The speed of light in a medium of index of refraction \(n\) is \(v=d s / d t=c /
n .\) Then the time of transit from \(A\) to \(B\) is \(t=\int_{A}^{B} d t=c^{-1}
\int_{A}^{B} n d s .\) By Fermat's principle above, \(t\) is stationary. If the
path consists of two straight line segments with \(n\) constant over each
segment, then \(\int_{A}^{B} n d s=n_{1} d_{1}+n_{2} d_{2}\) and the problem can
be done by ordinary calculus. Thus solve the following problems:
Derive the optical law of reflection. Hint: Let light go from the point
\(A=\left(x_{1}, y_{1}\right)\) to \(B=\left(x_{2}, y_{2}\right)\) via an
arbitrary point \(P=\) \((x, 0)\) on a mirror along the \(x\) axis. Set \(d t / d
x=(n / c) d D / d x=\)
\(0,\) where \(D=\) distance \(A P B,\) and show that then \(\theta=\phi\).