Chapter 15: Problem 9
Consider the following recursive function:
void recrun (int x)
\(f\)\\[\begin{array}{l}\text { If }(x>0) \\\\\text { cout }
Short Answer
Expert verified
258, 25, 2; 7; 36, 3; (no output)
Step by step solution
01
Understand the Recursive Function
The function 'recrun' takes an integer 'x' as input. If 'x' is greater than 0, it outputs the value of 'x' if it is not 10 and then recursively calls itself with 'x' divided by 10. If 'x' is not 0 (as an 'else if' condition), it outputs 'x'. If both conditions fail, which means 'x' is 0, the function simply ends.
02
Analyze recrun(258)
Start by evaluating if '258' is greater than 0, which it is. So, the function outputs '258,' and calls itself with 'x/10', which is '25'. For '25', it is also greater than 0, so it outputs '25,' again calls itself with '2'. Finally, the function outputs '2,' and calls recrun(0), which results in stopping the recursion.
03
Analyze recrun(7)
Since '7' is greater than 0, the function outputs '7,' and then calls itself with '7/10', which is 0.7, rounded down to '0', stopping the recursion due to the base case.
04
Analyze recrun(36)
Start with '36', which is greater than 0, so it outputs '36,' before calling itself with '3'. '3' is also greater than 0, thus it outputs '3,' then calls recrun(0), which halts further recursion.
05
Analyze recrun(-85)
The input '-85' is neither greater than 0 nor not 0 in terms of positive integer division by 10's conditions, so the function ends with no output as the conditions of the recursive function are not met.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integer Division
In mathematics and programming, integer division is a type of division in which the result is an integer, discarding any remainder. When this operation is performed, you divide two integers to get the quotient without the fractional part. Let's break it down with the recursion function 'recrun': when it calls itself with x divided by 10, it effectively reduces the number by removing its last digit. This is because each division operation by 10 shifts the decimal point left (in a decimal system) which eliminates the least significant digit.
For example, with recrun(258), dividing by 10 gives:
For example, with recrun(258), dividing by 10 gives:
- 258/10 = 25 (integer division discards the 0.8)
- 25/10 = 2
- 2/10 = 0
Base Case
The base case is an essential part of recursion that defines the condition under which the recursive function stops calling itself. It's like setting a ground rule to prevent endless repetition. Within 'recrun', the base case is reached when 'x' becomes zero.
When analyzing the recursion, the sequence where 'x' is repeatedly divided by 10 eventually leads to 'x = 0'.
This acts as a stop signal for further recursive calls and assures that the recursion concludes. A base case ensures that every recursive function has an end, preventing it from going infinitely and causing a stack overflow.
When analyzing the recursion, the sequence where 'x' is repeatedly divided by 10 eventually leads to 'x = 0'.
This acts as a stop signal for further recursive calls and assures that the recursion concludes. A base case ensures that every recursive function has an end, preventing it from going infinitely and causing a stack overflow.
Recursion Termination
Recursion termination happens when a function doesn’t call itself anymore. This is usually achieved when the base case condition is met. In the function 'recrun', recursion termination is evident when 'x' is zero after successively dividing by 10.
Here’s how it works:
Here’s how it works:
- The function keeps calling itself until 'x' equals zero.
- When 'x' becomes zero, the recursion stops as no further calls are needed.
Conditional Statements
Conditional statements are the backbone of decision-making in programming. They allow a program to choose between different paths based on certain conditions. In 'recrun', several conditional statements are employed to control logic flow.
Key parts to consider:
Key parts to consider:
- The first `if` condition checks if 'x' is greater than 0. If true, it prints 'x' and recurses with `x/10`.
- The `else if` handles the case when 'x' is not zero and serves additional logic, but 'x' being zero naturally terminates recursion.