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In the problems of this section, set up and evaluate the integrals by hand and check your results by computer. $$\int_{y=0}^{2} \int_{x=2 y}^{4} d x d y$$

Short Answer

Expert verified
The value of the integral is 4.

Step by step solution

01

Identify the limits of integration

First, note the limits of integration. The outer integral is over variable \(y\) from 0 to 2. The inner integral is over variable \(x\) from \(2y\) to 4.
02

Write the inner integral

Integrate the inner integral with respect to \(x\): \[ \int_{2y}^{4} dx \]
03

Evaluate the inner integral

The integral of 1 with respect to \(x\) is \(x\). So, evaluate \( \int_{2y}^{4} dx \): \[ x \bigg|_{2y}^{4} = 4 - 2y \]
04

Write and evaluate the outer integral

Substitute the result from the inner integral into the outer integral: \[ \int_{0}^{2} (4 - 2y) dy \] Now integrate with respect to \(y\).
05

Integrate the outer integral

Find the integral of \(4 - 2y\) with respect to \(y\): \[ \int_{0}^{2} (4 - 2y) dy = 4y - y^2 \bigg|_{0}^{2} \]
06

Evaluate the result

Substitute the limits into the result: \[ (4(2) - (2)^2) - (4(0) - (0)^2) = 8 - 4 - 0 = 4 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

limits of integration
In double integrals, setting up the correct limits of integration is crucial. The limits define the region over which you're integrating. There are two sets of limits: one for the outer integral and one for the inner integral.
In our problem, the outer integral for variable \( y \) ranges from 0 to 2, while the inner integral for variable \( x \) ranges from \( 2y \) to 4. This nesting of integrals allows us to integrate step-by-step, leading us to the final solution.
evaluating integrals
To evaluate double integrals, follow the nested structure of inner and outer integrals. Start with the inner integral, integrate it, and then use the result in the outer integral.
Integrating is a two-step process where you:
  • Integrate the inner integral while treating the outer variable as a constant.
  • Use the result in the outer integral and integrate it.
Following this process step-by-step ensures you evaluate the integral accurately, leading to the correct answer.
inner integral
The inner integral is the first part of the nested integration process. You integrate with respect to the inner variable while treating the outer variable as a constant.
In our problem, the inner integral is \[ \int_{2y}^{4} dx \].
Since the integrand is 1, the integral of 1 with respect to \( x \) is simply \( x \). Hence, we have:
\[ x \bigg|_{2y}^{4} \]
Evaluating this from \( 2y \) to 4 gives \( 4 - 2y \). This result will be used in the outer integral.
outer integral
After evaluating the inner integral, substitute its result into the outer integral to continue the process. The outer integral is integrated with respect to its variable.
For our problem, the outer integral becomes:
\[ \int_{0}^{2} (4 - 2y) dy \].
We now integrate \( 4 - 2y \) with respect to \( y \), yielding:
\[ 4y - y^2 \bigg|_{0}^{2} \].
Evaluating this from 0 to 2 gives \( (8 - 4) - (0 - 0) = 4 \).
integration techniques
Using proper integration techniques simplifies the process, ensuring you'll arrive at the correct solution. For double integrals:
  • Focus first on your inner integral, treating outer variables as constants.
  • Carefully address the limits of integration.
  • Handle one integral at a time, then substitute and integrate the result.
This methodical approach ensures you handle each step systematically and accurately.

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Most popular questions from this chapter

The following notation is used in the problems: \(M=\) mass, \(\bar{x}, \bar{y}, \bar{z}=\) coordinates of center of mass (or centroid if the density is constant), \(I=\) moment of inertia (about axis stated), \(I_{x}, I_{y}, I_{z}=\) moments of inertia about \(x, y, z\) axes, \(I_{m}=\) moment of inertia (about axis stated) through the center of mass. Note: It is customary to give answers for \(I, I_{m}, I_{x},\) etc., as multiples of \(M\) (for example, \(I=\frac{1}{3} M l^{2}\) ). For the pyramid inclosed by the coordinate planes and the plane \(x+y+z=1\) : (a) Find its volume. (b) Find the coordinates of its centroid. (c) If the density is \(z\), find \(M\) and \(\bar{z}\).

Write a triple integral in cylindrical coordinates for the volume inside the cylinder \(x^{2}+y^{2}=4\) and between \(z=2 x^{2}+y^{2}\) and the \((x, y)\) plane. Evaluate the integral.

(a) Write a triple integral in spherical coordinates for the volume inside the cone \(z^{2}=x^{2}+y^{2}\) and between the planes \(z=1\) and \(z=2 .\) Evaluate the integral. (b) Do (a) in cylindrical coordinates.

Find the area of the part of the sphere of radius \(a\) and center at the origin which is above the square in the \((x, y)\) plane bounded by \(x=\pm a / \sqrt{2}\) and \(y=\pm a / \sqrt{2} .\) Hint for evaluating the integral: Change to polar coordinates and evaluate the \(r\) integral first.

The following notation is used in the problems: \(M=\) mass, \(\bar{x}, \bar{y}, \bar{z}=\) coordinates of center of mass (or centroid if the density is constant), \(I=\) moment of inertia (about axis stated), \(I_{x}, I_{y}, I_{z}=\) moments of inertia about \(x, y, z\) axes, \(I_{m}=\) moment of inertia (about axis stated) through the center of mass. Note: It is customary to give answers for \(I, I_{m}, I_{x},\) etc., as multiples of \(M\) (for example, \(I=\frac{1}{3} M l^{2}\) ). A chain in the shape \(y=x^{2}\) between \(x=-1\) and \(x=1\) has density \(|x| .\) Find (a) \(M\), (b) \(\bar{x}, \bar{y}\).

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