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(Quicksort) The recursive sorting technique called quicksort uses the following basic algorithm for a one-dimensional vector of values: a. Partitioning Step : Take the first element of the unsorted vector and determine its final location in the sorted vector (i.e., all values to the left of the element in the vector are less than the element, and all values to the right of the element in the vector are greater than the elementwe show how to do this below). We now have one element in its proper location and two unsorted subvectors. b. Recursion Step : Perform Step 1 on each unsorted subvector. Each time Step 1 is performed on a subvector, another element is placed in its final location of the sorted vector, and two unsorted subvectors are created. When a subvector consists of one element, that element is in its final location (because a one-element vector is already sorted). The basic algorithm seems simple enough, but how do we determine the final position of the first element of each subvector? As an example, consider the following set of values (the element in bold is the partitioning elementit will be placed in its final location in the sorted vector): $$\begin{array}{llllllllll} 37 & 2 & 6 & 4 & 89 & 8 & 10 & 12 & 68 & 45 \end{array}$$

Short Answer

Expert verified
First, choose the element as the pivot, rearrange around it, then recursively sort the sub-lists.

Step by step solution

01

Choose the Pivot

For the partitioning step, we take the first element as the pivot. In this case, the pivot is 37.
02

Rearrange Elements

Rearrange the vector such that all elements less than 37 are moved to its left, and all elements greater or equal to 37 are moved to its right. The temporary rearrangement looks like \[\begin{array}{llllllllll} 2 & 6 & 4 & 8 & 10 & 12 & 37 & 89 & 68 & 45 \end{array}\].
03

Place Pivot in Final Position

Place the pivot (37) in its correct final position within the rearranged vector. At this point, 37 is placed between the two groups: \[\begin{array}{llllllllll} 2 & 6 & 4 & 8 & 10 & 12 & 37 & 89 & 68 & 45 \end{array}\].
04

Partition Left Subvector

Take the left subvector \([2, 6, 4, 8, 10, 12]\) and perform the partition step again with 2 as the new pivot. After rearranging, the vector becomes \[\begin{array}{llllll} 2 & 6 & 4 & 8 & 10 & 12 \end{array}\], since all elements are already greater than 2.
05

Partition Right Subvector

Now focus on the right subvector \([89, 68, 45]\). Choose 89 as the pivot. Rearrange to make sure elements less than 89 are to its left: \[\begin{array}{lll} 68 & 45 & 89 \end{array}\].
06

Continue Recursion on Sublists

For the left of the pivot 2, nothing needs to be done since it's a single element. Therefore, proceed to sort the sublists \([6, 4, 8, 10, 12]\) and \([68, 45]\) recursively using the previous steps.
07

Final Checks and Completion

Repeat Steps 4 to 6 until each element is checked and placed in its final position. Sub-vectors break down further until each element stands alone, signalling the end of the sort.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recursive Sorting
Recursive sorting is a fundamental concept at the heart of the quicksort algorithm. What makes quicksort powerful is its ability to break a larger problem into smaller, more manageable parts through the process of recursion. In quicksort, recursion begins with the entire unsorted vector. The vector is divided until it cannot be divided further. This recursive approach simplifies complex sorting tasks.

1. **Division into Subvectors**: Initially, the vector is partitioned into two subvectors, usually around a pivot element (more about this in the next section).
2. **Recursive Calls**: The algorithm then calls itself to sort each of these subvectors. As the recursion proceeds, each subvector divides further into smaller parts.
3. **Base Case**: The recursion stops when a subvector has only one element. Here, quicksort recognizes it as sorted.

This procedure efficiently organizes data, starting from smaller tasks and combining them to solve the larger problem.
Pivot Selection
Pivot selection is a crucial step in the quicksort algorithm. The pivot is the central element around which the vector is partitioned. The choice of pivot can significantly influence the efficiency of the sort.

Here are some key points about pivot selection:

  • **Simple Selection**: In the basic version of quicksort, the first element of the vector is chosen as the pivot, as demonstrated in the exercise.
  • **Alternative Choices**: More advanced techniques involve choosing a random element, the last element, or even the median of the vector to reduce the chances of poor performance.
  • **Impact on Performance**: An ideal pivot evenly splits the vector, leading to balanced recursion and optimized performance.

The selection must handle all eventualities, ensuring that the sorting continues effectively, minimizing time complexity.
Partitioning Algorithm
The partitioning algorithm in quicksort is where the action happens. It's the step where the selected pivot is used to divide the vector into two parts.

