Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suppose that \(L\) is a sorted list of 4096 elements. What is the maximum number of comparisons made by the binary search algorithm, given in this chapter, to determine if an item is in \(L ?\)

Short Answer

Expert verified
A binary search will make a maximum of 12 comparisons for 4096 elements.

Step by step solution

01

Understanding the Problem

We need to determine the maximum number of comparisons made by a binary search to check for an element in a sorted list of 4096 elements.
02

Binary Search Concept

Binary search works by repeatedly dividing the sorted list in half and checking the middle element. If the middle element is the target, the search ends. Otherwise, we continue with the half where the target could exist.
03

Calculating the Maximum Comparisons

The maximum number of comparisons is determined by how many times we can split the list in half until only a single element remains. This is calculated as the logarithm base 2 of the number of elements.
04

Applying the Formula

The number of times the list can be divided is \ \left\lceil \log_2(n) \right\rceil , \ where \( n \) is the number of elements. For \( n = 4096 \), we have \ \left\lceil \log_2(4096) \right\rceil.
05

Evaluating the Expression

Since 4096 is a power of 2 (\(2^{12}\)), we compute \(\log_2(4096) = 12\). Thus, a binary search will make a maximum of 12 comparisons.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sorted list
A sorted list is an essential prerequisite for performing a binary search. In computer science, a sorted list means that its elements are arranged in a particular order, usually ascending or descending. This order might apply to numbers, letters, or any elements that can be compared. The key to a sorted list is that you can quickly find where an item might be, because you only need to compare each element with the previous or next one in the list.

Imagine you are looking for a word in a dictionary. Because the words are already sorted alphabetically, you can efficiently guess where your target word might be. Similarly, in a sorted list, each item can be found much quicker than in an unsorted list.

The property of being sorted is crucial for binary search algorithms, as it allows the search process to exclude half of the remaining elements with each step. This makes the binary search very powerful and efficient.
logarithmic complexity
Logarithmic complexity is a type of computational complexity that describes an algorithm that can complete its task in a time or number of steps proportional to the logarithm of the size of the input. For binary search, the complexity is typically represented as \( O(\log_2 n) \) where \( n \) is the number of elements in the list.

This efficiency occurs because with each comparison, binary search cuts the problem size in half, rapidly narrowing down the possibilities. When you hear logarithmic complexity, envision an algorithm that gets significantly faster relative to an increase in input size, outperforming linear complexity algorithms as the dataset grows.

It is essential to note that logarithmic complexity is desirable in search algorithms, as it signifies that even a massive dataset can be efficiently managed. This property of the binary search allows it to perform exceptionally well with large datasets when compared to a linear search, which examines each element one by one.
search algorithms
Search algorithms are methods used to find specific data within a structure, like a list or a database. They play a crucial role in many areas of computer science and everyday technology, from searching through contacts in your phone to finding specific documents in your computer.

There are various types of search algorithms, but two common ones are linear search and binary search. A linear search checks each element one by one until it finds the target, which can be time-consuming but works in any dataset, sorted or unsorted. Binary search, in contrast, requires a sorted list and dramatically reduces the number of checks needed by repeatedly reducing the search interval by half.

Binary search stands out because of its efficiency in handling large datasets. This efficiency is due to its logarithmic time complexity, which ensures that even as the dataset size increases, the search remains fast and manageable.
power of two elements
The term "power of two elements" refers to numbers that are powers of two, like 2, 4, 8, 16, 32, etc. In the context of binary search, these numbers hold special significance because they allow for whole divisions when splitting the list.

For binary search to be most optimal, having a list size that is a power of two simplifies calculations and cuts the list cleanly in half at each step. It is especially significant when calculating the maximum number of comparisons needed.

If you have a list with a size that is a power of two, such as 4096 which is \( 2^{12} \), the number of divisions will precisely match the exponent \( \log_2(4096) = 12 \). This means that with each division, the elements are perfectly halved, optimizing the search process. This property of power of two helps to illustrate the efficiency of the binary search in more precise terms.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sort the following list using the bubble sort algorithm as discussed in this chapter. Show the list after each iteration of the outer for loop. \\[ 38,60,43,5,70,58,15,10 \\]

Assume the following list of keys: 25,32,20,15,45,4,18,91,62,88,66 This list is to be sorted using the insertion sort algorithm as described in this chapter for array-based lists. Show the resulting list after seven passes of the sorting phase - that is, after seven iterations of the for loop.

Sort the following list using the bubble sort algorithm as discussed in this chapter. Show the list after each iteration of the outer for loop. \\[ 46,58,16,25,83,98,8,70,5,62 \\]

a. The number of comparisons in the best case of a bubble sort algorithm, as given in this chapter, is \(O\left(n^{2}\right) .\) Show that the following version of the bubble sort algorithm reduces the number of comparisons in the best case of the bubble sort algorithm to \(O(n)\) //list – list to be sorted //elemType – type of the list elements //length – length of the list bool isSorted = false; for (int iteration = 1; (iteration < length) && !isSorted; iteration++) { isSorted = true; //assume that the sublist is sorted for (int index = 0; index < length - iteration; index++) { if (list[index] > list[index + 1]) { elemType temp = list[index]; list[index] = list[index + 1]; list[index + 1] = temp; isSorted = false; } } } b. Using the algorithm given in part (a), find the number of iterations that are needed to sort the following list: 65,14,52,43,75,25,80,90,95

Assume the following list of keys: 48,30,66,50,9,95,80,15,25,18,94,55,3,22,62 This list is to be sorted using the quick sort algorithm as discussed in this chapter. Use pivot as the median of the first, last, and middle elements of the list. a. What is the pivot? b. Give the resulting list after one call to the function partition. c. What is the size of the list that the function partition partitioned? d. What are the sizes of the two sublists created by the function partition?

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free