Chapter 5: Problem 11
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 5: Problem 11
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These are the key concepts you need to understand to accurately answer the question.
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Get started for freeWhat is the output of the following program segment? int count = 0; while (count++ < 10) cout << "This loop can repeat statements." << endl;
To learn how nested for loops work, do a walk-through of the following program segments and determine, in each case, the exact output. a. int i, j; for (i = 1; i <= 5; i++) { for (j = 1; j <= 5; j++) cout << setw(3) << i; cout << endl; } b. int i, j; for (i = 1; i <= 5; i++) { for (j = (i + 1); j <= 5; j++) cout << setw(5) << j; cout << endl; } c. int i, j; for (i = 1; i <= 5; i++) { for (j = 1; j <= i; j++) cout << setw(3) << j; cout << endl; } d. const int M = 10; const int N = 10; int i, j; for (i = 1; i <= M; i++) { for (j = 1; j <= N; j++) cout << setw(3) << M * (i - 1) + j; cout << endl; } e. int i, j; for (i = 1; i <= 9; i++) { for (j = 1; j <= (9 - i); j++) cout << " "; for (j = 1; j <= i; j++) cout << setw(1) << j; for (j = (i - 1); j >= 1; j--) cout << setw(1) << j; cout << endl; }
Suppose that the input is 38 35 71 44 -1. What is the output of the following code? Assume all variables are properly declared. sum = 0; cin >> num; for (j = 1; j <= 3; j++) { cin >> num; sum = sum + num; } cout << "Sum = " << sum << endl;
Consider the following for loop: int j, s; s = 0; for (j = 1; j <= 10; j++) s = s + j * (j - 1); In this for loop, identify the loop control variable, the initialization statement, the loop condition, the update statement, and the statement that updates the value of \(\mathbf{s}\)
The do....while loop in the following program is supposed to read some numbers
until it reaches a sentinel (in this case, -1 ). It is supposed to add all of
the numbers except for the sentinel. If the data looks like:
12 5 30 48 -1
the program does not add the numbers correctly. Correct the program so that it
adds
the numbers correctly.
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