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What is the stored in the link field of the last node of a nonempty single linked list?

Short Answer

Expert verified
The link field of the last node points to null.

Step by step solution

01

Understand the Structure

In a singly linked list, each node contains data and a link to the next node. The link field is used to point to the subsequent node in the sequence.
02

Explore the Last Node

Consider the position of the last node in this sequence. The last node is unique because it does not point to any other node, as it comes at the end of the list.
03

Identify the Value in the Link Field

Since the last node doesn't link to any further nodes, the link pointer in the last node generally points to null, indicating the end of the list.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Data Structures
Data structures are fundamental concepts in computer science and programming. They provide efficient ways to store and organize data so that it can easily be accessed and modified. Data structures come in many forms, ranging from linear structures like arrays and lists to more complex structures such as trees and graphs.
Understanding data structures gives programmers the capability to manage data effectively and optimize the performance of software applications.
Different types of data structures serve various purposes. For example:
  • Arrays: Fixed size and perfect for randomly accessing elements.
  • Stacks: Facilitate operations in a Last In First Out (LIFO) manner.
  • Queues: Organize operations in a First In First Out (FIFO) sequence.
  • Linked Lists: Allow dynamic memory allocation through a series of connected nodes.
Mastering data structures is crucial for anyone interested in software development, algorithm optimization, and handling large datasets.
Linked List Nodes
A linked list is a versatile data structure consisting of a sequence of nodes, each containing data and a pointer (or link) to the next node in line. This linkage of nodes creates a chain-like formation that allows for dynamic data management. Compared to arrays, linked lists provide more flexibility with dynamic memory allocation, meaning nodes can be easily added or removed without reallocation or resizing.
In a singly linked list, each node includes two key components:
  • Data Field: This part stores the actual information or value the node represents.
  • Link Field: This part holds the reference to the next node in sequence, forming the chain of nodes.
The simplicity of linked list nodes makes them suitable for low overhead applications, though their sequential access may lead to increased search times compared to direct-access data structures like arrays.
Null Pointer
The concept of a null pointer is significant in many data structures, particularly in linked lists. A pointer is a variable that stores the address of another variable in memory. When a pointer is set to null, it means that it does not reference or point to any valid memory location.
In the context of linked lists, a null pointer plays a crucial role in denoting the termination of the list. Specifically:
  • In a singly linked list, the last node's link field is null.
  • This null value signifies that there are no further nodes to traverse.
  • It serves as a critical check that prevents pointers from accessing invalid memory locations beyond the list.
Understanding the role of a null pointer helps prevent errors related to pointer dereferencing, which can lead to software crashes or memory leaks.
End of List Logic
End of list logic is an important concept to grasp when working with linked lists. It involves understanding how the last element in a list is detected and handled. This knowledge is particularly crucial for operations like traversal, insertion, or deletion where knowing when you've reached the end of the list is vital.
A primary aspect of end-of-list logic in a singly linked list is:
  • The last node's link field points to null, signaling no more nodes follow.
  • The recognition of this null value is a clear indication that the end of the data chain is reached.
Utilizing whether a node's pointer is null enables proper implementation of operations that need to stop at the last node or continue backwards. It serves to maintain list integrity and prevent access beyond the list boundaries, which can cause errors.

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Most popular questions from this chapter

Describe the two typical components of a single linked list node.

Assume that the node of a linked list is in the usual info-link form with the info of type int. The following data, as described in parts (a) to (d), is to be inserted into an initially linked list: \(72,43,8,12 .\) Suppose that head is a pointer of type nodeType. After the linked list is created, head should point to the first node of the list. Declare additional variables as you need them. Write the \(\mathrm{C}++\) code to create the linked list. After the linked list is created, write a code to print the list. What is the output of your code? a. Insert 72 into an empty linked list. b. Insert 43 before 72 c. Insert 8 at the end of the list. d. Insert 12 after 43

Suppose that first is a pointer to a linked list. What is stored in first?

Mark the following statements as true or false. a. In a linked list, the order of the elements is determined by the order in which the nodes were created to store the elements. b. In a linked list, memory allocated for the nodes is sequential. c. \(A\) single linked list can be traversed in either direction. d. In a linked list, nodes are always inserted either at the beginning or the end because a linked link is not a random-access data structure.

Show what is produced by the following \(\mathrm{C}++\) code. Assume the node is in the usual info-link form with the info of type int. (list and ptr are pointers of type nodeType.) 1ist \(=\) new nodeType; \(1 \mathrm{ist} \rightarrow \mathrm{info}=20\) ptr \(=\) new nodeType; \(p t r->i n f 0=28\) \(p t r->1\) ink \(=N U L L\) 1 ist \(->\operatorname{link}=\) ptr ptr \(=\) new nodeType; \(p t r->i n f 0=30\) \(p t r->1\) ink \(=1\) ist list \(=\operatorname{ptr}\) ptr \(=\) new nodeType; \(p t r->i n f 0=42\) \(p t r->1 i n k=1 i s t->1 i n k\) \(1 i s t->1 i n k=p t r\) \(p t r=1\) ist while (ptr != NULL) $$\\{$$ $$\begin{array}{l} \text { cout }<<\operatorname{ptr} \rightarrow \inf _{0}<<\text { end } 1 ; \\\ \operatorname{ptr}=\operatorname{ptr} \rightarrow \operatorname{lin} \mathrm{k} ; \end{array}$$ $$\\}$$

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