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Consider Figure \(1.19\) (b). Now suppose that there are \(M\) paths between the server and the client. No two paths share any link. Path \(k(k=1, \ldots, M)\) consists of \(N\) links with transmission rates \(R_{I}^{k}, R_{2}^{k}, \ldots, R_{N}^{k}\). If the server can only use one path to send data to the client, what is the maximum throughput that the server can achieve? If the server can use all \(M\) paths to send data, what is the maximum throughput that the server can achieve?

Short Answer

Expert verified
Maximum throughput using one path: \( \max(T_1, T_2, \ldots, T_M) \). Using all paths: \( T_{total} = T_1 + T_2 + \ldots + T_M \).

Step by step solution

01

Understanding Maximum Throughput for One Path

For each individual path, the maximum throughput is limited by the slowest link in that path. This is because data can only travel as fast as the slowest link can handle. For path \(k\), the throughput is determined by the minimum link transmission rate among \(R_1^k, R_2^k, \ldots, R_N^k\).
02

Calculating Throughput for Each Path

We calculate the throughput for each path \(k\) by finding the bottleneck, or the minimum rate among its links: \( T_k = \min(R_1^k, R_2^k, \ldots, R_N^k) \). Repeat this calculation for each \(k\) from 1 to \(M\).
03

Maximum Throughput Using One Path

The maximum throughput that the server can achieve when using only one path is the highest throughput among all individual paths. Therefore, we compute \( \max(T_1, T_2, \ldots, T_M) \).
04

Understanding Maximum Throughput for All Paths

If the server can use all \(M\) paths simultaneously, the total throughput is the sum of the throughputs of all paths. This is because data can be sent over all paths at the same time.
05

Calculating Total Throughput Using All Paths

Sum the throughputs of all the paths: \( T_{total} = T_1 + T_2 + \ldots + T_M \). This gives the maximum throughput when using all paths.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multipath Communication
Multipath communication refers to the strategy of using multiple paths simultaneously to send data from a server to a client. Imagine sending a package to someone using different routes. Each path, or route, can handle different amounts of data depending on their characteristics, known as transmission rates.
When a server has the capability to use multiple paths, it can distribute the data load across these paths. This process can enhance the total amount of data transmitted in a given time, known as throughput. In essence, think of it as using multiple lanes on a highway; more lanes typically result in faster traffic flow, just like how multiple paths can increase data speed.
However, each path might have different conditions affecting its data-carrying capacity. Thus, efficiently managing these paths for optimal throughput is crucial.
Bottleneck Analysis
Bottleneck analysis in network systems is about identifying the point in a network path that limits the data flow. Think of a bottleneck in terms of how it restricts the flow of liquid in a bottle; it’s the tightest part that slows things down.
When we look at a path with several links (sections of the path), the link with the lowest capacity becomes the limiting factor. This link is termed as the bottleneck. For any data to pass through, it has to slow down to match the capacity of the bottleneck link.
By identifying and understanding the bottleneck, network engineers can determine the maximum possible throughput of a single path. This is crucial because the total speed of data transmission is limited by this slowest link.
Transmission Rate
The transmission rate of a network link is the speed at which data is transferred through it. This is measured in data over time, such as gigabits per second (Gbps).
Each link on a path has its own transmission rate, and the path's performance is largely dependent on these rates. For each path utilized in multipath communication, understanding the link rates helps in determining how much data can be efficiently sent through it.
When looking at an individual path, the smallest transmission rate among the links defines the path’s overall capacity. This is because data cannot move faster than its slowest link, similar to how water flow is limited by the narrowest pipe in a series.
Data Transmission
Data transmission involves sending digital information from one place to another over a network path. It's like having messages that need safe delivery from the server to a client.
In networking, data travels through multiple links that form a complete path. Each link's transmission capability affects the overall ability to transmit data quickly and efficiently. In multipath communication, data can be transmitted over several paths at once to improve reliability and speed.
Ensuring efficient data transmission requires an understanding of factors like transmission rates and bottleneck locations. By optimizing these elements, the server can increase overall throughput, enabling faster and more reliable communication between endpoints.

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Most popular questions from this chapter

How long does it take a packet of length 1,000 bytes to propagate over a link of distance \(2,500 \mathrm{~km}\), propagation speed \(2.5 \cdot 10^{8} \mathrm{~m} / \mathrm{s}\), and transmission rate 2 Mbps? More generally, how long does it take a packet of length \(L\) to propagate over a link of distance \(d\), propagation speed \(s\), and transmission rate \(R\) bps? Does this delay depend on packet length? Does this delay depend on transmission rate?

What is the difference between a host and an end system? List several different types of end systems. Is a Web server an end system?

A packet switch receives a packet and determines the outbound link to which the packet should be forwarded. When the packet arrives, one other packet is halfway done being transmitted on this outbound link and four other packets are waiting to be transmitted. Packets are transmitted in order of arrival. Suppose all packets are 1,500 bytes and the link rate is 2 Mbps. What is the queuing delay for the packet? More generally, what is the queuing delay when all packets have length \(L\), the transmission rate is \(R, x\) bits of the currently-being-transmitted packet have been transmitted, and \(n\) packets are already in the queue?

This elementary problem begins to explore propagation delay and transmission delay, two central concepts in data networking. Consider two hosts, A and B, connected by a single link of rate \(R\) bps. Suppose that the two hosts are separated by \(m\) meters, and suppose the propagation speed along the link is \(s\) meters/sec. Host A is to send a packet of size \(L\) bits to Host B. a. Express the propagation delay, \(d_{\text {prop }}\), in terms of \(m\) and \(s\). b. Determine the transmission time of the packet, \(d_{\text {trans }}\), in terms of \(L\) and \(R\). c. Ignoring processing and queuing delays, obtain an expression for the endto- end delay. d. Suppose Host A begins to transmit the packet at time \(t=0\). At time \(t=d_{\text {trans }}\). where is the last bit of the packet? e. Suppose \(d_{\text {prop }}\) is greater than \(d_{\text {trans }} .\) At time \(t=d_{\text {trans }}\), where is the first bit of the packet? f. Suppose \(d_{\text {prop }}\) is less than \(d_{\text {trans }} .\) At time \(t=d_{\text {trans }}\), where is the first bit of the packet? g. Suppose \(s=2.5 \cdot 10^{8}, L=120\) bits, and \(R=56 \mathrm{kbps}\). Find the distance \(m\) so that \(d_{\text {prop }}\) equals \(d_{\text {trans }}^{-}\)

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