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Fill in the blanks for each of the following: a. Keyword _____________ specifies that a namespace or namespace member is being used. b. Operator _____________ is the operator keyword for logical OR. c. Storage specifier_____________ allows a member of a const object to be modified. d. The _____________ qualifier specifies that an object can be modified by other programs. e. Precede a member with its _____________ name and the scope resolution operator _____________ if the possibility exists of a scoping conflict. f. The body of a namespace is delimited by _____________. g. For a const object with no _____________ data members, operator _____________ must be used every time a member is to be modified.

Short Answer

Expert verified
a. using b. || c. mutable d. volatile e. class, :: f. {} g. mutable, const_cast<>

Step by step solution

01

Analyze the First Blank

The keyword used to specify that a namespace or namespace member is being used is 'using.' Therefore, the answer is 'using.' Fill in: a. Keyword 'using' specifies that a namespace or namespace member is being used.
02

Analyze the Second Blank

The operator keyword for logical OR is '||.' Therefore, the answer is '||.' Fill in: b. Operator '||' is the operator keyword for logical OR.
03

Determine the Storage Specifier

For a member of a const object to be modified, the 'mutable' storage class specifier is used. Therefore, the answer is 'mutable.' Fill in: c. Storage specifier 'mutable' allows a member of a const object to be modified.
04

Examine the Qualifier for Modification by Other Programs

The 'volatile' qualifier is used to indicate that an object can be modified by other programs or hardware. Fill in: d. The 'volatile' qualifier specifies that an object can be modified by other programs.
05

Resolve Scoping Conflict

When there is a possibility of a scoping conflict, precede a member with its 'class' name and the scope resolution operator '::.' Fill in: e. Precede a member with its 'class' name and the scope resolution operator '::' if the possibility exists of a scoping conflict.
06

Delimit the Body of a Namespace

The body of a namespace is delimited by braces '{}.' Fill in: f. The body of a namespace is delimited by '{' and '}'.
07

Use Operator for Const Object with Mutable Members

When a const object has no 'mutable' data members, operator 'const_cast<>' is used every time a member is to be modified. Fill in: g. For a const object with no 'mutable' data members, operator 'const_cast<>' must be used every time a member is to be modified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Namespace Usage
C++ uses namespaces to organize code into logical groups and avoid name clashes. A namespace is essentially a container for identifiers like classes, objects, and variables. To specify that we're using a namespace or a member of it, we use the keyword `using`. For example, if you want to use the standard library's `cout` object without prefixing it every time with `std::`, you could write `using namespace std;` at the beginning of your program. This helps avoid repetitive and lengthy code when accessing elements of the standard library.

Namespaces are declared with the keyword `namespace` followed by the namespace name and a pair of curly braces `{}` enclosing its declarations. For instance:

  • namespace myNamespace {
  • int myVar;
  • }
Using namespaces is a crucial part of C++ programming, especially in larger projects where keeping elements organized and preventing naming conflicts is essential.
Logical Operators
Logical operators are crucial in controlling the flow of a C++ program. They help in decision-making by evaluating expressions into true or false. The main logical operators in C++ are:

  • Logical AND: `&&`
  • Logical OR: `||`
  • Logical NOT: `!`
The logical OR operator, represented by `||`, returns true if at least one of the operands is true. For example, if you have two conditions and want your program to proceed if either of them is true, you use `||`. Here is an example:

`if (x > 5 || y < 10) { /* code to execute */ }`

This means if `x` is greater than 5 or `y` is less than 10, the block of code inside the statement will execute. Logical operators enable a program to make complex decisions and execute different code paths based on varying conditions.
Storage Specifier
Storage specifiers in C++ define the scope (visibility) and lifetime of variables or functions. They include specifiers like `static`, `extern`, `register`, and `mutable`. The `mutable` storage specifier is unique because it allows an attribute of a const object to be modified. This is particularly useful when you have a class with a member function marked as `const` but still require to alter some internal data members.

Consider a class with a data member that needs to update even in constant member functions. Here’s an example:

  • class Example {
  • mutable int changeable;
  • public:
  • void modify() const { changeable = 10; }
  • }
This code allows `changeable` to be modified even in a const function, which demonstrates the power of `mutable`.
Scope Resolution
The scope resolution operator `::` in C++ is used to define or access variables, functions, and classes within a specific namespace or class. It is especially useful when you have naming conflicts where the same name is used in multiple scopes or classes.

For instance, if a global variable and a local variable have the same name, the `::` operator helps in accessing the global variable:

`::globalVar = 10;`

It's also used when defining functions outside of a class definition and for accessing static or nested class members. Here's an example:

  • class MyClass {
  • public:
  • static int staticVar;
  • };
  • int MyClass::staticVar = 0;
In this scenario, `MyClass::staticVar` denotes that `staticVar` belongs to `MyClass`. Understanding the scope resolution operator is vital for managing large codebases and handling complexities in class definitions and namespaces.

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