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Suppose there is exactly one packet switch between a sending host and a receiving host. The transmission rates between the sending host and the switch and between the switch and the receiving host are \(R_{1}\) and \(R_{2}\), respectively. Assuming that the switch uses store-and-forward packet switching, what is the total end-to-end delay to send a packet of length \(L ?\) (Ignore queuing, propagation delay, and processing delay.)

Short Answer

Expert verified
Total end-to-end delay is \( \frac{L}{R_1} + \frac{L}{R_2} \).

Step by step solution

01

Understand the Problem

In this problem, we're supposed to calculate the total end-to-end delay for a packet of length \( L \) sent from the sending host to the receiving host through one packet switch. The transmission rates are \( R_1 \) for the link between the sending host and the switch, and \( R_2 \) for the link between the switch and the receiving host. We are using store-and-forward packet switching, and we need to ignore queuing delays, propagation delays, and processing delays.
02

Calculate Transmission Delay Between Sending Host and Switch

The transmission delay for sending the packet from the sending host to the switch is calculated using the formula: \[ \text{Transmission Delay} = \frac{L}{R_1} \] where \( L \) is the packet length and \( R_1 \) is the transmission rate of the link between the sending host and the switch.
03

Calculate Transmission Delay Between Switch and Receiving Host

The transmission delay for sending the packet from the switch to the receiving host is given by: \[ \text{Transmission Delay} = \frac{L}{R_2} \] where \( L \) is the packet length and \( R_2 \) is the transmission rate of the link between the switch and the receiving host.
04

Calculate Total End-to-End Delay

The total end-to-end delay is the sum of the transmission delays calculated in Step 2 and Step 3. Hence, it is given by: \[ \text{Total Delay} = \frac{L}{R_1} + \frac{L}{R_2} \] This sum includes the time needed for the packet to be transmitted to the switch and then from the switch to the receiving host.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transmission Rate
The transmission rate is a crucial concept in networking. It refers to the speed at which data can be transmitted over a network link. Measured in bits per second (bps), the transmission rate determines how quickly data packets, the building blocks of network communication, can be sent from one point to another. In packet switching, the transmission rate impacts the time it takes for a packet to be transmitted from one device to another. Understanding the transmission rate is essential because it directly affects the efficiency of data transfer. A higher transmission rate means data can be sent more quickly, reducing wait times in communication. On the contrary, a lower transmission rate results in a slower transfer, which might not be ideal for time-sensitive transmissions like video conferencing or online gaming. When working out problems related to packet switching, like in the original exercise, calculating how long it takes a packet of information to travel over each link requires knowledge of the respective transmission rates. These rates, represented as \( R_1 \) and \( R_2 \) for different segments of a network path, help in understanding and optimizing the network performance.
End-to-End Delay
End-to-end delay encompasses the total time taken for a packet to travel from the source to the destination. This delay includes several components, but in the context of our simplified exercise, we only consider the transmission delays since other factors (like queuing, propagation, and processing delays) are ignored.To solve for the end-to-end delay, we break it down into different segments:
  • The first segment is from the sending host to the switch with a transmission delay of \( \frac{L}{R_1} \), where \( L \) is the packet length and \( R_1 \) is the transmission rate between these nodes.
  • The second is from the switch to the receiving host, represented as \( \frac{L}{R_2} \).
  • The total end-to-end delay is the sum of these two individual transmission delays, resulting in \( \frac{L}{R_1} + \frac{L}{R_2} \).
Understanding these calculations helps highlight how network elements and their individual performance characteristics contribute to the overall delay experienced by data packets. This insight is valuable for optimizing network infrastructure and improving communication efficiency.
Store-and-Forward
The store-and-forward technique is a fundamental mechanism in packet-switched networks. It involves storing the entire packet at each point (or node) in the network before forwarding it to the next point. This method ensures that packets are received in their entirety before being processed and sent on, minimizing errors and improving the reliability of data transmission.With store-and-forward, routers and switches within a network can examine the packet data, perform necessary checks, and make forwarding decisions. This approach, although slightly delayed due to the need to store the data fully, is beneficial for handling complex network protocols and ensuring data integrity, especially on noisy links or those with high error rates.In the context of the original exercise, store-and-forward means:
  • The packet is first fully received and stored at the switch, incurring no additional delay beyond the transmission delay since queuing and processing are ignored.
  • Once stored, the switch then forwards the packet to the receiving host at the given transmission rate, \( R_2 \).
This method is contrasted with other packet-switching strategies that might begin forwarding data before the entire packet is received, which can reduce latency but at the risk of greater transmission errors.

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Most popular questions from this chapter

Suppose Host A wants to send a large file to Host B. The path from Host A to Host B has three links, of rates \(R_{1}=500 \mathrm{kbps}, R_{2}=2 \mathrm{Mbps}\), and \(R_{3}=1 \mathrm{Mbps}\). a. Assuming no other traffic in the network, what is the throughput for the file transfer? b. Suppose the file is 4 million bytes. Dividing the file size by the throughput, roughly how long will it take to transfer the file to Host B? c. Repeat (a) and (b), but now with \(R_{2}\) reduced to \(100 \mathrm{kbps}\).

What is the transmission rate of Ethernet LANs?

What advantage does a circuit-switched network have over a packet-switched network? What advantages does TDM have over FDM in a circuit-switched network?

A packet switch receives a packet and determines the outbound link to which the packet should be forwarded. When the packet arrives, one other packet is halfway done being transmitted on this outbound link and four other packets are waiting to be transmitted. Packets are transmitted in order of arrival. Suppose all packets are 1,500 bytes and the link rate is 2 Mbps. What is the queuing delay for the packet? More generally, what is the queuing delay when all packets have length \(L\), the transmission rate is \(R, x\) bits of the currently-being-transmitted packet have been transmitted, and \(n\) packets are already in the queue?

Suppose users share a 3 Mbps link. Also suppose each user requires \(150 \mathrm{kbps}\) when transmitting, but each user transmits only 10 percent of the time. (See the discussion of packet switching versus circuit switching in Section 1.3.) a. When circuit switching is used, how many users can be supported? b. For the remainder of this problem, suppose packet switching is used. Find the probability that a given user is transmitting. c. Suppose there are 120 users. Find the probability that at any given time, exactly \(n\) users are transmitting simultaneously. (Hint: Use the binomial distribution.) d. Find the probability that there are 21 or more users transmitting simultaneously.

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