppose all frames are of constant length \(L=k R S\), where \(R\) is the transmission rate of the channel and \(k\) is a large integer. Suppose there are \(N\) nodes, each with an infinite number of frames to send. We also assume that \(d_{\text {prop }}

Short Answer

Expert verified
Efficiency maximizes with specific \( p \) for fixed \( N \), and approaches 1 for large frame lengths and infinite nodes.

Step by step solution

01

Understanding the Protocol States

The protocol alternates between two states: a productive state lasting exactly \( k \) slots when one node successfully transmits, and a nonproductive state, which consists of collisions or no transmissions and lasts \( x \) slots. Each node sends with probability \( p \).
02

Finding Expected Nonproductive Slots

To find \( x \), note that the probability of exactly one node transmitting is \( Np(1-p)^{N-1} \). The probability of a nonproductive slot, where either no node or more than one node transmits, is \( 1 - Np(1-p)^{N-1} \). Since \( x \) is the expected number of slots before a successful transmission: \( x = \frac{1}{Np(1-p)^{N-1}} - 1 \).
03

Calculating Protocol Efficiency

The efficiency, defined as the ratio \( \frac{k}{k+x} \), is based on productive versus total slots. Substituting \( x \, \): the efficiency \( \text{Efficiency} = \frac{k}{k + \frac{1}{Np(1-p)^{N-1}} - 1} \).
04

Maximizing Efficiency with respect to p

To find the optimal \( p \), we take the derivative of \( \text{Efficiency} = \frac{kNp(1-p)^{N-1}}{1 + (k-1)Np(1-p)^{N-1}} \) with respect to \( p \) and set it to zero to solve for \( p \) that maximizes the efficiency.
05

Behavior of Efficiency as N Approaches Infinity

As \( N \to \infty \), the probability of any one node to successfully capture the channel per slot (\( Np(1-p)^{N-1} \)) approaches \( \frac{1}{N} \) which tends efficiency towards a maximum. Effectively, efficiency approaches the limiting value based on frame size as \( N \to \infty \).
06

Efficiency Approaches 1 with Large Frames

When the frame length \( L = kRS \) is very large, the time spent in productive states dominates, making \( k \rightarrow \infty \), and as a result, the efficiency \( \frac{k}{k+x} \to 1 \).
07

Concluding Remark

The derived protocol efficiency depends on the given parameters and specific calculations for probabilities and expectations in channel usage.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multiple Access Protocol
A multiple access protocol allows multiple network nodes to share the same communication channel effectively. In the context of CSMA/CD (Carrier Sense Multiple Access with Collision Detection), each node tries to access the channel but listens (or senses) the channel first to check if it is currently in use. If the channel is free, a node can attempt to send its frame. However, if two or more nodes attempt to transmit simultaneously, a collision occurs. In CSMA/CD, nodes can detect these collisions, stop transmitting, and try again after a random delay.

The main aim of such protocols is to manage access in a way that maximizes the efficient use of the channel while minimizing the delay caused by potential collisions. By using probability-based decisions on transmission, this protocol balances between channel wastage and usage efficiency.
Channel Efficiency
Channel efficiency is a measure of how effectively the communication channel is being used. In the CSMA/CD protocol described in the exercise, efficiency is calculated as the ratio \( \frac{k}{k+x} \), where \( k \) represents the productive state duration (when successfully transmitting nodes use the channel) and \( x \) is the average duration of the nonproductive state.

Because \( x \) represents the average number of slots taken before a successful transmission occurs, minimizing \( x \) and maximizing \( k \) are key to increasing channel efficiency. Simply put, the more time spent in successful transmissions and the less time in collisions or idle, the better the efficiency. This metric helps network engineers understand and improve the performance of network protocols by adjusting parameters like the slot length and transmission probability.
Transmission Probability
Transmission probability, denoted in the exercise by \( p \), is the likelihood that a node will attempt to transmit during any given slot. It is an essential factor in controlling the occurrence of collisions in a CSMA/CD environment.

