Chapter 14: Problem 5
What is the output of the following C++ code? int x; int y; int *p = &x int *q = &y *p = 35; *q = 98; *p = *q; cout << x << " " << y << endl; cout << *p << " " << *q << endl;
Short Answer
Expert verified
The output is:
98 98
98 98
Step by step solution
01
Understand Pointer Initialization
The code begins by declaring two integers, `x` and `y`, and two pointers, `p` and `q`. The pointer `p` is initialized to point to the memory address of `x` and `q` to the address of `y`. This setup allows us to modify the values of `x` and `y` using the pointers.
02
Assign Values Using Pointers
The line `*p = 35;` assigns the value 35 to the location in memory pointed to by `p`, which is `x`. Therefore, `x` becomes 35. The line `*q = 98;` assigns the value 98 to the location pointed to by `q`, which is `y`. Now, `y` is 98.
03
Copy Value from One Memory Location to Another
The operation `*p = *q;` assigns the value at the location pointed to by `q` (which is `y`, holding the value 98) to the location pointed to by `p` (which is `x`). Thus, `x` now becomes 98 instead of 35.
04
Output the Values of `x` and `y`
The first `cout` statement, `cout << x << " " << y << endl;`, displays the current values of `x` and `y`. Since both `x` and `y` are 98, it prints `98 98`.
05
Output the Values Pointed by `p` and `q`
The second `cout`, `cout << *p << " " << *q << endl;`, outputs the values pointed to by `p` and `q`. Since both pointers point to `98`, it outputs `98 98`.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pointer Initialization
In C++, pointers are powerful tools that allow for direct memory access and manipulation. Initialization is the first step when working with pointers. When you declare a pointer, you reserve space in memory to store the memory address it points to. Consider the example from the problem statement:
```cpp int x; int *p = &x; ```
```cpp int x; int *p = &x; ```
- Here, `x` is an integer variable, which holds its own value.
- The pointer `p` is declared and initialized to store the memory address of `x` using the `&` operator.
Memory Address Manipulation
Memory address manipulation involves changing the values stored at specified memory locations. With pointers, this becomes straightforward because pointers can "point" to specific addresses. In our example, once the pointers are initialized:
```cpp *p = 35; *q = 98; ```
```cpp *p = 35; *q = 98; ```
- The statement `*p = 35;` tells the program to store the value 35 at the memory address pointed to by `p`, i.e., the address of `x`. Consequently, `x` is set to 35.
- Similarly, `*q = 98;` directs the storage of 98 at the address pointed by `q`, which is `y`, so `y` becomes 98.
Value Assignment using Pointers
Using pointers to assign values involves utilizing the memory address they point to. This can include copying values between different memory locations. Continuing with the given example, examine the operation:
```cpp *p = *q; ```
```cpp *p = *q; ```
- This line uses pointer `p` to copy the value located at the address pointed to by `q` into the space occupied by `x`.
- Since `q` refers to `y`, which holds the value 98, this operation results in `x` also being set to 98.