Chapter 3: Problem 3
UDP and TCP use 1s complement for their checksums. Suppose you have the following three 8-bit bytes: \(01010011,01100110,01110100\). What is the \(1 \mathrm{~s}\) complement of the sum of these 8-bit bytes? (Note that although UDP and TCP use 16-bit words in computing the checksum, for this problem you are being asked to consider 8-bit sums.) Show all work. Why is it that UDP takes the Is complement of the sum; that is, why not just use the sum? With the 1 s complement scheme, how does the receiver detect errors? Is it possible that a 1-bit error will go undetected? How about a 2-bit error?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.