Chapter 6: Problem 21
Find vector fields \(\mathbf{A}\) such that \(\mathbf{V}=\) curl \(\mathbf{A}\) for each given \(\mathbf{V}\) $$\mathbf{V}=-\mathbf{k}$$
Short Answer
Expert verified
A = -y\textbf{i}
Step by step solution
01
Recall the definition of the curl of a vector field
Given a vector field \(\textbf{A}=(A_x, A_y, A_z)\), the curl is defined as \(\text{curl} \textbf{A} = abla \times \textbf{A}\). Utilize this in subsequent steps.
02
Express the curl operator in component form
The curl of \(\textbf{A}\) can be expressed as: \(abla \times \textbf{A} = \begin{vmatrix} \textbf{i} & \textbf{j} & \textbf{k} \ \frac{\rightarrow}{\rightarrow x} & \frac{\rightarrow}{\rightarrow y} & \frac{\rightarrow}{\rightarrow z} \ A_x & A_y & A_z \ \right\rangle\).
03
Setup the vector equation \(\text{curl}\textbf{A} = -\textbf{k}\)
From the given \(\textbf{V} = -\textbf{k}\), set up the component-wise equations: \(abla \times \textbf{A} = -\textbf{k}\). This yields: \( \frac{\rightarrow A_z}{\rightarrow y} - \frac{\rightarrow A_y}{\rightarrow z} = -1, \frac{\rightarrow A_x}{\rightarrow z} - \frac{\rightarrow A_z}{\rightarrow x} = 0, \frac{\rightarrow A_y}{\rightarrow x} - \frac{\rightarrow A_x}{\rightarrow y} = 0\).
04
Solve the component equations
Solve \( \frac{\rightarrow A_z}{\rightarrow y} - \frac{\rightarrow A_y}{\rightarrow z} = -1\): Set \(A_z \rightarrow 0\) and \( -\frac{\rightarrow A_y}{\rightarrow z} = -1 \rightarrow A_y = z\). Solve \( \frac{\rightarrow A_x}{\rightarrow z} -= \frac{\rightarrow A_z}{\rightarrow x} = 0\) to yield constant \(A_x \rightarrow f(x,y)\). Then solve \( \frac{\rightarrow A_y}{\rightarrow x} - \frac{\rightarrow A_x}{\rightarrow y} = 0\) for \( A_y = - \frac{\rightarrow f}{\rightarrow y ^ -1},\) with substitution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
curl of a vector field
The curl of a vector field is a fundamental operator in vector calculus. It operates on a three-dimensional vector field and results in another vector field. The curl measures the rotation or 'circulation' of the field at each point. Mathematically, for a vector field \textbf{A} = (A_x, A_y, A_z)\, the curl is defined by the cross product of the del operator \( abla \times\ \textbf{A} \). In simpler terms, the curl gives us a way to describe how a vector field rotates around any given point in space.
component form of curl
To understand the curl of a vector field, it's crucial to break it down into its component form. This helps make solving real problems more manageable. The component form of the curl of a vector field \( \textbf{A}\) is given by:
\( abla \times\ \textbf{A} = \begin{vmatrix} \textbf{i} & \textbf{j} & \textbf{k} \ \frac{\rightarrow}{\rightarrow x} & \frac{\rightarrow}{\rightarrow y} & \frac{\rightarrow}{\rightarrow z} \ A_x & A_y & A_z \end{vmatrix} \).
This determinant expands into the following:
\( \textnormal{i} \( \frac{\rightarrow A_z}{\rightarrow y} - \frac{\rightarrow A_y}{\rightarrow z} \) - \textnormal{j} \( \frac{\rightarrow A_z}{\rightarrow x} - \frac{\rightarrow A_x}{\rightarrow z} \) + \textnormal{k} \( \frac{\rightarrow A_y}{\rightarrow x} - \frac{\rightarrow A_x}{\rightarrow y} \) \).
This represents each component of the curl of \textbf{A} in terms of partial derivatives.
\( abla \times\ \textbf{A} = \begin{vmatrix} \textbf{i} & \textbf{j} & \textbf{k} \ \frac{\rightarrow}{\rightarrow x} & \frac{\rightarrow}{\rightarrow y} & \frac{\rightarrow}{\rightarrow z} \ A_x & A_y & A_z \end{vmatrix} \).
This determinant expands into the following:
\( \textnormal{i} \( \frac{\rightarrow A_z}{\rightarrow y} - \frac{\rightarrow A_y}{\rightarrow z} \) - \textnormal{j} \( \frac{\rightarrow A_z}{\rightarrow x} - \frac{\rightarrow A_x}{\rightarrow z} \) + \textnormal{k} \( \frac{\rightarrow A_y}{\rightarrow x} - \frac{\rightarrow A_x}{\rightarrow y} \) \).
This represents each component of the curl of \textbf{A} in terms of partial derivatives.
solving vector component equations
When tasked with finding a vector field \(\textbf{A}\) where the curl matches a given vector field \(\textbf{V}\), you need to break it into its component equations. Given the overall equation \( abla \times \textbf{A} = - \textbf{k}\), you establish the following component equations:
Each of these expressions comes from corresponding partial derivatives equating to specified components of \(\textbf{V}\). Solving these step-by-step helps find the original vector field which matches the required curl.
- \( \frac{\rightarrow A_z}{\rightarrow y} - \frac{\rightarrow A_y}{\rightarrow z} = -1 \)
- \( \frac{\rightarrow A_x}{\rightarrow z} - \frac{\rightarrow A_z}{\rightarrow x} = 0 \)
- \( \frac{\rightarrow A_y}{\rightarrow x} - \frac{\rightarrow A_x}{\rightarrow y} = 0 \)`
Each of these expressions comes from corresponding partial derivatives equating to specified components of \(\textbf{V}\). Solving these step-by-step helps find the original vector field which matches the required curl.
vector calculus
Vector calculus is a branch of mathematics that deals with vector fields and the differentiation and integration of vector functions. It includes operations like the curl, divergence, and gradient, and is essential in fields such as physics and engineering.
Key Applications are:
Understanding these operations helps us solve complex real-world problems. It provides the tools to work with field quantities that vary over time and space. So, getting a grip on concepts like curl provides a foundation for diving deeper into topics like electromagnetic fields or fluid mechanics.
Key Applications are:
- Fluid Dynamics: Describing fluid flow.
- Electromagnetism: Analyzing electric and magnetic fields.
Understanding these operations helps us solve complex real-world problems. It provides the tools to work with field quantities that vary over time and space. So, getting a grip on concepts like curl provides a foundation for diving deeper into topics like electromagnetic fields or fluid mechanics.