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A clay layer of 4 m thickness is located below a sand layer of 10 m thickness. The volumetric weights are all 20kN/m3, and the groundwater table coincides with the soil surface. The compression constant of the clay is C10=20. Predict the settlement of the soil by compression of the clay layer due to an additional load of 40kPa.

Short Answer

Expert verified
Answer: The predicted settlement of the soil due to compression of the clay layer is approximately 2.857 meters.

Step by step solution

01

Identify the given data

We are given the following data: - Thickness of clay layer (hclay) = 4m - Thickness of sand layer (hsand) = 10m - Volumetric weight (γ) = 20kN/m3 - Groundwater table location coincides with the soil surface - Compression constant of the clay (C10) = 20 - Additional load applied (Δσ) = 40kPa
02

Calculate the stress increase at the clay layer

First, we will calculate the increase in stress at the middle of the clay layer due to the additional load applied. The formula to calculate this is: Δσclay=Δσhsandhsand+hclay Where: - Δσclay is the increase in stress at the middle of the clay layer - Δσ is the additional load applied - hsand is the thickness of the sand layer - hclay is the thickness of the clay layer Plugging in the given values: Δσclay=401010+4=4001428.57kPa
03

Calculate the compression index (Cc)

Next, we will calculate the compression index (Cc) using the compression constant (C10): Cc=1C10=120=0.05
04

Calculate the settlement of the clay layer

Now we can calculate the settlement of the clay layer (ΔHclay) using the formula: ΔHclay=CchclayΔσclay1+e0 Where: - ΔHclay is the settlement of the clay layer - Cc is the compression index - hclay is the thickness of the clay layer - Δσclay is the stress increase at the clay layer - e0 is the initial void ratio (assumed to be 1 for simplicity) Plugging in the values: ΔHclay=0.05428.571+1=5.71422.857m The predicted settlement of the soil due to compression of the clay layer is approximately 2.857m.

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