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Show that the geodesics on a circular cylinder (with elements parallel to the \(z\) axis) are helices \(a z+b \theta=c,\) where \(a, b, c\) are constants depending on the given endpoints. (Hint: Use cylindrical coordinates.) Note that the equation \(a z+b \theta=c\) includes the circles \(z=\) const. (for \(b=0\) ), straight lines \(\theta=\) const. (for \(a=0\) ), and the special helices \(a z+b \theta=0\)

Short Answer

Expert verified
Geodesics on a circular cylinder are described by helices \(a z + b \theta = c\).

Step by step solution

01

Understand the Problem

The goal is to show that the geodesics (shortest paths) on a circular cylinder are helices given by the equation \(a z + b \theta = c \), where \(a, b, c\) are constants that depend on the endpoints. The problem specifies that the cylinder has its elements parallel to the \(z\)-axis and uses cylindrical coordinates.
02

Set Up Cylindrical Coordinates

Cylindrical coordinates \((r, \theta, z)\) are used, where \(r\) is the radius, \(\theta\) is the azimuthal angle, and \(z\) is the height. For a circular cylinder with its axis along the \(z\), the radius \(r\) is constant (say \(r = R\)).
03

Express Components of Line Element in Cylindrical Coordinates

The line element \(ds^2\) in cylindrical coordinates is given by: \[ ds^2 = dr^2 + R^2 d\theta^2 + dz^2. \] For a fixed radius \(R\), this simplifies to: \[ ds^2 = R^2 d\theta^2 + dz^2 \]
04

Calculate the Geodesics Using Euler-Lagrange

Consider the Lagrangian \[ L = \sqrt{R^2 \left(\frac{d\theta}{ds}\right)^2 + \left(\frac{dz}{ds}\right)^2}. \] The Euler-Lagrange equations apply here, but since \(L\) does not explicitly depend on \(s\), the simplified form is \[ \frac{d}{ds} \left( \frac{\partial L}{\partial \dot{y}} \right) = 0, \] where \(y\) can be either \(\theta\) or \(z\). This leads to the constancy of \( \frac{d\theta}{ds} \) and \( \frac{dz}{ds} \).
05

Integrate the Differential Equations

Integrate the differential equations for \( \frac{d\theta}{ds} \) and \( \frac{dz}{ds} \): \( \frac{d\theta}{ds} = \frac{B}{R^2} \) and \( \frac{dz}{ds} = A. \) Integrate to get \(\theta = \frac{B}{R^2}s + \theta_0\) and \(z = As + z_0\).
06

Combine the Results and Eliminate \(s\)

By eliminating the parameter \(s\) from the equations for \(\theta(s)\) and \(z(s)\), arrive at the relationship \[a z + b \theta = c \] where \( a = 1/A \), \( b = -1/B \), and \( c \) is a constant.
07

Interpret the Geodesic Equation

The equation \(a z + b \theta = c\) describes a family of helices on the circular cylinder, which includes vertical circles (\(b = 0\)), straight lines (\(a = 0\)), and the general helices where both gradients are non-zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cylindrical Coordinates
Cylindrical coordinates are a way of representing points in a 3D space using three parameters: radius \(r\), azimuthal angle \(\theta\), and height \(z\). It's a mix between polar coordinates (in the \(r-\theta\) plane) and Cartesian coordinates \(z\).

These coordinates are particularly convenient for objects with cylindrical symmetry.
In the context of the given problem, the cylinder has a constant radius \(r = R\), which simplifies our calculations significantly

Key points to remember about cylindrical coordinates:
  • \(r\) - The radial distance from the \(z\)-axis.
  • \(\theta\) - The angle around the \(z\)-axis.
  • \(z\) - The height along the \(z\)-axis.
In this problem, since the radius \(r = R\) remains constant, it allows us to focus only on the changes in \(\theta\) and \(z\), which are more straightforward.
Euler-Lagrange Equations
The Euler-Lagrange equations are a fundamental tool in calculus of variations, used to find the path that minimizes a given functional. They originate from the principle of least action in physics. Here, they help us find the geodesics, or shortest paths, on a surface.

For a given Lagrangian (\(L\)), the Euler-Lagrange equation states:
\[\frac{d}{ds} \left( \frac{\partial L}{\partial \dot{y}} \right) - \frac{\partial L}{\partial y} = 0.\]

In our exercise, the Lagrangian \(L\) is:
\[L = \sqrt{R^2 \left(\frac{d\theta}{ds}\right)^2 + \left(\frac{dz}{ds}\right)^2}.\]

We apply the Euler-Lagrange equations to this Lagrangian, leading to constant expressions for \(\frac{d\theta}{ds}\) and \(\frac{dz}{ds}\).

