Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Compute the length of a path. Some object is moving along a path in the plane. At \(n\) points of time we have recorded the corresponding \((x, y)\) positions of the object: \(\left(x_{0}, y_{0}\right),\left(x_{1}, y_{2}\right), \ldots,\left(x_{n-1}, y_{n-1}\right) .\) The total length \(L\) of the path from \(\left(x_{0}, y_{0}\right)\) to \(\left(x_{n-1}, y_{n-1}\right)\) is the sum of all the individual line segments \(\left(\left(x_{i-1}, y_{i-1}\right)\right.\) to \(\left.\left(x_{i}, y_{i}\right), i=1, \ldots, n-1\right)\) : $$ L=\sum_{i=1}^{n-1} \sqrt{\left(x_{i}-x_{i-1}\right)^{2}+\left(y_{i}-y_{i-1}\right)^{2}} $$ Make a function pathlength \((x, y)\) for computing \(L\) according to the formula. The arguments \(\mathrm{x}\) and \(\mathrm{y}\) hold all the \(x_{0}, \ldots, x_{n-1}\) and \(y_{0}, \ldots, y_{n-1}\) coordinates, respectively. Test the function on a triangular path with the four points \((1,1),(2,1),(1,2)\), and \((1,1) .\) Name of program file: pathlength.py.

Short Answer

Expert verified
The path length is approximately 3.41.

Step by step solution

01

Understanding the Problem

The task is to calculate the total length of a path in the plane, given by a series of coordinate points. This path is composed of straight line segments connecting these points. For each segment, the length can be found using the distance formula between two points.
02

Examining the Distance Formula

The distance between two points \((x_{i-1}, y_{i-1})\) and \((x_i, y_i)\) in a 2D plane is calculated using the formula: \[ d = \sqrt{(x_i - x_{i-1})^2 + (y_i - y_{i-1})^2} \]This formula is derived from the Pythagorean theorem.
03

Designing the Function

The function `pathlength(x, y)` will accept two lists of coordinates, \(x\) and \(y\), corresponding to the x-coordinates and y-coordinates of the points, respectively. The function will iterate through all consecutive pairs of points, calculate the distance between them, and accumulate these distances to get the total length \(L\).
04

Implementing the Function

In the program file `pathlength.py`, implement the following code: ```python import math def pathlength(x, y): L = 0 for i in range(1, len(x)): dx = x[i] - x[i-1] dy = y[i] - y[i-1] L += math.sqrt(dx**2 + dy**2) return L ``` This uses Python's `math.sqrt` function for calculating the square root.
05

Testing the Function

Test the `pathlength` function with the provided triangular path points: ```python x = [1, 2, 1, 1] y = [1, 1, 2, 1] L = pathlength(x, y) print(f'The path length is {L:.2f}') ``` This test checks if the function correctly computes the length of the path made by these points.
06

