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Suppose Host A wants to send a large file to Host B. The path from Host A to Host B has three links, of rates \(R_{1}=500 \mathrm{kbps}, R_{2}=2 \mathrm{Mbps}\), and \(R_{3}=1 \mathrm{Mbps}\). a. Assuming no other traffic in the network, what is the throughput for the file transfer? b. Suppose the file is 4 million bytes. Dividing the file size by the throughput, roughly how long will it take to transfer the file to Host B? c. Repeat (a) and (b), but now with \(R_{2}\) reduced to \(100 \mathrm{kbps}\).

Short Answer

Expert verified
(a) Throughput is 500 kbps. (b) Transfer time is 64 seconds. (c) With reduced \(R_2\), throughput is 100 kbps and transfer time is 320 seconds.

Step by step solution

01

Identify the Bottleneck Link

In a network path, the throughput is constrained by the link with the smallest transmission rate. Thus, examine the rates: \(R_1 = 500 \text{ kbps}, R_2 = 2 \text{ Mbps}, R_3 = 1 \text{ Mbps}\). The bottleneck link is \(R_1 = 500 \text{ kbps}\), which is the smallest rate among the links.
02

Calculate the Throughput for Part (a)

For part (a), since \(R_1\) is the bottleneck, the throughput is \(500 \text{ kbps}\). This means that data can be transferred at this rate along the entire path because \(R_2\) and \(R_3\) can handle more data than \(R_1\) can pass through.
03

Convert File Size for Calculation

The file size given is 4 million bytes. Convert this to bits for consistency with the throughput rate: \(4,000,000 \text{ bytes} \times 8 = 32,000,000 \text{ bits}.\)
04

Calculate Transfer Time for Part (b)

To find the transfer time, divide the file size in bits by the throughput: \[\text{Transfer Time} = \frac{32,000,000 \text{ bits}}{500,000 \text{ bits per second}} = 64 \text{ seconds}.\]
05

Adjust Network for New Conditions

For part (c), reduce \(R_2\) to \(100 \text{ kbps}.\) Re-evaluate the network to find the new bottleneck, which is now \(R_2 = 100 \text{ kbps}\), smaller than \(R_1\) and \(R_3\).
06

Calculate Throughput for Adjusted Network

Under the new condition, the throughput is \(100 \text{ kbps}\) since \(R_2\) is now the bottleneck.
07

Recalculate Transfer Time for Part (c)

With the new bottleneck, recalculate the transfer time:\[\text{Transfer Time} = \frac{32,000,000 \text{ bits}}{100,000 \text{ bits per second}} = 320 \text{ seconds}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bottleneck Link
In any network path, the concept of a bottleneck link is crucial as it determines the maximum throughput achievable along that path. Let's think of each link as a pipe carrying data. The link with the smallest bandwidth, or transmission rate, acts like the narrowest pipe in a series, restricting the flow no matter how wide the other pipes are.
For example, given three links with rates of 500 kbps, 2 Mbps, and 1 Mbps, the smallest rate is the bottleneck. Here, 500 kbps on the first link confines the data flow, even though the subsequent links can handle higher rates. Changing the network could change the bottleneck. It depends on the comparative rates of each link in the network path.
File Transfer Time
File transfer time is a critical metric for understanding how long it will take to move data from one host to another over a network. It is essentially the time required to transmit all packets of a file across the network path.
  • First, convert the file size into bits (since transmission rates are in bits per second). For instance, a 4 million byte file equates to 32 million bits.
  • To find the transfer time, divide the total number of bits by the network throughput, which, due to the bottleneck link, is the minimum transmission rate.
In our example, with a throughput of 500 kbps, the time needed is 64 seconds. If a link's rate decreases, as in reducing the second link to 100 kbps, it becomes the new bottleneck and the transfer time increases to 320 seconds.
Transmission Rate
The transmission rate of a network link is its capacity to pass data, typically given in bits per second (bps). This rate can be thought of as how fast you can pour data into the link, analogous to how much water a pipe can carry in a given amount of time.
The rate is pivotal in determining the overall efficiency of information flow in a network. For our case:
  • Link 1 has a rate of 500 kbps.
  • Link 2 originally at 2 Mbps.
  • Link 3 at 1 Mbps.
Reduction in the transmission rate of any link can lead to a new bottleneck, such as lowering Link 2 to 100 kbps. Each link's rate directly influences both throughput and thus, transfer time.
Network Path
A network path is the route data takes from one host to another, passing through various interconnected links or nodes. It is crucial for understanding the potential delays and capacity limitations occurring during data transfer.
The path's performance is determined by several factors, but notably:
  • The number of links within the path.
  • The transmission rate of each link on that path.
In scenarios where no other network traffic exists, the path's throughput matches the rate of the slowest link. This indicates that the path's efficiency and overall transfer speed rely heavily on the link with the least capacity—again, the bottleneck.

