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Write four different \(C++\) statements that each add 1 to integer variable \(x.\)

Short Answer

Expert verified
x++; or ++x; or x += 1; or x = x + 1;

Step by step solution

01

Statement Using Postfix Increment Operator

Use the postfix increment operator to increase the value of the variable by 1. In code: x++;. This statement adds 1 to x and then yields the original value of x.
02

Statement Using Prefix Increment Operator

Use the prefix increment operator to increase the value of the variable by 1 before its value is used in expressions. In code: ++x;. This statement increases x by 1 and immediately yields the new value.
03

Statement Using Addition Assignment Operator

Use the addition assignment operator to add a value to the variable. In code: x += 1;. This adds 1 directly to the current value of x.
04

Statement Using Basic Addition

Perform a basic addition to add 1 to the variable and update its value. In code: x = x + 1;. This takes the current value of x, adds 1, and then assigns the result back to x.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Postfix Increment Operator
Understanding the postfix increment operator is essential when learning C++. This operator, represented by two plus signs following a variable, as in x++, is used to increase the value of the variable by 1 after its current value has been used. Imagine you're counting apples in a basket, and after counting each apple, you mark it; this is similar to how the postfix operator works—you use the apple (variable), then mark it (increment).

Here's how you might see it in action:
  • int x = 5;
  • int y = x++;
  • // Now, x is 6 and y is 5

The key point to remember is that the original value of x is used in any expressions or assignments before x itself is incremented.
Prefix Increment Operator
The prefix increment operator is another way to add 1 to a variable in C++. Unlike the postfix version, the prefix increment operator, denoted with two plus signs before a variable, as in ++x, increments the variable's value before it's used anywhere else. It's like preparing all of your apples by washing them before putting them into the basket.

Consider this example:
  • int x = 5;
  • int y = ++x;
  • // x is now 6, and y is also 6

This behavior has implications when the increment is part of a larger expression. It ensures that you're working with the updated value right away.
Addition Assignment Operator
If you're looking to increase a variable's value directly and concisely, the addition assignment operator += is your tool of choice. This operator combines addition and assignment in one sleek motion. For example, the statement x += 1 essentially tells the computer, 'Take the current value of x, add 1 to it, and then make this new sum the value of x.'

It's like saying, 'I have these many apples, I'm getting one more, and that's my new total.' This operator simplifies code and eliminates the need to write the variable out twice, as compared to x = x + 1.
Basic Addition in C++
The most straightforward way to increase a value in C++ is with basic addition. To add 1 to a variable, you simply take its current value, add 1, and then update the variable with the new value using the equals operator. In code, this looks like x = x + 1.

This is equivalent to a one-step process where you hold a certain number of apples, say 'I have one more,' and count them together to find your new total. While this approach is clear and intuitive, especially for those new to programming, it's often substituted with the more concise increment operators or the addition assignment operator in practice.

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Most popular questions from this chapter

Write C++ statements to accomplish each of the following: a) In one statement, assign the sum of the current value of \(x\) and \(y\) to \(z\) and postincrement the value of \(x\) b) Determine whether the value of the variable count is greater than \(10 .\) If it is, print "Count is greater than \(10 . "\) c) Predecrement the variable \(x\) by \(1,\) then subtract it from the variable total. d) Calculate the remainder after \(q\) is divided by divisor and assign the result to q. Write this statement two different ways.

(Printing the Decimal Equivalent of a Binary Number) Input an integer containing only 0 s and \(1 s\) (i.e., a "binary" integer) and print its decimal equivalent. Use the modulus and division operators to pick off the "binary" number's digits one at a time from right to left. Much as in the decimal number system, where the rightmost digit has a positional value of \(1,\) the next digit left has a positional value of \(10,\) then \(100,\) then \(1000,\) and so on, in the binary number system the rightmost digit has a positional value of \(1,\) the next digit left has a positional value of \(2,\) then \(4,\) then \(8,\) and so on. Thus the decimal number 234 can be interpreted as \(2^{*} 100+3^{*} 10+4^{*} 1 .\) The decimal equivalent of binary 1101 is \(1^{*} 1+0^{*} 2+1^{*} 4+1^{*} 8\) or \(1+0+4+8\), or \(13 .[\) Note: To learn more about binary numbers, refer to Appendix D.]

Write single \(\mathrm{C}_{++}\) statements or portions of statements that do the following: a) Input integer variable \(x\) with \(\operatorname{cin}\) and \(>>\) b) Input integer variable \(y\) with \(\operatorname{cin}\) and \(>>\) c) Set integer variable i to 1 d) Set integer variable power to 1 e) Multiply variable power by \(x\) and assign the result to power. \(f\) ) Preincrement variable i by 1 g) Determine whether i is less than or equal to y. h) Output integer variable power with cout and \(<<\)

(Factorial) The factorial of a nonnegative integer \(n\) is written \(n !\) (pronounced "n factorial") and is defined as follows: \(n !=n \cdot(n-1) \cdot(n-2) \cdot \ldots \cdot 1 \quad(\text { for values of } n \text { greater than } 1)\) and \\[ n !=1 \quad(\text { for } n=0 \text { or } n=1) \\] For example, \(5 !=5 \cdot 4 \cdot 3 \cdot 2 \cdot 1,\) which is \(120 .\) Use while statements in each of the following: a) Write a program that reads a nonnegative integer and computes and prints its factorial. b) Write a program that estimates the value of the mathematical constant \(e\) by using the formula: \\[ e=1+\frac{1}{1 !}+\frac{1}{2 !}+\frac{1}{3 !}+\ldots \\] Prompt the user for the desired accuracy of \(e\) (i.e., the number of terms in the summation) c) Write a program that computes the value of \(e^{x}\) by using the formula \\[ e^{x}=1+\frac{x}{1 !}+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\ldots \\] Prompt the user for the desired accuracy of \(e\) (i.e., the number of terms in the summation).

\(4.26 \quad\) forward. For example, each of the following five-digit integers is a palindrome: 12321,55555 45554 and \(11611 .\) Write a program that reads in a five-digit integer and determines whether it's a palindrome. [Hint: Use the division and modulus operators to separate the number into its individual digits.

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