Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(Bucket Sort) A bucket sort begins with a one-dimensional vector of positive integers to be sorted and a two-dimensional vector of integers with rows indexed from 0 to 9 and columns indexed from 0 to \(n 1\), where \(n\) is the number of values to be sorted. Each row of the two-dimensional vector is referred to as a bucket. Write a class named Bucketsort containing a function called sort that operates as follows: a. Place each value of the one-dimensional vector into a row of the bucket vector, based on the value's "ones" (rightmost) digit. For example, 97 is placed in row 7,3 is placed in row 3 and 100 is placed in row 0. This procedure is called a distribution pass. b. Loop through the bucket vector row by row, and copy the values back to the original vector. This procedure is called a gathering pass. The new order of the preceding values in the one-dimensional vector is 100,3 and 97 c. Repeat this process for each subsequent digit position (tens, hundreds, thousands, etc.). On the second (tens digit) pass, 100 is placed in row 0,3 is placed in row 0 (because 3 has no tens digit) and 97 is placed in row 9. After the gathering pass, the order of the values in the one-dimensional vector is 100,3 and \(97 .\) On the third (hundreds digit) pass, 100 is placed in row 1,3 is placed in row 0 and 97 is placed in row 0 (after the 3 ). After this last gathering pass, the original vector is in sorted order. Note that the two-dimensional vector of buckets is 10 times the length of the integer vector being sorted. This sorting technique provides better performance than a bubble sort, but requires much more memorythe bubble sort requires space for only one additional element of data. This comparison is an example of the spacetime trade-off: The bucket sort uses more memory than the bubble sort, but performs better. This version of the bucket sort requires copying all the data back to the original vector on each pass. Another possibility is to create a second two-dimensional bucket vector and repeatedly swap the data between the two bucket vectors.

Short Answer

Expert verified
Implement a distribution and gathering pass for each digit position in the numbers to perform bucket sort.

Step by step solution

01

Initializing Data

Start by identifying the one-dimensional array of positive integers that needs to be sorted. Also, prepare a two-dimensional array (a vector of buckets) with 10 rows, one for each digit (0-9). The number of columns should be equal to the length of the input array since, in the worst case, all numbers could end up in the same bucket.
02

Distribution Pass for Ones Digit

For each number in the input array, determine the value of its ones (rightmost) digit. Place each number into the corresponding row (bucket) in the two-dimensional array based on this digit. For example, the number 97 goes into row 7, and the number 3 goes into row 3.
03

Gathering Pass

Once all numbers are placed in their respective buckets based on the ones digit, gather all numbers from the buckets and copy them back to the original array starting from the lowest index. This will result in a partially sorted array based on the ones digit.
04

Repeat Process for Tens Digit

Perform the same distribution and gathering process for the tens digit. Determine each number’s tens digit and place it into the appropriate row in the bucket array. After placing all numbers by their tens digits, gather them back into the original array.
05

Repeat Process for Further Digits

Continue the distribution and gathering process for higher-place digits (hundreds, thousands, etc.) until all digits have been processed. For each pass, extract and sort numbers by the respective digit value and copy them back to the original array.
06

