Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Implement Lagrange's interpolation formula. Imagine we have n+1 measurements of some quantity y that depends on x : (x0,y0),(x1,y1),,(xn,yn). We may think of y as a function of x and ask what y is at some arbitrary point x not coinciding with any of the x0,,xn. This problem is known as interpolation. One way to solve this problem is to fit a continuous function that goes through all the n+1 points and then evaluate this function for any desired x. A candidate for such a function is the polynomial of degree n that goes through all the points. This polynomial can be written pL(x)=k=0nykLk(x) where Lk(x)=i=0,iknxxixkxj The Π notation corresponds to , but the terms are multiplied, e.g., i=0,iknxi=x0x1xk1xk+1xn The polynomial pL(x) is known as Lagrange's interpolation formula, and the points (x0,y0),,(xn,yn) are called interpolation points. Make a function Lagrange (x, points) that evaluates pL at the point x, given n+1 interpolation points as a two-dimensional array points, such that points [i,0] is the x coordinate of point number i and points [i,1] is the corresponding y coordinate. To verify the program, we observe that Lk(xk)=1 and that Lk(xi)=0 for ik, implying that pL(xk)=yk. Write a function verify (points) that computes |pL(xk)yk| at all the interpolation points and checks that the value is approximately zero. Call verify with 5 equally spaced points along the curve y=sin(x) for x[0,π]. Then evaluate pL(x) for an x in the middle of two interpolation points and compare the value of pL(x) with the exact one: sin(x). Name of program file: Lagrange_polynomial1.py.

Short Answer

Expert verified
Implement Lagrange interpolation and test it using 5 points from the sine function. Ensure the polynomial approximates these points accurately.

Step by step solution

01

Understand Lagrange's Interpolation Formula

Lagrange's interpolation formula is a method used to estimate a polynomial that passes through a given set of points. The formula relies on constructing a polynomial of degree n that fits n+1 points (x0,y0),(x1,y1),,(xn,yn). The polynomial is expressed as pL(x)=k=0nykLk(x), where Lk(x) are Lagrange basis polynomials.
02

Define Lagrange Basis Polynomials

For each point, the Lagrange basis polynomial Lk(x) is defined as Lk(x)=i=0,ieqknxxixkxi. This ensures that Lk(xk)=1 and Lk(xi)=0 for ieqk. This property is crucial because it allows pL(x) to interpolate exactly the given points.
03

Implement the Lagrange Function

Create a function `Lagrange(x, points)` that takes a target x value and an array of points as input. Iterate over each point to calculate Lk(x) and use it to compute pL(x). Accumulate these results to get the interpolated value.
04

Verify the Implementation

Write a function `verify(points)` to ensure the correctness of the Lagrange interpolation. For each point in `points`, compute |pL(xk)yk| where xk and yk are the coordinates of each point. The result should be approximately zero, confirming that the polynomial accurately interpolates the points.
05

Test with Sine Function Data

Test the implementation using 5 equally spaced points from the sine function over x[0,π]. Calculate pL(x) for a value of x located between two interpolation points, then compare this result with sin(x) to evaluate the accuracy of the interpolation.
06

Code the Program

Write the `Lagrange_polynomial1.py` file with the implemented functions `Lagrange` and `verify`. Ensure the functions are correctly coded, tested, and debugged to verify that the interpolation and verification work as expected.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Interpolation
Polynomial Interpolation is a fundamental technique in numerical analysis used to find a polynomial that fits a given set of data points. This polynomial is used to estimate values at points not explicitly provided in the data set. The idea is to construct a polynomial of degree n that passes through n+1 data points. The polynomial created joins the dots and enables predictions between known points.
  • Used for estimating unknown values within a range of discrete points.
  • Helps in interpolation by constructing a smooth curve.
  • Applications can be found in fields like engineering, science, and financial modeling.

The main aim is to achieve a polynomial that not only smoothly passes through all the chosen points but also provides reliable estimates for in-between values.
Lagrange Basis Polynomials
Lagrange Basis Polynomials are at the heart of Lagrange Interpolation. Each basis polynomial Lk(x) is designed to be zero at all data points except one, where it equals one. This specific characteristic ensures that each term in the polynomial contributes exactly the value it should at its corresponding data point.
The formula for the Lagrange basis polynomial Lk(x) is given by: Lk(x)=i=0,ieqknxxixkxi
This ingenious design:
  • Guarantees the interpolating polynomial goes through each given point.
  • Allows a unique combination of these basis polynomials to make up the desired polynomial.
  • Makes each data point "control" only its corresponding term in the interpolation polynomial.

