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Consider the following C++ function: int mystery(int num) { int y = 1; if (num == 0) return 1; else if (num < 0) return -1; else for (int count = 1; count < num; count++) y = y * (num - count); return y; } What is the output of the following statements? a. cout << mystery(6) << endl; b. cout << mystery(0) << endl; c. cout << mystery(-5) << endl; d. cout << mystery(10) << endl;

Short Answer

Expert verified
a. 120, b. 1, c. -1, d. 362880

Step by step solution

01

Understand the Function

The `mystery` function takes an integer `num` as its argument. It returns 1 if `num` is 0, returns -1 if `num` is negative, and calculates a product if `num` is positive.
02

Initialize and Check Base Cases

For `num` equal to 0, the function returns 1 immediately. For negative values of `num`, the function returns -1 as the output.
03

Evaluate Loop for Positive `num`

If `num` is positive, the function initializes `y` to 1 and enters a loop from `count = 1` to `count < num`. Inside the loop, it multiplies `y` by `(num - count)`. The initial value of `y` and loop calculations determine the final output.
04

Compute Output for `mystery(6)`

`y` starts at 1 and the loop modifies `y` as follows: `y = 1 * 5`, `y = 5 * 4`, `y = 20 * 3`, `y = 60 * 2`, `y = 120 * 1`. The loop ends when `count` is 5. Therefore, `mystery(6)` returns 120.
05

Compute Output for `mystery(0)`

Since `num` is 0, the function immediately returns 1.
06

Compute Output for `mystery(-5)`

Because `num` is negative, the function directly returns -1.
07

Compute Output for `mystery(10)`

`y` starts at 1 and the loop modifies `y` as follows: `y = 1 * 9`, `y = 9 * 8`, `y = 72 * 7`, `y = 504 * 6`, `y = 3024 * 5`, `y = 15120 * 4`, `y = 60480 * 3`, `y = 181440 * 2`, `y = 362880 * 1`. Therefore, `mystery(10)` returns 362880.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Loop Structures
In C++, loop structures allow us to execute a block of code multiple times. They are foundational in programming for tasks that need repetition. The `mystery` function uses a `for` loop to perform calculations based on the input value `num`. Each iteration of the loop adjusts the variable `y` by multiplying it with (num - count). This setup helps in calculating factorial-like values, minus the full range from the original number down to 1.

A loop typically consists of:
  • An initialization clause, which sets up the loop variable (e.g., `int count = 1`).
  • A condition that determines whether the loop will continue (e.g., `count < num`).
  • An iteration expression that modifies the loop variable, moving towards the loop termination (e.g., `count++`).
The `mystery` function loop is crucial because it handles the multiplication logic when `num` is positive, determining how many times it iterates. It stops once `count` matches `num`, ensuring that the loop does not mistakenly execute for an unintended range.
Conditional Statements
Conditional statements in C++ are used to perform different actions based on specific conditions. These conditions allow your code to make decisions and respond dynamically. The `mystery` function utilizes `if`, `else if`, and `else` blocks to control the flow based on the provided integer `num`.

Within the `mystery` function:
  • The `if` statement checks `if (num == 0)` and returns `1`. This condition is a direct decision path for the function.
  • The `else if (num < 0)` checks for negative numbers and returns `-1`. This caters to a scenario where the function shouldn't proceed with calculations.
  • The `else` block runs a loop structure for positive numbers, indicating a continuation of the function's process.
This use of conditional statements ensures that the function can quickly respond to different input values, optimizing execution by bypassing unnecessary computations under specific conditions.
Function Output
In C++, functions often provide results via output mechanisms. These outputs represent the final results of a function's internal calculations or logic. The `mystery` function returns an integer based on different input criteria and conditions.

