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Suppose a process in Host C has a UDP socket with port number 6789. Suppose both Host A and Host B each send a UDP segment to Host C with destination port number 6789 . Will both of these segments be directed to the same socket at Host C? If so, how will the process at Host C know that these two segments originated from two different hosts?

Short Answer

Expert verified
Yes, both segments go to the same socket. The process differentiates them using source IPs and ports.

Step by step solution

01

Identify the Destination

Both Host A and Host B send a UDP segment to Host C with the destination port number 6789. In UDP, the destination port number is used to deliver the datagram to the specific socket listening on that port.
02

Understand UDP Socket Functionality

UDP sockets are identified by tuple pairs consisting of the local IP address and the socket's port number. In Host C, the socket is uniquely identified by its local port number (6789 in this case). All segments arriving at this port will be directed to the same UDP socket.
03

Determine Packet Differentiation

Even though both segments are directed to the same socket on Host C, the process can differentiate the two segments by checking their source IP addresses and source port numbers. These are part of the UDP segment metadata.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

UDP Protocol
The User Datagram Protocol (UDP) is a communication protocol used in network applications that need low latency. It's simpler than the Transmission Control Protocol (TCP) because UDP provides a way to send datagrams without establishing a connection first. This lack of connection reduces latency and the overhead involved with maintaining session states.
UDP is particularly useful when applications need to send small packets of data. Since it does not implement retransmission, flow control, or error recovery, it's faster but less reliable than TCP. This makes it ideal for:
  • Live broadcasts
  • Online games
  • Voice over IP (VoIP)
These services prioritize speed and may handle potential errors or data loss within the application itself. UDP does not track data sequencing, so each datagram is independent. This simplicity is both its strength and its weakness.
Source IP Address
The source IP address is a crucial piece of information in a network communication. It identifies the origin of a data packet, allowing the recipient to know where the data came from. When a UDP segment arrives at its destination, the receiving application can examine the source IP address to determine from which host the data was sent.
This feature is beneficial in applications that handle data from multiple hosts or devices. For instance, if Host C receives UDP packets from Hosts A and B, it can distinguish between the two segments because each will have a unique source IP address. This is vital when the same application process requires communication with multiple devices, ensuring that data is processed correctly based on its origin.
Destination Port Number
In network communications, the port number serves as an endpoint for the communication in the operating system. The **destination port number** in a UDP segment directs incoming packets to the appropriate process/application on the host. For example, Host C listens to port 6789, and any UDP segment addressed to this port is routed to Host C's designated application or service.
The destination port is essential because it ensures data is directed to the correct socket. This way, multiple applications or services can run simultaneously on the same server without interfering with each other. When Host A and Host B both send UDP segments to Host C's port 6789, those packets are guaranteed to be handled by the socket associated with that port.
Socket Communication
Sockets are endpoints for sending and receiving data across a network. In the context of UDP, a socket is identified by a combination of an IP address and a port number, forming a unique endpoint for communications. This identifier distinguishes each application within a host, enabling it to communicate over the network.
In Host C, a single UDP socket at port 6789 can receive data from multiple different sources. While every segment is directed to this same socket as indicated by the destination port, the underlying process can ascertain the source using the segment's metadata. Socket communication is the backbone of network applications, as it defines the rules for how data is transferred and received, ensuring that applications remain in sync.
Through socket communication, applications can efficiently handle large numbers of simultaneous connections, directing requests and responses to the correct processes.

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Most popular questions from this chapter

Suppose an application uses \(r d t \quad 3.0\) as its transport layer protocol. As the stop-and-wait protocol has very low channel utilization (shown in the crosscountry example), the designers of this application let the receiver keep sending back a number (more than two) of alternating ACK 0 and ACK 1 even if the corresponding data have not arrived at the receiver. Would this application design increase the channel utilization? Why? Are there any potential problems with this approach? Explain.

Suppose Host A sends two TCP segments back to back to Host B over a TCP connection. The first segment has sequence number 90 ; the second has sequence number 110 . a. How much data is in the first segment? b. Suppose that the first segment is lost but the second segment arrives at B. In the acknowledgment that Host B sends to Host A, what will be the acknowledgment number?

Consider the GBN protocol with a sender window size of 4 and a sequence number range of 1,024 . Suppose that at time \(t\), the next in-order packet that the receiver is expecting has a sequence number of \(k\). Assume that the medium does not reorder messages. Answer the following questions: a. What are the possible sets of sequence numbers inside the sender's window at time \(t\) ? Justify your answer. b. What are all possible values of the ACK field in all possible messages currently propagating back to the sender at time \(t\) ? Justify your answer.

Why is it that voice and video traffic is often sent over TCP rather than UDP in today's Internet? (Hint: The answer we are looking for has nothing to do with TCP's congestion-control mechanism.)

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