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Suppose that \(L\) is a list of 10,000 elements. Find the average number of comparisons made by bubble sort, selection sort, and insertion sort to sort \(L\)

Short Answer

Expert verified
Bubble sort and selection sort make approximately 49,995,000 comparisons, while insertion sort makes about 25,000,000.

Step by step solution

01

Understanding the Bubble Sort Comparisons

Bubble sort compares each element with the next one and repeats this for each element in the list, leading to comparisons for each pass through the list. For a list of size \(n\), there are \(n-1\) comparisons in the first pass, \(n-2\) in the second, and so on, until 1 comparison at the end. Thus, the total number of comparisons is \((n-1) + (n-2) + \ldots + 1 = \frac{n(n-1)}{2}\). For a list of size 10,000, the number of comparisons is \(\frac{10000 \times 9999}{2}\).
02

Calculate Comparisons for Bubble Sort

Using the formula derived, calculate the total number of comparisons for bubble sort when sorting 10,000 elements:\[\frac{10000 \times 9999}{2} = 49,995,000\].
03

Understanding the Selection Sort Comparisons

Selection sort makes exactly \(n(n-1)/2\) comparisons since, in each pass through the list, it looks for the smallest (or largest) element, requiring comparisons with each remaining element. For \(n = 10,000\), the number of comparisons is \(49,995,000\), just like bubble sort.
04

Calculate Comparisons for Selection Sort

Using the same formula as bubble sort, we find:\[\frac{10000 \times 9999}{2} = 49,995,000\].
05

Understanding the Insertion Sort Comparisons

The average case for insertion sort is derived from successively inserting a new element into an already sorted portion of the array. On average, the insertion of each element into the sorted list requires \((n-1)/2\) comparisons, leading to a total of approximately \(n^2/4\) comparisons for random data. For \(n = 10,000\), the estimated number of comparisons is \(10,000^2/4\).
06

Calculate Comparisons for Insertion Sort

Assuming average case behavior for insertion sort, we find:\[\frac{10000^2}{4} = 25,000,000\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bubble Sort
Bubble Sort is a simple and intuitive sorting algorithm. It works by repeatedly swapping adjacent elements if they are in the wrong order. Here's how it proceeds:
  • It compares each pair of adjacent elements, from the start to the end of the list.
  • Swapping happens if the first element is greater than the second.
  • This process continues for every element, for every pass through the entire list.
  • On average, it requires \[\frac{n(n-1)}{2}\] comparisons to sort a list of size \(n\).
Although it is easy to implement, Bubble Sort is not efficient for large datasets. It has a time complexity of \(O(n^2)\), making it quite slow compared to other algorithms for larger numbers of elements. It is mainly used for educational purposes to help understand sorting basics.
Selection Sort
Selection Sort is another straightforward sorting algorithm. Its main idea is to divide the list into two parts: the sorted part on the left and the unsorted part on the right.
  • It starts by finding the smallest (or largest, depending on the order) element in the unsorted part.
  • The smallest element is then swapped with the first element of the unsorted part, moving it to the end of the sorted part.
  • The algorithm repeats this process for each of the following unsorted elements.
Typically, Selection Sort makes \[\frac{n(n-1)}{2}\] comparisons, similar to Bubble Sort. Selection Sort is very predictable in terms of the number of swaps it makes, which is one of its distinct features. Despite this, like Bubble Sort, it also has a time complexity of \(O(n^2)\), making it inefficient on large lists.
Insertion Sort
Insertion Sort is a methodical sorting technique that builds the final sorted array one item at a time. It is particularly useful for small data sets or those that are already partially sorted.
  • It starts with the second element, assuming the first element is already sorted.
  • Each new element is compared with the already sorted part, inserted into the correct position, and the sorted section grows every iteration.
  • On average, inserting a new element requires about \((n-1)/2\) comparisons for each element.
For a random list, the total comparisons tend to approximate \(\frac{n^2}{4}\). It is more efficient than Bubble and Selection sorts for partially sorted lists and has a time complexity of \(O(n^2)\) in the worst case. However, for nearly sorted data, its time complexity can improve to \(O(n)\).
Algorithm Comparisons
Algorithm comparisons help us understand which sorting algorithm might be the best choice under different circumstances. These comparisons often focus on:
  • Time Complexity: All three algorithms discussed, Bubble, Selection, and Insertion Sort, have a worst-case time complexity of \(O(n^2)\). This makes them less suitable for large datasets.
  • Best Usage: Bubble and Selection Sort are mainly educational tools or are used in applications with small datasets or memory constraints. Insertion Sort shines on small or partially sorted data structures.
  • Stability: Bubble Sort and Insertion Sort are stable algorithms, meaning they preserve the order of equal elements. Selection Sort is not stable.
  • Ease of Implementation: All three are relatively easy to implement, which is why they're often introduced early in programming courses.
Despite being \(O(n^2)\), understanding these basic sorts lays the groundwork for more complex sorting algorithms that are highly efficient, like Merge Sort or Quick Sort.

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Most popular questions from this chapter

Consider the following list: 5,12,25,32,38,46,58,62,85,90,97,105,110 Using the binary search as described in this chapter, how many comparisons are required to find whether the following items are in the list? Show the values of first, last, and middle and the number of comparisons after each iteration of the loop. a. 32 b. 20 c. 105 d. 60

Suppose that \(L\) is a sorted list of 4096 elements. What is the maximum number of comparisons made by the binary search algorithm, given in this chapter, to determine if an item is in \(L ?\)

Recall the insertion sort algorithm (contiguous version) as discussed in this chapter. Assume the following list of keys: 30,20,35,27,96,82,56,60,48,75,5,80 Exactly how many key comparisons are executed to sort this list using the insertion sort algorithm?

a. The number of comparisons in the best case of a bubble sort algorithm, as given in this chapter, is \(O\left(n^{2}\right) .\) Show that the following version of the bubble sort algorithm reduces the number of comparisons in the best case of the bubble sort algorithm to \(O(n)\) //list – list to be sorted //elemType – type of the list elements //length – length of the list bool isSorted = false; for (int iteration = 1; (iteration < length) && !isSorted; iteration++) { isSorted = true; //assume that the sublist is sorted for (int index = 0; index < length - iteration; index++) { if (list[index] > list[index + 1]) { elemType temp = list[index]; list[index] = list[index + 1]; list[index + 1] = temp; isSorted = false; } } } b. Using the algorithm given in part (a), find the number of iterations that are needed to sort the following list: 65,14,52,43,75,25,80,90,95

a. Write a version of the sequential search algorithm that can be used to search a sorted list. b. Consider the following list: 8,12,15,27,35,48,65,77,86,94,120 Using a sequential search on ordered lists, which you designed in (a), how many comparisons are required to determine whether the following items are in the list? (Recall that comparisons mean item comparisons, not index comparisons. i. 65 ii. 8 iii. 80 iv. 125

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