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Consider the following definition of the class studentType: public studentType: public personType { public: void print(); void calculateGPA(); void setID(long id); void setCourses(const string c[], int noOfC); void setGrades(const char cG[], int noOfC); void getID(); void getCourses(string c[], int noOfC); void getGrades(char cG[], int noOfC); void studentType(string fName = "", string lastName = "", long id, string c[] = NULL, char cG[] = NULL, int noOfC = 0); private: long studentId; string courses[6]; char coursesGrade[6] int noOfCourses; } Rewrite the definition of the class studentType so that the functions print and calculateGPA are pure virtual functions.

Short Answer

Expert verified
Add `= 0` to `print` and `calculateGPA` to make them pure virtual functions.

Step by step solution

01

Understanding Pure Virtual Functions

A pure virtual function in C++ is a function that has no implementation in the base class and is defined by assigning 0 to it in the class definition. It must be overridden by any derived class.
02

Identify Functions to Be Converted

Locate the functions in the class that need to be declared as pure virtual. In this case, the functions `print` and `calculateGPA` need to be modified.
03

Modify Class Declaration

To make `print` and `calculateGPA` pure virtual functions, change their declaration by adding `= 0` at the end. This will create an abstract base class.
04

Rewrite the Class Definition

Edit the class definition to include the changes: ```cpp class studentType: public personType { public: virtual void print() = 0; virtual void calculateGPA() = 0; void setID(long id); void setCourses(const string c[], int noOfC); void setGrades(const char cG[], int noOfC); long getID(); void getCourses(string c[], int noOfC); void getGrades(char cG[], int noOfC); studentType(string fName = "", string lastName = "", long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0); private: long studentId; string courses[6]; char coursesGrade[6]; int noOfCourses; }; ```

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pure Virtual Functions
In C++, a pure virtual function is a function declared in a base class that is assigned to 0. This means the function does not have a body in the base class. When a class contains at least one pure virtual function, it is considered an abstract class. These functions are placeholders meant to be overridden in any derived class.

Pure virtual functions are useful because they enable creating blueprints for other classes. You might compare them to empty boxes, where each derived class fills these empty boxes with its own specific implementation.
  • The syntax for a pure virtual function declaration is: `virtual void functionName() = 0;`.
  • A class having one or more pure virtual functions cannot be instantiated directly.
  • Derived classes must provide implementations for all inherited pure virtual functions, otherwise, they too will become abstract classes.
This promotes a design known as polymorphism, where the same function can act differently depending on which derived class is implementing it.
Inheritance in C++
Inheritance in C++ allows one class (the derived class) to inherit attributes and behavior (methods) from another class (the base class). This is one of the cornerstones of C++ Object-Oriented Programming and facilitates code reusability.
  • The `public studentType : public personType{}` syntax means `studentType` is inheriting from `personType`, taking all its public and protected members.
  • Inheritance establishes a "is-a" relationship; for example, a `studentType` is a `personType`.
  • Beyond just copying over members, inheritance can mean the derived class can also extend or modify the behavior of the base class's methods.
Inheritance enhances encapsulation by allowing derived classes to use and extend functionalities of existing classes. It promotes easier maintenance and scalability of applications.
Abstract Base Class
An abstract base class is a class that is designed to be specifically used as a base class. It is a class that cannot be instantiated on its own and typically contains one or more pure virtual functions. These classes provide an interface for other classes to implement.

Using abstract base classes in C++ encourages a design pattern where specific methods must be implemented by subclasses, enforcing a certain level of consistency and reliability across derived classes.
  • An abstract base class guides the design of derived classes, ensuring they implement required behaviors.
  • These classes emphasize defining a protocol or contract for the derived classes to follow.
  • A design using abstract classes is often more adaptable to changes, as new classes can be introduced without modifying existing ones.
Creating abstract base classes using pure virtual functions ensures that derived classes provide the detailed functionality while the base class provides the interface guide. This makes your architecture robust, future-proof, and efficient.

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Most popular questions from this chapter

What is the output of the following C++ code? int *length; int *width; length = new int; *length = 5; width = length; length = new int; *length = 2 * (*width); cout << *length << " " << *width << " " << (*length) * (*width) << endl;

Suppose that numPtr is a pointer of type int and gpaPtr is a pointer of type double. Further suppose that numPtr = 1050 and gpaPtr = 2000. Also suppose that the size of the memory allocated for an int value is 4 bytes and the size of the memory allocated for a double value is 8 bytes. What are the values of numPtr and gpaPtr after the statements numPtr = numPtr + 2; and gpaPtr = gpaPtr + 3; execute?

Mark the following statements as true or false. a. In C++, pointer is a reserved word. b. In C++, pointer variables are declared using the word pointer. c. The statement delete p; deallocates the variable pointer p. d. The statement delete p; deallocates the dynamic variable that is pointed to by p. e. Given the declaration: int list[10]; int *p; the statement: p = list; is valid in C++. f. Given the declaration: int *p; the statement: p = new int[50]; dynamically allocates an array of 50 components of type int, and p contains the base address of the array. g. The address of operator returns the address and value of its operand. h. If p is a pointer variable, then the statement p = p * 2; is valid in C++.

Consider the following statement: int *num; a. Write the C++ statement that dynamically creates an array of 10 components of type int and num contains the base address of the array. b. Write a C++ code that inputs data into the array num from the standard input device. c. Write a C++ statement that deallocates the memory space of array to which num points.

What is the output of the following C++ code? (Assume that decimal numbers are output with two decimal places.) double *test1 = new double; double *test2 = new double; double *average; average = test1; *test1 = 45.00; *test2 = 90.00; test1 = test2; test2 = new double; *test2 = 86.00; *average = ((*test1) + (*test2)) / 2; cout << *test1 << " " << *test2 << " " << *average << endl;

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