This gives us two first integrals, which we integrate to find the forms of \(\theta\) and \(z\).
These integrals essentially describe how \(\theta\) and \(z\) change along the geodesic on the cylinder's surface.
Helices
A helix is a type of smooth curve in 3D space, characterized by its helical (spiral-like) form.
The defining feature of a helix on a cylinder is that as you move along the curve, it winds around the cylinder at a constant angle relative to the cylinder's axis.
In the given problem, we need to show that geodesics on the cylinder are described by helical paths.

The general form of the helix on the cylinder is given by the equation:
\[a z + b \theta = c,\]
where \(a\), \(b\), and \(c\) are constants. This covers different types of paths:
  • Circular paths: If \(b = 0\), the path is a horizontal circle at a constant height \(z\).
  • Straight lines: If \(a = 0\), the path is a vertical line with a constant \(\theta\).
  • General helices: When both constants are non-zero, the path forms a helical structure around the cylinder.
These helices are the geodesics on the cylinder, showing that no matter the particular case (circle, line, or helix), they all fit under the equation \(a z + b \theta = c\).

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Most popular questions from this chapter

Write the \(\theta\) Lagrange equation for a particle moving in a plane if \(V=V(r)\) (that is, a central force). Use the \(\theta\) equation to show that: (a) The angular momentum \(\mathbf{r} \times m \mathbf{v}\) is constant. (b) The vector \(\mathbf{r}\) sweeps out equal areas in equal times (Kepler's second law).

Write and solve the Euler equations to make the following integrals stationary. Change the independent variable, if needed, to make the Euler equation simpler. \(\int_{x_{1}}^{x_{2}} \sqrt{1+y^{2} y^{\prime 2}} d x\)

(a) Consider the case of two dependent variables. Show that if \(F=F\left(x, y, z, y^{\prime}, z^{\prime}\right)\) and we want to find \(y(x)\) and \(z(x)\) to make \(I=\int_{x_{1}}^{x_{2}} F d x\) stationary, then \(y\) and \(z\) should each satisfy an Euler equation as in (5.1). Hint: Construct a formula for a varied path \(Y\) for \(y\) as in Section \(2[Y=y+\epsilon \eta(x) \text { with } \eta(x) \text { arbitrary }]\) and construct a similar formula for \(z\) llet \(Z=z+\epsilon \zeta(x),\) where \(\zeta(x)\) is another arbitrary function]. Carry through the details of differentiating with respect to \(\epsilon,\) putting \(\epsilon=0,\) and integrating by parts as in Section \(2 ;\) then use the fact that both \(\eta(x)\) and \(\zeta(x)\) are arbitrary to get (5.1). (b) Consider the case of two independent variables. You want to find the function \(u(x, y)\) which makes stationary the double integral $$\int_{y_{1}}^{y_{2}} \int_{x_{1}}^{x_{2}} F\left(u, x, y, u_{x}, u_{y}\right) d x d y$$. Hint: Let the varied \(U(x, y)=u(x, y)+\epsilon \eta(x, y)\) where \(\eta(x, y)=0\) at \(x=x_{1}\) \(x=x_{2}, y=y_{1}, y=y_{2},\) but is otherwise arbitrary. As in Section \(2,\) differentiate \(x=y=y=y\), with respect to \(\epsilon,\) set \(\epsilon=0,\) integrate by parts, and use the fact that \(\eta\) is arbitrary. Show that the Euler equation is then $$\frac{\partial}{\partial x} \frac{\partial F}{\partial u_{x}}+\frac{\partial}{\partial y} \frac{\partial F}{\partial u_{y}}-\frac{\partial F}{\partial u}=0$$ (c) Consider the case in which \(F\) depends on \(x, y, y^{\prime},\) and \(y^{\prime \prime} .\) Assuming zero values of the variation \(\eta(x)\) and its derivative at the endpoints \(x_{1}\) and \(x_{2},\) show that then the Euler equation becomes $$\frac{d^{2}}{d x^{2}} \frac{\partial F}{\partial y^{\prime \prime}}-\frac{d}{d x} \frac{\partial F}{\partial y^{\prime}}+\frac{\partial F}{\partial y}=0$$

Use Fermat's principle to find the path of a light ray through a medium of index of refraction proportional to the given function. \((x+y)^{1 / 2} \quad\) Hint: Make the change of variables \((45^{\circ}\) rotation). $$X=\frac{1}{\sqrt{2}}(x+y), \quad Y=\frac{1}{\sqrt{2}}(x-y) ; \quad \text { what is } \quad d X^{2}+d Y^{2} ?$$

Find a first integral of the Euler equation to make stationary the integrals. $$\int_{a}^{b} \frac{y y^{\prime 2} d x}{\sqrt{1+y^{\prime 2}}}$$

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