This process ensures that the final polynomial mimics the behavior of the original function at the provided data points.
Interpolation Verification
Verification is a critical step in ensuring that the interpolation is accurate. For the Lagrange method, the verification involves checking whether the interpolated polynomial correctly matches the original data points.
For each data point (xk,yk), compute |pL(xk)yk|. If this difference is approximately zero for all points, the interpolation is deemed successful:
  • Confirms that the polynomial passes exactly through each data point.
  • Helps identify any potential inaccuracies or errors in implementation.
  • Ensures that interpolated values between data points will be more reliable.

By comparing results from the interpolated polynomial with known values, students can gain confidence in their method and calculations.
Numerical Methods
Numerical methods are techniques used for finding approximate solutions to mathematical problems. In the context of polynomial interpolation, these methods are crucial for efficiently computing values that might be too complex or impossible to solve analytically. Lagrange interpolation is a type of numerical method that provides an elegant solution to interpolation problems.
Key advantages include:
  • Capability to handle large datasets where analytical solutions are impractical.
  • Fast and efficient calculations once set up, given that the Lagrange polynomials are determined.
  • Offers a way to deal with real-world inaccuracies by providing estimates rather than exact solutions.

Numerical methods like Lagrange Interpolation expand our ability to work with complex data relationships in practical, computationally friendly ways.
Python Programming
Python is an ideal language for implementing numerical algorithms, due to its ease of syntax and powerful libraries. In Lagrange Interpolation, Python can be used to implement both the construction of the interpolation polynomial and its evaluation at desired points. Here's why Python shines in this context:
  • The language's simplicity allows focus on algorithmic logic rather than intricate syntax.
  • Libraries such as NumPy provide robust tools for handling numerical data and performing mathematical operations.
  • Python scripts can easily verify calculations, automate testing, and debug efficiently, helping ensure the accuracy of implementations.

By employing Python to solve interpolation problems, students harness a modern tool that is both powerful and widely applicable in scientific computing.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Plot the velocity profile for pipeflow. A fluid that flows through a (very long) pipe has zero velocity on the pipe wall and a maximum velocity along the centerline of the pipe. The velocity v varies through the pipe cross section according to the following formula: v(r)=(β2μ0)1/nnn+1(R1+1/nr1+1/n) where R is the radius of the pipe, β is the pressure gradient (the force that drives the flow through the pipe), μ0 is a viscosity coefficient (small for air, larger for water and even larger for toothpaste), n is a real number reflecting the viscous properties of the fluid ( n=1 for water and air, n<1 for many modern plastic materials), and r is a radial coordinate that measures the distance from the centerline (r=0 is the centerline, r=R is the pipe wall). Make a function that evaluates v(r). Plot v(r) as a function of r[0,R], with R=1,β=0.02,μ=0.02, and n=0.1. Thereafter, make an animation of how the v(r) curves varies as n goes from 1 and down to 0.01. Because the maximum value of v(r) decreases rapidly as n decreases, each curve can be normalized by its v(0) value such that the maximum value is always unity. Name of program file: plot_velocity_pipeflow.py.

Plot a formula. Make a plot of the function y(t)=v0t0.5gt2 for v0=10,g=9.81 and t[0,2v0/g]. The label on the x axis should be 'time (s)' and the label on the y axis should be 'height (m). Name of program file: plot_ball1.py.

Apply a function to a vector. Given a vector v=(2,3,1) and a function f(x)=x3+xex+1, apply f to each element in v. Then calculate f(v) as v3+vev+1 using vector computing rules. Show that the two results are equal.

Plot a smoothed "hat" function. The "hat" function N(x) defined by (3.5) on page 109 has a discontinuity in the derivative at x=1. Suppose we want to "round" this function such that it looks smooth around x=1. To this end, replace the straight lines in the vicinity of x=1 by a (small) cubic curve y=a(x1)3+b(x1)2+c(x1)+d for x[1ϵ,1+ϵ], where a,b,c, and d are parameters that must be adjusted in order for the cubic curve to match the value and the derivative of the function N(x). The new rounded functions has the specification N~(x)={0,x<0x,0x<1ϵ a1(x1)3+b(x1)+c(x1)+d1,1ϵx<1 a2(x1)3+b(x1)+c(x1)+d2,1x<1+ϵ2x,1+ϵx<20,x2 with a1=13ϵ2,a2=a1,d1=1ϵ+a1ϵ3,d2=1ϵa2ϵ3, and b=c=0. Plot this function. (Hint: Be careful with the choice of x coordinates!) Name of program file: plot_hat.py.

Fill lists with function values. A function with many applications in science is defined as h(x)=12πe12x2 Fig. 5.13 Plot of the dimensionless temperature T(z,t) in the ground for two different t values and b=2. Fill lists xlist and hlist with x and h(x) values for uniformly spaced x coordinates in [4,4]. You may adapt the example in Chapter 5.2.1. Name of program file: fill_lists.py.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free