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Consider the following statements: int num1, num2, num3; double length, width, height; double volume; num1 = 6; num2 = 7; num3 = 4; length = 6.2; width = 2.3; height = 3.4 and the function prototype: double box(double, double, double); Which of the following statements are valid? If they are invalid, explain why. a. volume = box(length, width, height); b. volume = box(length, 3.8, height); c. cout << box(num1, num3, num2) << endl; d. cout << box(length, width, 7.0) << endl; e. volume = box(length, num1, height); f. cout << box(6.2, , height) << endl; g. volume = box(length + width, height); h. volume = box(num1, num2 + num3);

Short Answer

Expert verified
Valid: a, b, c, d, e. Invalid: f, g, h (wrong number of arguments).

Step by step solution

01

Validate Data Compatibility

Based on the function prototype given, `double box(double, double, double);`, the box function expects three arguments, each of type `double`. We have to ensure that each function call matches this prototype.
02

Evaluate Statement a

`volume = box(length, width, height);` is valid. All the variables `length`, `width`, and `height` are of type `double`, which matches the function's expected argument types.
03

Evaluate Statement b

`volume = box(length, 3.8, height);` is valid. The literal `3.8` is a `double`, and both `length` and `height` are `double` types. All three arguments are compatible with the expected types.
04

Evaluate Statement c

`cout << box(num1, num3, num2) << endl;` is valid but requires type implicit conversion. The variables `num1`, `num3`, and `num2` are integers, but they can be automatically converted to `double` for the function call.
05

Evaluate Statement d

`cout << box(length, width, 7.0) << endl;` is valid. The literal `7.0` is a `double`, and the other two variables `length` and `width` are `double` types, fitting the function's parameters.
06

Evaluate Statement e

`volume = box(length, num1, height);` is valid with an implicit conversion. `num1` is an `int`, but it can be automatically converted to `double`, fitting the function call requirements.
07

Evaluate Statement f

`cout << box(6.2, , height) << endl;` is invalid. The call is missing a second argument, making it incompatible with the function prototype that requires three arguments.
08

Evaluate Statement g

`volume = box(length + width, height);` is invalid because it only supplies two arguments. The function expects three `double` arguments.
09

Evaluate Statement h

`volume = box(num1, num2 + num3);` is invalid because it only provides two arguments to the function expecting three. `num2 + num3` will be implicitly converted to `double`, but still only forms one argument.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Implicit Type Conversion
In C++, implicit type conversion happens when data types are automatically converted by the compiler to match the required type. It's often referred to as "type coercion". This feature is quite helpful when you want your program to handle different data types seamlessly during operations or function calls.

For example, consider a function that expects arguments of type `double`. If you provide `int` variables instead, the compiler will automatically convert these integers into `double` values. This ensures compatibility between the types without requiring manual intervention.

In the given exercise, statements like `cout << box(num1, num3, num2) << endl;` leverage implicit type conversion. Although `num1`, `num2`, and `num3` are integers, they are automatically coerced into `double` types, aligning perfectly with the function's parameter expectations.
Function Prototype
A function prototype in C++ is a declaration of a function that informs the compiler about the function's name, return type, and parameters, without specifying the function's body. It acts like a contract, ensuring that any function call aligns with the declared prototype.

For example, in the exercise, the function prototype provided is `double box(double, double, double);`. This declaration informs the compiler that any function call to `box` must have three `double` parameters and will return a `double` value.

Prototypes play a critical role in validating function calls. They allow the compiler to catch errors at compile-time if functions are not called with the appropriate number of arguments or with compatible types. This mechanism is essential in maintaining robustness and accuracy within C++ programs.
Data Types in C++
Data types in C++ define the kind of data a variable can hold. They instruct the compiler on how to allocate memory and process the variable's contents. C++ supports various basic data types, including `int`, `double`, `float`, `char`, etc.

