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a. Overload the operator + for the class newString to perform string concatenation. For example, if \(s 1\) is "Hello " and \(s 2\) is "there", the statement: \(s 3=s 1+s 2 i\) should assign "Hello there" to s3, in which \(s 1, s 2,\) and \(s 3\) are newString objects. b. Overload the operator \(+=\) for the class newString to perform the following string concatenation. Suppose that \(s 1\) is "Hello " and s2 is "there". Then, the statement: \(s 1+s 2\) should assign "Hello there" to s1, in which s1 and s2 are newString objects.

Short Answer

Expert verified
Overload `+` and `+=` for class `newString` to perform string concatenation.

Step by step solution

01

Define the Class newString

Start by creating a class named `newString` that will hold a string as its data member. This class will enable us to overload operators for string concatenation.
02

Implement the Constructor

Add a constructor to initialize the `newString` object with a given C++ string or an empty string by default. This sets up the necessary infrastructure for managing string data within your class.
03

Overload the Operator +

Define the operator function `operator+` inside the `newString` class. This function should accept a `newString` object as a parameter and return a new `newString` object representing the concatenation of the two strings.
04

Implement the Concatenation Logic for +

Within the `operator+` function, use the existing string from the current object and the string from the passed object to create a new concatenated string. Construct a new `newString` object using this concatenated result and return it.
05

Overload the Operator +=

Define the operator function `operator+=` within the `newString` class. This function should accept a `newString` object as its parameter and modify the existing object by appending the string from the passed object to its current string.
06

Implement the Concatenation Logic for +=

Inside the `operator+=` function, directly append the string from the passed `newString` object to the string of the current object using concatenation.
07

Test the Class and Operator Overloading

Create instances of `newString` and test the overloaded `+` and `+=` operators to ensure they perform string concatenation correctly. Verify the output matches expected values, such as `"Hello there"`.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

String Concatenation
String concatenation is a fundamental concept in programming, allowing you to join two or more strings together to create a single, longer string. In C++, this can be performed using overloaded operators within a class. The process takes place by defining specific logic that dictates how the strings should combine.

In the context of this exercise, we need the `newString` class to handle concatenation via the `+` and `+=` operators. When you concatenate using these operators, you create a seamless integration where strings from different `newString` objects combine without manual string manipulation. By overloading these operators, users can effectively concatenate strings the same way they combine basic data types like numbers.
Class Definition
A class in C++ acts as a blueprint for creating objects. It encapsulates data for the object and methods to manipulate that data. Defining a class involves specifying its data members and the member functions that will operate on these members.

For the `newString` class, the objective is to manage string data and provide functionality for string operations. The data member in this class is typically a `std::string` type that holds the string's value. You would define the `newString` class in such a way that it provides the necessary infrastructure to support operations like concatenation. This would include declaring private data members for encapsulation and public member functions for interfacing and operations.
  • Private Data Member: Holds the actual string value within the class.
  • Public Member Functions: Include constructor(s) and overloaded operator functions.
Constructor Implementation
Constructors are special member functions of a class that initialize the objects of that class. For the `newString` class, a constructor is essential for initializing the string data stored in the object.

The constructor's role is to set up the object's initial state. When creating a `newString` object, the constructor allows you to either pass an initial value or default to an empty string if no argument is provided. This ensures that each object starts with a well-defined state and is ready for operations such as concatenation.

Constructors can be overloaded to handle different types of initialization, providing flexibility in object creation. For example, you might have:
  • Default Constructor: Initializes an empty string.
  • Parameterized Constructor: Takes a `std::string` argument and sets the object's string data accordingly.
Overload Operator Function
Operator overloading in C++ allows you to redefine how operators work with user-defined types, like classes. By overloading operators, you can provide intuitive and seamless interactions between objects.

In the `newString` class, the `+` and `+=` operators are overloaded to allow for string concatenation. Overloading these operators involves defining a member function with `operator` keyword followed by the operator symbol you wish to redefine. This function specifies how the operator should combine objects of the class.

To overload the `+` operator for the `newString` class, you define a function within the class that creates a new `newString` object with the combined string of the current and passed objects. Meanwhile, the `+=` operator alters the current object by appending the passed object's string directly. This distinction is important:
  • `+` Operator: Returns a new object representing the concatenated string.
  • `+=` Operator: Modifies the existing object by appending to its string.
With operator overloading, performing operations on objects becomes as intuitive as dealing with primitive data types, enhancing code readability and usability.

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Most popular questions from this chapter

Find the error(s) in the following code: template //Line 1 class strange //Line 2 { . . . }; strange s1; //Line 3 strange s2; //Line 4

Suppose that the operator \(<<\) is to be overloaded for a user-defined class mystery. Why must \(<<\) be overloaded as a friend function?

Mark the following statements as true or false. a. In \(\mathrm{C}++,\) all operators can be overloaded for user-defined data types. b. In \(\mathrm{C}++,\) operators cannot be redefined for built-in types. c. The function that overloads an operator is called the operator function. d. \(\mathrm{C}++\) allows users to create their own operators. e. The precedence of an operator cannot be changed, but its associativity can be changed. f. Every instance of an overloaded function has the same number of parameters. g. It is not necessary to overload relational operators for classes that have only int member variables. h. The member function of a class template is a function template. i. When writing the definition of a friend function, the keyword friend must appear in the function heading. j. Templates provide the capability for software reuse. k. The function heading of the operator function to overload the preincrement operator \((++)\) and the post-increment operator \((++)\) is the same because both operators have the same symbols.

Write the definition of the function template that swaps the contents of two variables.

Consider the definition of the following function template: template Type funcExp(Type list[], int size) { int j; Type x = list[0]; Type y = list[size - 1]; for (j = 1; j < (size - 1)/2; j++) { if (x < list[j]) x = list[j]; if (y > list[size – 1 – j]) y = list[size – 1 – j]; } return x + y; } Further suppose that you have the following declarations: int list[10] = {5, 3, 2, 10, 4, 19, 45, 13, 61, 11}; string strList[] = {"One", "Hello", "Four", "Three", "How", "Six"}; What is the output of the following statements? a. cout << funExp(list, 10); b. cout << funExp(strList, 6) << endl;

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