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Suppose that the roundtrip delay between sender and receiver is constant and known to the sender. Would a timer still be necessary in protocol rdt \(3.0\), assuming that packets can be lost? Explain.

Short Answer

Expert verified
Yes, a timer is still necessary to handle packet loss.

Step by step solution

01

Understanding Protocol rdt 3.0

Protocol rdt 3.0 (reliable data transfer protocol) is designed for communication over channels that may lose or corrupt packets. It uses acknowledgements (ACKs) and negative acknowledgements (NAKs) from the receiver and requires timeouts and retransmissions by the sender to ensure reliable delivery.
02

Defining the Constant Roundtrip Delay

A constant and known roundtrip delay between sender and receiver implies that the time it takes for a packet to travel to the receiver, and for an acknowledgement to travel back, is fixed and predictable. This delay can be incorporated into the timing mechanism of the sender.
03

The Role of the Timer in rdt 3.0

In rdt 3.0, the timer is crucial. It is set when a packet is sent. If an ACK for the packet is not received within the timer's period (due to packet loss), the sender assumes the packet is lost and retransmits. This ensures delivery despite packet loss.
04

Impact of Known Roundtrip Delay on Timer Requirement

Even with a known roundtrip delay, a timer is still necessary. Though the delay is predictable, packet loss still necessitates retransmissions—prompted by the timer. Without the timer, the sender has no mechanism to detect packet loss and initiate a retransmission when ACKs are not received.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reliable Data Transfer
In computer networking, reliable data transfer ensures that data is transmitted accurately and completely from source to destination. Protocol rdt (Reliable Data Transfer) versions, such as rdt 3.0, were developed to handle communication over unreliable channels where packet loss or corruption might occur. The main goal of these protocols is to ensure error-free data delivery, despite these potential issues.
Protocol rdt 3.0 employs several strategies to achieve reliability:
  • Acknowledgments (ACKs): The receiver sends an acknowledgment to the sender upon successfully receiving a packet, ensuring that the sender knows the packet was correctly delivered.
  • Negative Acknowledgments (NAKs): The receiver sends a NAK if the packet is corrupted or lost, prompting the sender to retransmit the data.
  • Timeouts: The sender uses timers to detect lost packets when acknowledgments are not received within a certain period.
These mechanisms work together to ensure that packets are eventually received correctly, allowing robust communication in the presence of errors.
Packet Loss
Packet loss occurs when data packets traveling across a network fail to reach their destination. This may be due to network congestion, faulty hardware, or software issues. In a reliable data transfer scenario like rdt 3.0, dealing with packet loss is crucial for ensuring data integrity.
Packet loss can significantly impact network performance:
  • Data Corruption: Lost packets can lead to incomplete or corrupted data being assembled at the receiver's end.
  • Increased Latency: Retransmissions caused by packet loss can slow down communication, increasing the time it takes for data to be delivered.
To mitigate these issues, protocols like rdt 3.0 employ retransmission strategies based on acknowledgments and timeouts. If a packet is lost, the sender is notified via lack of acknowledgment within a specified time, prompting retransmission. This method ensures that even if packets are lost mid-transmission, the data eventually gets through accurately.
Roundtrip Delay
Roundtrip delay is the total time taken for a data packet to travel from the sender to the receiver and back. It includes propagation times, processing delays, and any queuing delays that occur along the route. In networking protocols like rdt 3.0, understanding and accounting for roundtrip delay is essential for setting timers that guide retransmissions in case of packet loss.
A constant and known roundtrip delay aids in fine-tuning the acknowledgement process:
  • Timer Calibration: Knowing the exact roundtrip time helps in setting precise timers for retransmissions, minimizing unnecessary delays.
  • Predictability: A fixed roundtrip delay makes it easier to predict when acknowledgments should be expected, aiding in timely decision-making regarding retransmissions.
Despite the known delay, timers remain critical in protocols dealing with unreliable channels. Without them, it is challenging to detect and recover from packet loss effectively.
Acknowledgements
Acknowledgements (ACKs) in networking are signals sent by the receiver to indicate successful receipt of a data packet. In reliable data transfer protocols like rdt 3.0, they play a vital role in ensuring data is transmitted accurately and completely.
The process of acknowledgements involves multiple elements:
  • Positive Acknowledgement: When the receiver successfully receives and processes a packet, it sends back an ACK to the sender, confirming that the transmission was successful.
  • Timeout-Triggered Retransmission: If an ACK is not received within a predetermined time due to possible packet loss, the sender will retransmit the packet. This ensures eventual delivery irrespective of network issues.
Without acknowledgements, the sender cannot confirm if the data was received correctly, leading to potential data loss or corruption. ACKs thus provide a reliable means of communication, compensating for the imperfections in network channels.

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Most popular questions from this chapter

Suppose an application uses \(r d t \quad 3.0\) as its transport layer protocol. As the stop-and-wait protocol has very low channel utilization (shown in the crosscountry example), the designers of this application let the receiver keep sending back a number (more than two) of alternating ACK 0 and ACK 1 even if the corresponding data have not arrived at the receiver. Would this application design increase the channel utilization? Why? Are there any potential problems with this approach? Explain.

Suppose the network layer provides the following service. The network layer in the source host accepts a segment of maximum size 1,200 bytes and a destination host address from the transport layer. The network layer then guarantees to deliver the segment to the transport layer at the destination host. Suppose many network application processes can be running at the destination host. a. Design the simplest possible transport-layer protocol that will get application data to the desired process at the destination host. Assume the operating system in the destination host has assigned a 4-byte port number to each running application process. b. Modify this protocol so that it provides a "return address" to the destination process. c. In your protocols, does the transport layer "have to do anything" in the core of the computer network?

Suppose two TCP connections are present over some bottleneck link of rate \(R\) bps. Both connections have a huge file to send (in the same direction over the bottleneck link). The transmissions of the files start at the same time. What transmission rate would TCP like to give to each of the connections?

Suppose Client A initiates a Telnet session with Server S. At about the same time, Client B also initiates a Telnet session with Server S. Provide possible source and destination port numbers for a. The segments sent from \(\mathrm{A}\) to \(\mathrm{S}\). b. The segments sent from \(B\) to \(S\). c. The segments sent from \(S\) to \(A\). d. The segments sent from \(S\) to \(B\). e. If \(A\) and \(B\) are different hosts, is it possible that the source port number in the segments from \(\mathrm{A}\) to \(\mathrm{S}\) is the same as that from \(\mathrm{B}\) to \(\mathrm{S}\) ? f. How about if they are the same host?

Consider the TCP procedure for estimating RTT. Suppose that \(\alpha=0.1\). Let SampleRTT \(_{1}\) be the most recent sample RTT, let SampleRTT \(_{2}\) be the next most recent sample RTT, and so on. a. For a given TCP connection, suppose four acknowledgments have been returned with corresponding sample RTTs: SampleRTT \(_{4}\), SampleRTT \(_{3}\), SampleRTT \(_{2}\), and SampleRTT \(_{1}\). Express EstimatedRTT in terms of the four sample RTTs. b. Generalize your formula for \(n\) sample RTTs. c. For the formula in part (b) let \(n\) approach infinity. Comment on why this averaging procedure is called an exponential moving average.

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