Here's how it works:

  • **Rearrangement**: The algorithm rearranges elements such that those less than the pivot move to its left, and those greater move to its right, creating two new subvectors.
  • **Placement**: Once rearranged, the pivot is placed between these two groups. This step ensures that it's in the correct final position.
  • **Subvector Creation**: The vector is now divided into two unsorted subvectors to be processed in further recursive steps.

This partitioning efficiently isolates elements around the pivot, ensuring continuous progress of the sorting process.
Vector Sorting
Vector sorting with quicksort involves organizing a collection of numbers or elements stored in a one-dimensional vector. This method uses the principles of recursive sorting, pivot selection, and partitioning to achieve a fully sorted vector.

Here's a quick breakdown:

  • **Initial Arrangement**: Begin with a one-dimensional vector, unsorted.
  • **Recursive Sorting Methodology**: Use the recursive quicksort technique to continuously break down the vector into smaller parts.
  • **Arrange and Finalize**: Through continuous partitioning and recursive calls, each element reaches its final sorted position.
    The vector sorting completes when all elements are correctly organized, resulting in a sorted sequence from smallest to largest.

This systematic approach ensures that the sorting is done efficiently, making quicksort a popular choice for sorting data structures.

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Most popular questions from this chapter

(Bubble Sort) Implement bubble sortanother simple yet inefficient sorting technique. It is called bubble sort or sinking sort because smaller values gradually "bubble" their way to the top of the vector (i.e., toward the first element) like air bubbles rising in water, while the larger values sink to the bottom (end) of the vector. The technique uses nested loops to make several passes through the vector. Each pass compares successive pairs of elements. If a pair is in increasing order (or the values are equal), the bubble sort leaves the values as they are. If a pair is in decreasing order, the bubble sort swaps their values in the vector. The first pass compares the first two elements of the vector and swaps them if necessary. It then compares the second and third elements in the vector. The end of this pass compares the last two elements in the vector and swaps them if necessary. After one pass, the largest element will be in the last index. After two passes, the largest two elements will be in the last two indices. Explain why bubble sort is an \(O\left(n^{2}\right)\) algorithm.

(Bucket Sort) A bucket sort begins with a one-dimensional vector of positive integers to be sorted and a two-dimensional vector of integers with rows indexed from 0 to 9 and columns indexed from 0 to \(n 1\), where \(n\) is the number of values to be sorted. Each row of the two-dimensional vector is referred to as a bucket. Write a class named Bucketsort containing a function called sort that operates as follows: a. Place each value of the one-dimensional vector into a row of the bucket vector, based on the value's "ones" (rightmost) digit. For example, 97 is placed in row 7,3 is placed in row 3 and 100 is placed in row 0. This procedure is called a distribution pass. b. Loop through the bucket vector row by row, and copy the values back to the original vector. This procedure is called a gathering pass. The new order of the preceding values in the one-dimensional vector is 100,3 and 97 c. Repeat this process for each subsequent digit position (tens, hundreds, thousands, etc.). On the second (tens digit) pass, 100 is placed in row 0,3 is placed in row 0 (because 3 has no tens digit) and 97 is placed in row 9. After the gathering pass, the order of the values in the one-dimensional vector is 100,3 and \(97 .\) On the third (hundreds digit) pass, 100 is placed in row 1,3 is placed in row 0 and 97 is placed in row 0 (after the 3 ). After this last gathering pass, the original vector is in sorted order. Note that the two-dimensional vector of buckets is 10 times the length of the integer vector being sorted. This sorting technique provides better performance than a bubble sort, but requires much more memorythe bubble sort requires space for only one additional element of data. This comparison is an example of the spacetime trade-off: The bucket sort uses more memory than the bubble sort, but performs better. This version of the bucket sort requires copying all the data back to the original vector on each pass. Another possibility is to create a second two-dimensional bucket vector and repeatedly swap the data between the two bucket vectors.

In the text, we say that after the merge sort splits the vector into two subvectors, it then sorts these two subvectors and merges them. Why might someone be puzzled by our statement that "it then sorts these two subvectors"?

What key aspect of both the binary search and the merge sort accounts for the logarithmic portion of their respective Big Os?

Fill in the blanks in each of the following statements: a. A selection sort application would take approximately ________ times as long to run on a 128-element vector as on a 32-element vector. b. The efficiency of merge sort is ________.

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