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Mark the following statements as true or false. a. The constructor of a derived class can specify a call to the constructor of the base class in the heading of the function definition. b. The constructor of a derived class can specify a call to the constructor of the base class using the name of the class. c. Suppose that \(\mathbf{x}\) and \(\mathbf{y}\) are classes, one of the member variables of \(\mathbf{x}\) is an object of type \(\mathbf{y}\), and both classes have constructors. The constructor of \(\mathbf{x}\) specifies a call to the constructor of \(y\) by using the object name of type \(y\)

Short Answer

Expert verified
a. True, b. False, c. False.

Step by step solution

01

Analyze Statement a

Statement: "The constructor of a derived class can specify a call to the constructor of the base class in the heading of the function definition." This statement refers to how initializations occur in derived class constructors. In C++, a derived class's constructor can indeed specify a call to a base class constructor in the member initializer list, which is part of the constructor's heading. Thus, statement a is **True**.
02

Analyze Statement b

Statement: "The constructor of a derived class can specify a call to the constructor of the base class using the name of the class." This statement seems to suggest that the base class constructor is called using the class name itself, similar to how member functions are called. However, in C++, the name of the base class is not directly used during initialization in a derived class's constructor; instead, the member initializer list is used. Thus, statement b is **False**.
03

Analyze Statement c

Statement: "Suppose that \(\mathbf{x}\) and \(\mathbf{y}\) are classes, one of the member variables of \(\mathbf{x}\) is an object of type \(\mathbf{y}\), and both classes have constructors. The constructor of \(\mathbf{x}\) specifies a call to the constructor of \(y\) by using the object name of type \(y\)." In C++, when a class \(\mathbf{x}\) has a member object of another class \(\mathbf{y}\), the constructor of \(\mathbf{x}\) needs to explicitly call the constructor of \(\mathbf{y}\) in the initialization list, not by the object name. Thus, statement c is **False**.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derived Class
In C++, a derived class is a class that inherits properties and behaviors from another class, known as the base class. This concept allows for reusable code and organized class hierarchies, making object-oriented programming powerful and efficient. Derived classes can add new features or modify existing ones from the base class. They can be used to create complex structures that still rely on shared functionalities.
When creating a derived class, you often inherit traits of a base class to extend functionality without rewriting existing code. Derived classes can change or extend the behavior and properties of base classes while still using the structure of the base class.
  • The syntax for creating a derived class involves specifying the base class during the class definition.
  • Derived classes can access public and protected members of the base class.
  • Private members of a base class are inaccessible directly through the derived class.
Base Class
A base class in C++ serves as the foundation from which other classes are developed. This class can encapsulate common properties and methods that other classes can use as a template. The base class simplifies code management by grouping shared capabilities that derived classes can leverage.
The base class contains definitions for data and functionalities shared among derived classes, maintaining consistency across derived implementations. It ensures that similar objects can operate on identical methods and have consistent attributes.
  • Base classes help in defining the common interface and ensures a structured object-oriented design.
  • They contain all the functionalities that should be available to derived classes.
  • The base class can also provide default behaviors that can be overridden by derived classes.
Object Initialization
Object initialization in C++ is how resources and values are assigned to newly created objects. This is crucial in constructing objects correctly, especially when working with class hierarchies that involve base and derived classes.
When a derived class is instantiated, it typically calls the constructor of its base class first to ensure that all inherited attributes are correctly initialized. This process is done through a mechanism known as **member initializer lists**. The C++ constructor for the derived class includes a list of initializations for the base class, ensuring that the object is set up correctly.
  • Member initializer lists are used in constructors to initialize class data members and base classes.
  • If a class contains objects of other types as members, their corresponding constructors must be called as part of this process.
  • C++ allows constructors to delegate to other constructors, ensuring proper order and methodology during object construction.

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Most popular questions from this chapter

Consider the following class definition: class circle class cylinder: public circle { { public: public: void print() const; void print() const; void setRadius(double); void setHeight(double); double getRadius(); double getHeight(); double area(); double volume(); circle(); double area(); circle(double); cylinder(); cylinder(double, double); private: private: double radius; double height; }; }; Suppose that you have the declaration: cylinder newCylinder;

Assume the declaration of Exercise \(12 .\) Suppose that class third is derived from class first using the statement: class third: protected first Determine which members of class first are private, protected, and public in class third.

Consider the following class definitions: class baseClass { public: void print() const; int getX() const; baseClass(int a = 0); protected: int x; }; class derivedClass: public baseClass { public: void print() const; int getResult() const; derivedClass(int a = 0, int b = 0); private: int y; }; Suppose the definitions of the member functions of these classes are as follows: void baseClass::print() const { cout << "In base: x = " << x << endl; } baseClass::baseClass(int a) { x = a; } int baseClass::getX() const { return x; } void derivedClass::print() const { cout << "In derived: x = " << x << ", y = " << y << "; x + y = " << x + y << endl; } int derivedClass::getResult() const { return x + y; } derivedClass::derivedClass(int a, int b) : baseClass(a) { y = b; } What is the output of the following function main? int main() { baseClass baseObject(7); derivedClass derivedObject(3, 8); baseObject.print(); derivedObject.print(); cout << "****" << baseObject.getX() << endl; cout << "" << derivedObject.getResult() << endl; return 0; }

Consider the following statements: class dog: public animal { ... }; In this declaration, which class is the base class, and which class is the derived class?

Consider the following statements: class yClass class xClass: public yClass { { public: public: void one(); void one(); void two(int, int); xClass(); yClass(); private: private: int z; int a; int b; }; }; Suppose the following statements are in a user program (client code): yClass y; xClass x; a. The private members of yClass are public members of xClass. True or False? b. Mark the following statements as valid or invalid. If a statement is invalid, explain why. i. void yClass::one() { cout << a + b << endl; } ii. y.a = 15; x.b = 30; iii. void xClass::one() { a = 10; b = 15; z = 30; cout << a + b + z << endl; } iv. cout << y.a << " " << y.b << " " << x.z << endl;

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