Here's how the output works:
  • If the input `num` is `0`, it outputs `1` immediately without further calculations. This is straightforward since the condition is checked first in the function.
  • For negative inputs, it outputs `-1`. This quickly concludes the function's process for those values, as computation isn't useful in this context.
  • Positive numbers will result in a calculation process through the loop, generating a factorial-like output. After all iterations, the function outputs the computed value of `y`.
This function's output system efficiently uses return statements at different execution points to handle distinct scenarios.
Return Values
Return values in C++ functions are pivotal as they convey the function's result back to its caller. The return values are determined by the conditions and logic within the function, like those in the `mystery` function.

In `mystery`, the return value relies on:
  • A simple return of `1` or `-1` immediately through conditional checks when `num` is `0` or negative, respectively.
  • An iterative calculation process for positive `num`, where the loop modifies `y` to eventually convey the result, outputting the final value at the end of the function.
Using return values effectively allows functions to serve their purpose of processing data or performing operations while offering a clear output result. This concept is fundamental in C++ as it simplifies the task of performing complex calculations while informing other parts of the program of its outcomes.

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Most popular questions from this chapter

include using namespace std; void tryMe(int& v); int main() { int x = 8; for (int count = 1; count < 5; count++)… # What is the output of the following program? #include using namespace std; void tryMe(int& v); int main() { int x = 8; for (int count = 1; count < 5; count++) tryMe(x); return 0; } void tryMe(int& v) { static int num = 2; if (v % 2 == 0) { num++; v = v + 3; } else { num--; v = v + 5; } cout << v << ", " << num << endl; }

Mark the following statements as true or false: a. To use a predefined function in a program, you need to know only the name of the function and how to use it. b. \(A\) value-returning function returns only one value. c. Parameters allow you to use different values each time the function is called. When a return statement executes in a user-defined function, the function immediately exits. e. A value-returning function returns only integer values. I. A function that changes the value of a reference parameter also changes the value of the actual parameter. a. A variable name cannot be passed to a value parameter. h. If a \(\mathrm{C}++\) function does not use parameters, parentheses around the empty parameter list are still required. I. In \(C++,\) the names of the corresponding formal and actual parameters must be the same. I. Whenever the value of a reference parameter changes, the value of the actual parameter changes. k. In \(\mathrm{C}++,\) function definitions can be nested; that is, the definition of one function can be enclosed in the body of another function. I. Using global variables in a program is a better programming style than using local variables, because extra variables can be avoided. m. In a program, global constants are as dangerous as global variables. n. The memory for a static variable remains allocated between function calls.

include using namespace std; int x; void summer(int&, int); void fall(int, int&); int main() { int intNum1 = 2; … # What is the output of the following program? #include using namespace std; int x; void summer(int&, int); void fall(int, int&); int main() { int intNum1 = 2; int intNum2 = 5; x = 6; summer(intNum1, intNum2); cout << intNum1 << " " << intNum2 << " " << x << endl; fall(intNum1, intNum2); cout << intNum1 << " " << intNum2 << " " << x << endl; return 0; } void summer(int& a, int b) { int intNum1; intNum1 = b + 12; a = 2 * b + 5; b = intNum1 + 4; } void fall(int u, int& v) { int intNum2; intNum2= x; v = intNum2 * 4; x = u - v; }

Consider the following function prototypes: int func1(int, double); double func2(string, int, double); char func3(int, int, double, char); string join(string, string); Answer the following questions: a. How many parameters does the function func1 have? What is the type of the function func1? b. How many parameters does function func2 have? What is the type of function func2? c. How many parameters does function func3 have? What is the type of function func3? d. How many parameters does function join have? What is the type of function join? e. How many actual parameters are needed to call the function func1? What is the type of each actual parameter, and in what order should you use these parameters in a call to the function func1? f. Write a C++ statement that prints the value returned by the function func1 with the actual parameters 3 and 8.5. g. Write a C++ statement that prints the value returned by function join with the actual parameters "John" and "Project Manager", respectively. h. Write a C++ statement that prints the next character returned by function func3. (Use your own actual parameters.)

Write the definition of a function that takes as input the three numbers. The function returns true if the first number to the power of the second number equals the third number; otherwise, it returns false. (Assume that the three numbers are of type double.)

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