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You are given a directed graph with (possibly negative) weighted edges, in which the shortest path between any two vertices is guaranteed to have at most edges. Give an algorithm that finds the shortest path between two vertices u and v in O(KE)time.

Short Answer

Expert verified

Bellman Ford algorithm in which the edges have negative weights and it finds the shortest path between two vertices inOKE time.

Step by step solution

01

 Step 1: Algorithm used for negative weighted directed graph

Bellman-Ford algorithmis an application of a single source shortest path, which is used forfinding the shortest distance from one vertex to other vertices of a weighted directed graph.

It is almost similar to Dijkstra's algorithm but Dijkstra's algorithm works only for the graph with a positive weight and Bellman-Ford algorithm works with graphs in which edges have negative weights in its graph.

02

Design the Algorithm

Bellman-Ford algorithm applies to the graph for finding the single source’s shortest path.A directed graph with positive and negative edge weight, and returns the length of the shortest cycle in the graph and the graph is acyclic, which takes time at mostOKE So, here the vertex A is the source vertex. Now take an array as a data structure to evaluate a single source’s shortest path between the source and the destination.

From A the distance of A is zero and take the distance of vertex A from each and every vertex is infinity. Now take A as the first vertex and evaluate the weight towards each vertex. Draw a directed positive and negative weighted graph as shown below:

Choose the next vertex from the vertices which have minimum weight and select that node as the second vertex. Then again evaluate the distance of it from every vertex and as get the minimum weight of the node and consider it as the main node. Through this the series of the vertex arises.

Here the vertex A is the source vertex. now take a minheap as a data structure for evaluate single source shortest path between the source and the destination.

From A the distance of A is zero and take the distance of vertex A from each and every vertex is infinity.

All vertices will be released many times in Bellman Ford algorithm.

Select every vertex one by one and put it into the array as a data structure one by one as shown in the figure.

Hence, the shortest distance from the vertex A to vertex D is evaluate in OKEtime.

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Most popular questions from this chapter

You are given a set of cities, along with the pattern of highways between them, in the form of an undirected graph G = (V , E). Each stretch of highway eEconnects two cities, and you know its length in miles, le. You want to get from city s to city t. There’s one problem: your car can only hold enough gas to cover L miles. There are gas stations in each city, but not between cities. Therefore, you can only take a route if every one of its edges has length leL

(a) Given the limitation on your car’s fuel tank capacity, show how to determine in linear time whether there is a feasible route from sto t.

(b) You are now planning to buy a new car, and you want to know the minimum fuel tank capacity that is needed to travel from s to t. Give anO[(V+E)log|V|]algorithm to determine this.

Just like the previous problem, but this time with the Bellman-Ford algorithm.

You are given a directed graph G(V,E)with (possibly negative) weighted edges, along with a specific node sVand a tree T=(V,E'),E'E. Give an algorithm that checks whether T is a shortest-path tree for G with starting point s . Your algorithm should run in linear time.

Squares.Design and analyse an algorithm that takes as input an undirected graph G(V,E) and determines whether graph contains a simple cycle (that is, a cycle which doesn’t intersect itself) of length four. Its running time should be at mostO(V3) time.

You may assume that the input graph is represented either as an adjacency matrix or with adjacency lists, whichever makes your algorithm simpler.

Suppose we want to run Dijkstra’s algorithm on a graph whose edge weights are integers in the range 0,1,........,W, where Wis a relatively small number.
(a) Show how Dijkstra’s algorithm can be made to run in time

O(W|V|+|E|)

(b) Show an alternative implementation that takes time just .

O((|V|+|E|)logW)

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