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How long does it take a packet of length 1,000 bytes to propagate over a link of distance \(2,500 \mathrm{~km}\), propagation speed \(2.5 \cdot 10^{8} \mathrm{~m} / \mathrm{s}\), and transmission rate 2 Mbps? More generally, how long does it take a packet of length \(L\) to propagate over a link of distance \(d\), propagation speed \(s\), and transmission rate \(R\) bps? Does this delay depend on packet length? Does this delay depend on transmission rate?

Short Answer

Expert verified
Propagation delay is 0.01 seconds and depends only on distance and speed, not packet length or transmission rate.

Step by step solution

01

Understanding Propagation Delay

Propagation delay is the time it takes for a signal to propagate from the sender to the receiver over a specific distance with a given speed. It is calculated using the formula \( \text{Propagation Delay} = \frac{d}{s} \), where \(d\) is the distance and \(s\) is the propagation speed.
02

Calculate Propagation Delay for Given Values

Substitute the given values into the propagation delay formula. Here, \(d = 2500 \times 10^3 \) meters and \(s = 2.5 \times 10^8 \) m/s, so: \[ \text{Propagation Delay} = \frac{2500 \times 10^3}{2.5 \times 10^8} = 0.01 \text{ seconds} \]
03

Understand Impact of Packet Length and Transmission Rate

Propagation delay depends solely on the distance and propagation speed, not on the packet length \(L\) or the transmission rate \(R\). Therefore, when calculating propagation delay, we do not consider these.
04

Answer General Question About Propagation Delay Dependency

The propagation delay \( \frac{d}{s} \) depends only on the distance \(d\) and the propagation speed \(s\). It does not depend on the packet length \(L\) or the transmission rate \(R\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Packet Length
Packet length refers to the size or amount of data that is packed into one unit, often measured in bytes. In computer networks, the packet length can affect how data is sent and processed. A packet has a header and data payload, where the length of the payload determines the total packet length.
They vary depending on the protocol used and the amount of information sent. In our example, the packet length is 1,000 bytes. Understanding packet length is important because in a network, a larger packet might take longer to transmit, depending on the transmission rate.
While packet length is vital for determining transmission time, it doesn't affect propagation delay. Propagation delay is purely a function of physical distance and speed, as the delay is governed by how fast the signal travels through the medium.
Transmission Rate
Transmission rate, or bandwidth, is the rate at which data is transmitted over a network. It is mainly measured in bits per second (bps). In our case, the transmission rate is 2 Mbps (Megabits per second). This is a critical factor in determining how quickly one packet can be sent from the source to the destination.
The transmission rate indicates how much data can travel across the network in one second:
  • If the transmission rate is high, data can be sent faster.
  • If it's lower, more time is required to send the same amount of data.
However, it's important to note that the transmission rate impacts the overall time to send the packet, not the propagation delay. Propagation delay is unaffected by how fast data is being sent once the transmission is complete.
Propagation Speed
Propagation speed is the speed at which the signal travels through the medium (like wire or cable). Its value depends on the type of material used and the signal characteristics. In our exercise, the propagation speed is given as \(2.5 \times 10^8 \) meters per second, which is a typical value close to the speed of light.
The propagation speed is crucial for determining the propagation delay, calculated as the distance divided by the speed. For example:
  • Faster propagation speeds lead to shorter delays.
  • Slower speeds result in longer delays.
It is important to remember that propagation speed impacts only the time it takes for the signal to travel the distance, not how long it takes to transmit the data OVER that distance.
Distance
Distance in networking context refers to the physical space the signal must cover from sender to receiver. It is often measured in kilometers, meters, or miles. In our scenario, the distance is 2,500 km. This concept heavily influences propagation delay, as the signal must physically traverse this space.
The relationship between distance and propagation delay is direct:
  • The longer the distance, the greater the propagation delay.
  • Shorter distances translate to reduced delay times.
Understanding this concept is important, especially when planning network topologies. Networks with long-range communication will experience longer delay times simply due to the increased distances involved. This is crucial for applications requiring real-time data transmission.

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Most popular questions from this chapter

Suppose users share a 2 Mbps link. Also suppose each user transmits continuously at \(1 \mathrm{Mbps}\) when transmitting, but each user transmits only 20 percent of the time. (See the discussion of statistical multiplexing in Section 1.3.) a. When circuit switching is used, how many users can be supported? b. For the remainder of this problem, suppose packet switching is used. Why will there be essentially no queuing delay before the link if two or fewer users transmit at the same time? Why will there be a queuing delay if three users transmit at the same time? c. Find the probability that a given user is transmitting. d. Suppose now there are three users. Find the probability that at any given time, all three users are transmitting simultaneously. Find the fraction of time during which the queue grows.

Consider Figure \(1.19\) (b). Now suppose that there are \(M\) paths between the server and the client. No two paths share any link. Path \(k(k=1, \ldots, M)\) consists of \(N\) links with transmission rates \(R_{I}^{k}, R_{2}^{k}, \ldots, R_{N}^{k}\). If the server can only use one path to send data to the client, what is the maximum throughput that the server can achieve? If the server can use all \(M\) paths to send data, what is the maximum throughput that the server can achieve?

List six access technologies. Classify each one as home access, enterprise access, or wide-area wireless access.

Suppose users share a 3 Mbps link. Also suppose each user requires \(150 \mathrm{kbps}\) when transmitting, but each user transmits only 10 percent of the time. (See the discussion of packet switching versus circuit switching in Section 1.3.) a. When circuit switching is used, how many users can be supported? b. For the remainder of this problem, suppose packet switching is used. Find the probability that a given user is transmitting. c. Suppose there are 120 users. Find the probability that at any given time, exactly \(n\) users are transmitting simultaneously. (Hint: Use the binomial distribution.) d. Find the probability that there are 21 or more users transmitting simultaneously.

Suppose two hosts, A and B, are separated by 20,000 kilometers and are connected by a direct link of \(R=2\) Mbps. Suppose the propagation speed over the link is \(2.5 \cdot 10^{8}\) meters/sec. a. Calculate the bandwidth-delay product, \(R \cdot d_{\text {prop }}\) b. Consider sending a file of 800,000 bits from Host A to Host B. Suppose the file is sent continuously as one large message. What is the maximum number of bits that will be in the link at any given time? c. Provide an interpretation of the bandwidth-delay product. d. What is the width (in meters) of a bit in the link? Is it longer than a football field? e. Derive a general expression for the width of a bit in terms of the propagation speed \(s\), the transmission rate \(R\), and the length of the link \(m\).

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