Conclusion of Sorting

After completing the passes for each digit in the largest number, the sorting of the initial array is complete. The output will be the sorted array, now in ascending order, based on all the digit places.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sorting Algorithms
Sorting algorithms are methods used to arrange data in a specific order, most commonly in ascending or descending order. They are fundamental in computer science as they optimize the process of accessing or arranging data in a meaningful way.
There are several types of sorting algorithms, each with its own mechanisms and efficiencies. For instance, Quick Sort and Merge Sort are known for their speed, but they involve more complex operations compared to simpler algorithms such as Bubble Sort or Selection Sort.
Bucket Sort, the algorithm of focus here, is distinctive because it distributes elements into different "buckets" or sections based on their values for a particular digit. This makes Bucket Sort particularly efficient with uniformly distributed data over a fixed range. Essentially, the concept of Bucket Sort follows a distributive approach, grouping values before sorting them within each group and then combining them.
In summary, sorting algorithms serve as essential tools for organizing data, and choosing the right one depends on the specific data characteristics and performance requirements.
Time Complexity
Understanding time complexity is key to evaluating how efficient an algorithm is as it scales with larger input sizes. It helps us predict how an algorithm's runtime increases as the size of the input data grows.
Bucket Sort has an average time complexity of \( O(n + k) \), where \( n \) is the number of elements in the array and \( k \) is the number of buckets. This assumes that the input distribution is uniform and that the time to sort within a bucket is sufficiently small.
However, if data is not perfectly distributed or if each bucket contains many elements, additional sorting within the buckets can degrade overall performance. This could push Bucket Sort towards a worse-case scenario resembling \( O(n^2) \).
Thus, while Bucket Sort can perform efficiently under optimal conditions, it's important to consider the nature of the dataset when evaluating this algorithm's time complexity.
Space Complexity
Space complexity refers to the amount of working storage an algorithm needs. For sorting algorithms, understanding space complexity is essential for assessing their practicality, especially when dealing with large datasets.
Bucket Sort is known to have a relatively high space complexity because it requires additional memory storage in the form of buckets. Specifically, it uses \( O(n + k) \) space, where \( n \) is the number of elements and \( k \) is the number of buckets.
This space requirement implies a need for larger memory allocation compared to more space-efficient algorithms such as Insertion Sort or Bubble Sort, which generally use \( O(1) \) auxiliary space.
Despite its good average performance, the high space complexity of Bucket Sort can be a drawback for applications with memory constraints, underscoring the trade-off between speed and space efficiency.
Radix Sort
Radix Sort is a fascinating sorting algorithm that's often compared to Bucket Sort. Like Bucket Sort, Radix Sort handles numbers through distribution based on their digit places, starting from the least significant digit to the most significant digit.
One of the key distinctions is that Radix Sort operates efficiently with a fixed-sized base (usually ten for decimal digits), and it typically utilizes a stable sorting algorithm like Counting Sort for internally sorting the values at each level of digit significance.
The efficiency of Radix Sort lies in its ability to process numbers in multiple passes, sorting one digit at a time without comparing total values directly. It works particularly well on integers and can be highly efficient when the maximum digit length is known, making it a good choice for datasets with known limits.
With a time complexity of \( O(nk) \), where \( n \) is the number of keys, and \( k \) is the maximum number of digits in any key, Radix Sort can outperform other sorts under certain conditions, though it does require additional space due to the auxiliary sorting process.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fill in the blanks in each of the following statements: a. A selection sort application would take approximately ________ times as long to run on a 128-element vector as on a 32-element vector. b. The efficiency of merge sort is ________.

(Quicksort) The recursive sorting technique called quicksort uses the following basic algorithm for a one-dimensional vector of values: a. Partitioning Step : Take the first element of the unsorted vector and determine its final location in the sorted vector (i.e., all values to the left of the element in the vector are less than the element, and all values to the right of the element in the vector are greater than the elementwe show how to do this below). We now have one element in its proper location and two unsorted subvectors. b. Recursion Step : Perform Step 1 on each unsorted subvector. Each time Step 1 is performed on a subvector, another element is placed in its final location of the sorted vector, and two unsorted subvectors are created. When a subvector consists of one element, that element is in its final location (because a one-element vector is already sorted). The basic algorithm seems simple enough, but how do we determine the final position of the first element of each subvector? As an example, consider the following set of values (the element in bold is the partitioning elementit will be placed in its final location in the sorted vector): $$\begin{array}{llllllllll} 37 & 2 & 6 & 4 & 89 & 8 & 10 & 12 & 68 & 45 \end{array}$$

In the text, we say that after the merge sort splits the vector into two subvectors, it then sorts these two subvectors and merges them. Why might someone be puzzled by our statement that "it then sorts these two subvectors"?

(Bubble Sort) Implement bubble sortanother simple yet inefficient sorting technique. It is called bubble sort or sinking sort because smaller values gradually "bubble" their way to the top of the vector (i.e., toward the first element) like air bubbles rising in water, while the larger values sink to the bottom (end) of the vector. The technique uses nested loops to make several passes through the vector. Each pass compares successive pairs of elements. If a pair is in increasing order (or the values are equal), the bubble sort leaves the values as they are. If a pair is in decreasing order, the bubble sort swaps their values in the vector. The first pass compares the first two elements of the vector and swaps them if necessary. It then compares the second and third elements in the vector. The end of this pass compares the last two elements in the vector and swaps them if necessary. After one pass, the largest element will be in the last index. After two passes, the largest two elements will be in the last two indices. Explain why bubble sort is an \(O\left(n^{2}\right)\) algorithm.

What key aspect of both the binary search and the merge sort accounts for the logarithmic portion of their respective Big Os?

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free