Chapter 7: Problem 10
A general form of Parseval's theorem says that if two functions are expanded in Fourier series $$f(x)=\frac{1}{2} a_{0}+\sum_{1}^{\infty} a_{n} \cos n x+\sum_{1}^{\infty} b_{n} \sin n x$$ $$g(x)=\frac{1}{2} a_{0}^{\prime}+\sum_{1}^{\infty} a_{n}^{\prime} \cos n x+\sum_{1}^{\infty} b_{n}^{\prime} \sin n x$$ $$\text { then the average value of } f(x) g(x) \text { is } \frac{1}{4} a_{0} a_{0}^{\prime}+\frac{1}{2} \sum_{1}^{\infty} a_{n} a_{n}^{\prime}+\frac{1}{2} \sum_{1}^{\infty} b_{n} b_{n}^{\prime} . \text { Prove this. }$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.