Finding the optimal transmission probability is crucial. If \( p \) is too high, many nodes will attempt to send simultaneously, causing frequent collisions. Conversely, if \( p \) is too low, the channel can be underutilized as nodes wait too long before attempting transmission.

The efficiency derived from the CSMA/CD protocol is optimized by selecting the transmission probability that balances successful transmissions against the chance of collisions. By solving efficiency maximization problems, optimal \( p \) values can be mathematically determined, which adapt based on the number of nodes \( N \).
Network Nodes
Network nodes are individual devices or points connected within a network that can send, receive, or manage network data. In the studied protocol, each node has an endless supply of frames and competes for the same channel for transmission. When we increase the number of nodes \( N \), the nature of the collisions and network behavior change.

As \( N \) grows large, the chances of any single node capturing the channel diminishes per slot, necessitating changes in strategy or parameters to maintain channel efficiency. This growing complexity is why protocols often need to self-adjust or be tuned to accommodate the scale of the network in order to optimize performance.

Understanding how network nodes interact under these protocols aids in better design of networking systems that ensure even with many users, the channel remains efficiently utilized.

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Most popular questions from this chapter

Suppose the information portion of a packet ( \(D\) in Figure \(5.3\) ) contains 10 bytes consisting of the 8-bit unsigned binary ASCII representation of string "Networking." Compute the Internet checksum for this data.

Suppose nodes A, B, and C each attach to the same broadcast LAN (through their adapters). If \(\mathrm{A}\) sends thousands of IP datagrams to \(\mathrm{B}\) with each encapsulating frame addressed to the MAC address of B, will C's adapter process these frames? If so, will \(\mathrm{C}\) 's adapter pass the IP datagrams in these frames to the network layer C? How would your answers change if A sends frames with the MAC broadcast address?

Suppose four active nodes - nodes A, B, C and D-are competing for access to a channel using slotted ALOHA. Assume each node has an infinite number of packets to send. Each node attempts to transmit in each slot with probability \(p\). The first slot is numbered slot 1 , the second slot is numbered slot 2 , and so on. a. What is the probability that node A succeeds for the first time in slot \(5 ?\) b. What is the probability that some node (either A, B, C or D) succeeds in slot 4? c. What is the probability that the first success occurs in slot 3 ? d. What is the efficiency of this four-node system?

Suppose nodes \(\mathrm{A}\) and \(\mathrm{B}\) are on the same \(10 \mathrm{Mbps}\) broadcast channel, and the propagation delay between the two nodes is 325 bit times. Suppose CSMA/CD and Ethernet packets are used for this broadcast channel. Suppose node A begins transmitting a frame and, before it finishes, node B begins transmitting a frame. Can A finish transmitting before it detects that B has transmitted? Why or why not? If the answer is yes, then A incorrectly believes that its frame was successfully transmitted without a collision. Hint: Suppose at time \(t=0\) bits, A begins transmitting a frame. In the worst case, A transmits a minimum-sized frame of \(512+64\) bit times. So A would finish transmitting the frame at \(t=512+64\) bit times. Thus, the answer is no, if B's signal reaches A before bit time \(t=512+64\) bits. In the worst case, when does B's signal reach A?

Suppose nodes A and B are on the same \(10 \mathrm{Mbps}\) broadcast channel, and the propagation delay between the two nodes is 245 bit times. Suppose A and \(B\) send Ethernet frames at the same time, the frames collide, and then \(\mathrm{A}\) and \(\mathrm{B}\) choose different values of \(K\) in the CSMA/CD algorithm. Assuming no other nodes are active, can the retransmissions from \(\mathrm{A}\) and \(\mathrm{B}\) collide? For our purposes, it suffices to work out the following example. Suppose A and B begin transmission at \(t=0\) bit times. They both detect collisions at \(t=245\) bit times. Suppose \(K_{A}=0\) and \(K_{B}=1\). At what time does B schedule its retransmission? At what time does A begin transmission? (Note: The nodes must wait for an idle channel after returning to Step 2 -see protocol.) At what time does A's signal reach B? Does B refrain from transmitting at its scheduled time?

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