In the example provided, the exercise uses `int` for integer values and `double` for decimal numbers. This distinction is crucial as each data type operates differently in terms of memory allocation and precision.
  • `int`: Used for whole numbers, like `num1`, `num2`, and `num3`.
  • `double`: Used for floating-point numbers, providing more precision than a `float`. Variables like `length`, `width`, and `height` are declared as `double`.
Understanding data types is vital for efficient memory use and ensuring calculations are precise and accurate.
Argument Compatibility
Argument compatibility refers to the alignment between the arguments passed in a function call and the parameters expected by that function. Compatibility is essential because mismatched types can lead to unexpected behaviors or compile-time errors.

In C++, argument compatibility primarily focuses on the type and number of arguments. When calling a function, the given arguments must match or be compatible with the declared parameter types in the function's prototype. If implicit conversion is possible, types can be adjusted automatically to fit.

For example, in `volume = box(length, width, height);`, the arguments `length`, `width`, and `height` are all `double` types, aligning perfectly with the `box` function's prototype. On the other hand, `cout << box(num1, num3);` would be invalid because it offers only two integers where three `double` arguments are required, regardless of type conversion capabilities.

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Most popular questions from this chapter

Mark the following statements as true or false: a. To use a predefined function in a program, you need to know only the name of the function and how to use it. b. \(A\) value-returning function returns only one value. c. Parameters allow you to use different values each time the function is called. When a return statement executes in a user-defined function, the function immediately exits. e. A value-returning function returns only integer values. I. A function that changes the value of a reference parameter also changes the value of the actual parameter. a. A variable name cannot be passed to a value parameter. h. If a \(\mathrm{C}++\) function does not use parameters, parentheses around the empty parameter list are still required. I. In \(C++,\) the names of the corresponding formal and actual parameters must be the same. I. Whenever the value of a reference parameter changes, the value of the actual parameter changes. k. In \(\mathrm{C}++,\) function definitions can be nested; that is, the definition of one function can be enclosed in the body of another function. I. Using global variables in a program is a better programming style than using local variables, because extra variables can be avoided. m. In a program, global constants are as dangerous as global variables. n. The memory for a static variable remains allocated between function calls.

include using namespace std; void func1(); void func2(); int main() { int num; cout << "Enter 1 or 2: "; cin >> … # What is the output of the following program? #include using namespace std; void func1(); void func2(); int main() { int num; cout << "Enter 1 or 2: "; cin >> num; cout << endl; cout << "Take "; if (num == 1) func1(); else if (num == 2) func2(); else cout << "Invalid input. You must enter a 1 or 2" << endl; return 0; } void func1() { cout << "Programming I." <

include using namesp… # Consider the following program. What is its exact output? Show the values of the variables after each line executes, as in Example 6-13. #include using namespace std; void funOne(int& a); int main() { int num1, num2; num1 = 10; //Line 1 num2 = 20; //Line 2 cout << "Line 3: In main: num1 = " << num1 << ", num2 = " << num2 << endl; //Line 3 funOne(num1); //Line 4 cout << "Line 5: In main after funOne: num1 = " << num1 << ", num2 = " << num2 << endl; //Line 5 return 0; //Line 6 } void funOne(int& a) { int x = 12; int z; z = a + x; //Line 7 cout << "Line 8: In funOne: a = " << a << ", x = " << x << ", and z = " << z << endl; //Line 8 x = x + 5; //Line 9 cout << "Line 10: In funOne: a = " << a << ", x = " << x << ", and z = " << z << endl; //Line 10 a = a + 8; //Line 11 cout << "Line 12: In funOne: a = " << a << ", x = " << x << ", and z = " << z << endl; //Line 12 }

include using namespace std; void tryMe(int& v); int main() { int x = 8; for (int count = 1; count < 5; count++)… # What is the output of the following program? #include using namespace std; void tryMe(int& v); int main() { int x = 8; for (int count = 1; count < 5; count++) tryMe(x); return 0; } void tryMe(int& v) { static int num = 2; if (v % 2 == 0) { num++; v = v + 3; } else { num--; v = v + 5; } cout << v << ", " << num << endl; }

a. How would you use a return statement in a void function? b. Why would you want to use a return statement in a void function?

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