Analyzing the Test Result

By substituting the coordinates into our function, we find the segment lengths: 1. From (1,1) to (2,1) has length 1.2. From (2,1) to (1,2) has length \(\sqrt{2}\), approximately 1.41.3. From (1,2) to (1,1) has length 1.Adding these gives a total path length of approximately 3.41.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distance Formula
When measuring the length between two points in a 2D plane, the distance formula becomes exceptionally useful. The formula is given by \[ d = \sqrt{(x_i - x_{i-1})^2 + (y_i - y_{i-1})^2} \]. This formula stems from the Pythagorean theorem, which relates the sides of a right-angle triangle.
  • Horizontal and Vertical Differences: The expressions \((x_i - x_{i-1})\) and \((y_i - y_{i-1})\) represent the differences in the x and y coordinates between the two points.
  • Hypotenuse Calculation: These differences form two sides of a right triangle with the distance between the points being the hypotenuse, hence the use of the square root to find it.
Understanding this concept is key to applying this formula in geometry, physics, or even computer graphics. The distance formula helps us seamlessly compute how far apart points are, paving the way for further geometric calculations.
Python Function
Creating a Python function to compute path lengths is not only efficient but also straightforward. With Python, we can design reusable pieces of code that solve specific problems. The task is to create a function called `pathlength` that computes the cumulative path length given a series of
  • Function Definition: The function `pathlength(x, y)` receives two lists, x and y, each containing respective x and y coordinates of points.
  • Looping through Points: By iterating through the range of points, starting from 1 (since we're looking at pairs), we calculate the distance between each consecutive pair of points.
  • Distance Calculation: Using the `math.sqrt` function, the distance is calculated for each segment of the path.
  • Sum Accumulation: This distance is then added to the total, which is initialized to zero before the loop.
This approach neatly takes advantage of Python's powerful list operations and its math module, resulting in clear and concise code.
Coordinate Geometry
Coordinate geometry is a branch of mathematics that utilizes algebraic formulas to represent and understand geometric figures and their properties in the coordinate plane. When dealing with problems involving paths, understanding coordinate geometry is beneficial.
  • Coordinate System: Typically, we use the Cartesian coordinate system, which allows any point in the plane to be described by an ordered pair of numbers \((x, y)\).
  • Points and Lines: In this system, geometric concepts like distance, midpoint, and slope can be easily calculated by formulas involving these coordinate points.
  • Path Description: The sequence of points along a path can be visualized as a series of straight lines or segments in this space.
Coordinate geometry offers systematic techniques to analyze shapes and distances, providing a balance between algebra and geometry. It is the foundation for more complex studies involving motions and shapes in higher dimensions.
2D Plane
A 2D plane is a flat, two-dimensional surface extending infinitely in two directions, often defined in mathematics using a grid system where every location is given by two coordinates, typically x and y. Here are a few important points:
  • Basic Concept: Think of the 2D plane as a piece of graph paper. Each point on this graph can be identified by two numbers corresponding to its horizontal (x-axis) and vertical (y-axis) positions.
  • Graphing Figures: The 2D plane allows us to visually represent equations, shapes, and paths, making complex mathematical ideas easier to comprehend.
  • Applications: In coordinate geometry, we often plot points, draw lines, and understand the relationship between different lines and shapes.
By studying the 2D plane, we gain insights not only into basic shapes and their dimensions but also into more complex scenarios involving motion, intersection, or alignment of paths and curves. Mastery of this concept empowers one to tackle a wide range of mathematical and real-world problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Express a step function as a Python function. The following "step" function is known as the Heaviside function and is widely used in mathematics: $$ H(x)=\left\\{\begin{array}{l} 0, x<0 \\ 1, x \geq 0 \end{array}\right. $$ Write a Python function \(\mathrm{H}(\mathrm{x})\) that computes \(H(x)\). Name of program file: Heaviside.py.

Compute velocity and acceleration from position data; one dimension. Let \(x(t)\) be the position of an object moving along the \(x\) axis. The velocity \(v(t)\) and acceleration \(a(t)\) can be approximately computed by the formulas $$ v(t) \approx \frac{x(t+\Delta t)-x(t-\Delta t)}{2 \Delta t}, \quad a(t) \approx \frac{x(t+\Delta t)-2 x(t)+x(t-\Delta t)}{\Delta t^{2}} $$ where \(\Delta t\) is a small time interval. As \(\Delta t \rightarrow 0\), the above formulas approach the first and second derivative of \(x(t)\), which coincide with the well-known definitions of velocity and acceleration. Write a function kinematics \((x, t, d t=1 E-4)\) for computing \(x, v\), and \(a\) time \(t\), using the above formulas for \(v\) and \(a\) with \(\Delta t\) corresponding to dt. Let the function return \(x, v\), and \(a\). Test the function with the position function \(x(t)=e^{-(t-4)^{2}}\) and the time point \(t=5\) (use \(\left.\Delta t=10^{-5}\right)\). Name of program: kinematics 1.py.

Resolve a problem with a function. Consider the following interactive session: Why do we not get any output when calling \(f(5)\) and \(f(10) ?\) (Hint: Save the \(\mathrm{f}\) value in a variable \(\mathrm{r}\) and write print \(\mathrm{r}\).)

Compute the area of an arbitrary triangle. An arbitrary triangle can be described by the coordinates of its three vertices: \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right),\left(x_{3}, y_{3}\right)\), numbered in a counterclockwise direction. The area of the triangle is given by the formula $$ A=\frac{1}{2}\left|x_{2} y_{3}-x_{3} y_{2}-x_{1} y_{3}+x_{3} y_{1}+x_{1} y_{2}-x_{2} y_{1}\right| $$ Write a function area(vertices) that returns the area of a triangle whose vertices are specified by the argument vertices, which is a nested list of the vertex coordinates. For example, vertices can be \([[0,0],[1,0],[0,2]]\) if the three corners of the triangle have coordinates \((0,0),(1,0)\), and \((0,2)\). Test the area function on a triangle with known area. Name of program file: area_triangle.py.

Find an error in a program. Consider the following program for computing $$ f(x)=e^{r x} \sin (m x)+e^{s x} \sin (n x) $$ def \(f(x, m, n, r, s):\) return expsin \((x, r, m)+\operatorname{expsin}(x, s, n)\) \(x=2.5\) print \(f(x, 0.1,0.2,1,1)\) from math import exp, sin def expsin \((x, p, q):\) return \(\exp \left(p^{* x}\right) * \sin \left(q^{* x}\right)\) Running this code results in NameError: global name 'expsin' is not defined What is the problem? Simulate the program flow by hand or use the debugger to step from line to line. Correct the program.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free