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Suppose that sale and bonus are double variables. Write an if....else statement that assigns a value to bonus as follows: If sale is greater than \(\$ 20,000,\) the value assigned to bonus is \(0.10 ;\) If sale is greater than \(\$ 10,000\) and less than or equal to \(\$ 20,000,\) the value assigned to bonus is \(0.05 ;\) otherwise, the value assigned to bonus is 0

Short Answer

Expert verified
The `bonus` is 0.10 if sale > $20,000, 0.05 if $10,000 < sale ≤ $20,000, and 0 otherwise.

Step by step solution

01

Define the Variables

First, ensure that you have two double variables named `sale` and `bonus` declared in your program. These variables will be used to store the sales amount and the calculated bonus, respectively.
02

Check the First Condition

Write an `if` statement to check if `sale` is greater than $20,000. If this condition is true, set `bonus` to 0.10. ``` if (sale > 20000) { bonus = 0.10; } ```
03

Write the Else If Statement

Add an `else if` condition to check if `sale` is greater than $10,000 and less than or equal to $20,000. If this condition is true, set `bonus` to 0.05. ``` else if (sale > 10000 && sale <= 20000) { bonus = 0.05; } ```
04

Complete with Else Statement

Finally, conclude with an `else` statement to handle any other case where `sale` does not meet the above conditions. Set `bonus` to 0 as the default value. ``` else { bonus = 0; } ```
05

Combine Steps into Full If...Else Statement

Bring together the steps into one complete if...else structure: ``` double sale, bonus; if (sale > 20000) { bonus = 0.10; } else if (sale > 10000 && sale <= 20000) { bonus = 0.05; } else { bonus = 0; } ``` Now the if...else statement correctly assigns the value to `bonus` based on the conditions provided.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

C++ programming
C++ is a powerful programming language that is widely used in software development. It is known for its efficiency and its ability to handle complex tasks. C++ allows developers to have a deep control over system resources. This makes it ideal for developing resource-intensive applications, such as operating systems and game engines.

C++ integrates object-oriented, procedural, and generic programming features. This makes it versatile and suitable for different types of projects. Although it can be complex, mastering C++ is incredibly beneficial for any programmer.
  • It has a robust standard library that provides a rich set of capabilities.
  • It supports both high-level and low-level programming tasks.
  • Due to its flexibility, C++ allows for efficient memory management and performance optimization.
This exercise showcases a fundamental aspect of C++ with structures like if...else statements, allowing you to execute code based on specific conditions.
conditional statements
In C++, conditional statements like `if...else` allow programs to make decisions and execute certain blocks of code. Depending on whether a specified condition evaluates to true or false, different paths of execution are chosen.

The basic syntax of an `if...else` statement is straightforward. It starts with the `if` keyword followed by a logical expression in parentheses. If this expression evaluates to true, the code inside the subsequent braces is executed. If it's false, the program moves on to the `else` block, if it's present.
  • `if (condition) { /* code to execute if condition is true */ }`
  • `else { /* code to execute if condition is false */ }`
In the given exercise, the `if...else` statement checks various conditions on the `sale` variable to determine the correct bonus. Each condition is catered to with either an `if`, `else if`, or `else` block, ensuring proper decision making based on logical comparisons.
variable declaration
Variable declaration in C++ is a critical concept that allows you to define variables for storing data values. In C++, you must declare variables before using them. This helps the compiler know what kind of data you want to store.

Variables can hold different data types, such as `int`, `double`, `char`, etc. The choice of data type depends on the kind of value you want the variable to hold. For this exercise, we use the `double` type for more precise decimal values, which is important for financial calculations.
  • `double sale, bonus;` declares two variables named `sale` and `bonus` of type `double`.
  • Using `double` ensures accuracy when dealing with currency and percentages, avoiding errors that could occur with types that have less precision.
Understanding how to declare and properly use variables is essential for effectively solving programming problems. It is the first step towards building a functional program and is foundational in languages like C++.
problem solving in programming
Problem solving in programming involves breaking down a problem into manageable parts and resolving each part using coding principles. It often requires logical thinking and a thorough understanding of programming constructs.

In C++, and particularly with this exercise, problem solving focuses on:
  • Determining what needs to be computed or assigned, such as calculating the `bonus` based on `sale` amounts.
  • Choosing the right constructs, like `if...else` to implement decision-making logic effectively.
  • Organizing the code to ensure it is easy to read and maintain, making it easier to understand the programming flow.
Applying these principles consistently allows programmers to solve varied and complex problems effectively. This involves not just writing code, but thinking critically and structuring solutions that handle all possible situations, as shown in the structured `if...else` logic of the exercise.

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Most popular questions from this chapter

Suppose that score is an int variable. Consider the following if statements: i. if (score = \(=70\) ) cout \(<<\) "Grade is \(\mathrm{C}\). " \(<<\) endl ii. if (score \(=70\) ) cout \(<<\) "Grade is \(\mathrm{C}\). " \(<<\) endl

Suppose that you have the following conditional expression. (Assume that all the variables are properly declared.) \((0<\text { backyard } \& \& \text { backyard }<=5000)\) ? fertilizingCharges \(=40.00\) \(: \text { fertilizingCharges }=40.00+\text { (backyard }-5000) \star 0.01\) a. What is the value of fertilizingCharges if the value of backyard is \(3000 ?\) b. What is the value of fertilizingCharges if the value of backyard is \(5000 ?\) c. What is the value of fertilizingCharges if the value of backyard is \(6500 ?\)

Suppose that score is an int variable. Consider the following if statements: if (score > = 90) ; cout \(<<\) "Discount \(=10\) \&" \(<<\) endl a. What is the output if the value of score is 95 ? Justify your answer. b. What is the output if the value of score is \(85 ?\) Justify your answer.

Mark the following statements as true or false. a. The result of a logical expression cannot be assigned to an int variable. b. In a one-way selection, if a semicolon is placed after the expression in an if statement, the expression in the if statement is always true. c. Every if statement must have a corresponding else. d. The expression in the if statement: if \(\quad(\text { score }=30)\) grade \(=' \mathrm{A}^{\prime}\) always evaluates to true. e. The expression: \((\mathrm{ch}>=\text { 'A ' } \& \& \mathrm{ch}<=\text { ' } \mathrm{Z}\) ') f. Suppose the input is \(5 .\) The output of the code: cin \(>>\) num; if \((\text { num }>5)\) cout \(<<\) num \(;\) num \(=0\); else cout \(<<\) "Num is zero" \(<<\) endl is: Num is zero g. The expression in a switch statement should evaluate to a value of the simple data type. h. The expression ! \((x>0)\) is true only if \(x\) is a negative number. i. \(\quad\) In \(C++,\) both \(!\) and \(!=\) are logical operators. j. The order in which statements execute in a program is called the flow of control.

Suppose that \(x, y,\) and \(z\) are int variables, and \(x=10, y=15,\) and \(z=20\) Determine whether the following expressions evaluate to true or false. a. \(\quad !(x>10)\) b. \(x<=5 | 1 \quad y<15\) \(\begin{array}{llllll}\text { c. } & \langle x & !=5) & \& \& \quad(y \quad !=z)\end{array}\) \(\begin{array}{ll}\text { d. } \quad x>=z & || \quad(x+y>=z)\end{array}\) e. \(\quad(x=z) \quad|| \quad(z-2 \quad !=20)\)

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