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Most popular questions from this chapter

(a) Suppose \(N\) packets arrive simultaneously to a link at which no packets are currently being transmitted or queued. Each packet is of length \(L\) and the link has transmission rate \(R\). What is the average queuing delay for the \(N\) packets? (b) Now suppose that \(N\) such packets arrive to the link every \(L N / R\) seconds. What is the average queuing delay of a packet?

This elementary problem begins to explore propagation delay and transmission delay, two central concepts in data networking. Consider two hosts, A and B, connected by a single link of rate \(R\) bps. Suppose that the two hosts are separated by \(m\) meters, and suppose the propagation speed along the link is \(s\) meters/sec. Host A is to send a packet of size \(L\) bits to Host B. a. Express the propagation delay, \(d_{\text {prop }}\), in terms of \(m\) and \(s\). b. Determine the transmission time of the packet, \(d_{\text {trans }}\), in terms of \(L\) and \(R\). c. Ignoring processing and queuing delays, obtain an expression for the endto- end delay. d. Suppose Host A begins to transmit the packet at time \(t=0\). At time \(t=d_{\text {trans }}\). where is the last bit of the packet? e. Suppose \(d_{\text {prop }}\) is greater than \(d_{\text {trans }} .\) At time \(t=d_{\text {trans }}\), where is the first bit of the packet? f. Suppose \(d_{\text {prop }}\) is less than \(d_{\text {trans }} .\) At time \(t=d_{\text {trans }}\), where is the first bit of the packet? g. Suppose \(s=2.5 \cdot 10^{8}, L=120\) bits, and \(R=56 \mathrm{kbps}\). Find the distance \(m\) so that \(d_{\text {prop }}\) equals \(d_{\text {trans }}^{-}\)

Suppose users share a 2 Mbps link. Also suppose each user transmits continuously at \(1 \mathrm{Mbps}\) when transmitting, but each user transmits only 20 percent of the time. (See the discussion of statistical multiplexing in Section 1.3.) a. When circuit switching is used, how many users can be supported? b. For the remainder of this problem, suppose packet switching is used. Why will there be essentially no queuing delay before the link if two or fewer users transmit at the same time? Why will there be a queuing delay if three users transmit at the same time? c. Find the probability that a given user is transmitting. d. Suppose now there are three users. Find the probability that at any given time, all three users are transmitting simultaneously. Find the fraction of time during which the queue grows.

Consider sending a large file of \(F\) bits from Host A to Host B. There are three links (and two switches) between \(A\) and \(B\), and the links are uncongested (that is, no queuing delays). Host A segments the file into segments of \(S\) bits each and adds 80 bits of header to each segment, forming packets of \(L=80+S\) bits. Each link has a transmission rate of \(R\) bps. Find the value of \(S\) that minimizes the delay of moving the file from Host A to Host B. Disregard propagation delay.

In this problem, we consider sending real-time voice from Host A to Host B over a packet-switched network (VoIP). Host A converts analog voice to a digital \(64 \mathrm{kbps}\) bit stream on the fly. Host A then groups the bits into 56 -byte packets. There is one link between Hosts A and B; its transmission rate is 2 Mbps and its propagation delay is \(10 \mathrm{msec}\). As soon as Host A gathers a packet, it sends it to Host B. As soon as Host B receives an entire packet, it converts the packet's bits to an analog signal. How much time elapses from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B)?

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