Chapter 5: Problem 3
In the problems of this section, set up and evaluate the integrals by hand and check your results by computer. $$\int_{y=0}^{2} \int_{x=2 y}^{4} d x d y$$
Short Answer
Expert verified
The value of the integral is 4.
Step by step solution
01
Identify the limits of integration
First, note the limits of integration. The outer integral is over variable \(y\) from 0 to 2. The inner integral is over variable \(x\) from \(2y\) to 4.
02
Write the inner integral
Integrate the inner integral with respect to \(x\): \[ \int_{2y}^{4} dx \]
03
Evaluate the inner integral
The integral of 1 with respect to \(x\) is \(x\). So, evaluate \( \int_{2y}^{4} dx \): \[ x \bigg|_{2y}^{4} = 4 - 2y \]
04
Write and evaluate the outer integral
Substitute the result from the inner integral into the outer integral: \[ \int_{0}^{2} (4 - 2y) dy \] Now integrate with respect to \(y\).
05
Integrate the outer integral
Find the integral of \(4 - 2y\) with respect to \(y\): \[ \int_{0}^{2} (4 - 2y) dy = 4y - y^2 \bigg|_{0}^{2} \]
06
Evaluate the result
Substitute the limits into the result: \[ (4(2) - (2)^2) - (4(0) - (0)^2) = 8 - 4 - 0 = 4 \]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
limits of integration
In double integrals, setting up the correct limits of integration is crucial. The limits define the region over which you're integrating. There are two sets of limits: one for the outer integral and one for the inner integral.
In our problem, the outer integral for variable \( y \) ranges from 0 to 2, while the inner integral for variable \( x \) ranges from \( 2y \) to 4. This nesting of integrals allows us to integrate step-by-step, leading us to the final solution.
In our problem, the outer integral for variable \( y \) ranges from 0 to 2, while the inner integral for variable \( x \) ranges from \( 2y \) to 4. This nesting of integrals allows us to integrate step-by-step, leading us to the final solution.
evaluating integrals
To evaluate double integrals, follow the nested structure of inner and outer integrals. Start with the inner integral, integrate it, and then use the result in the outer integral.
Integrating is a two-step process where you:
Integrating is a two-step process where you:
- Integrate the inner integral while treating the outer variable as a constant.
- Use the result in the outer integral and integrate it.
inner integral
The inner integral is the first part of the nested integration process. You integrate with respect to the inner variable while treating the outer variable as a constant.
In our problem, the inner integral is \[ \int_{2y}^{4} dx \].
Since the integrand is 1, the integral of 1 with respect to \( x \) is simply \( x \). Hence, we have:
\[ x \bigg|_{2y}^{4} \]
Evaluating this from \( 2y \) to 4 gives \( 4 - 2y \). This result will be used in the outer integral.
In our problem, the inner integral is \[ \int_{2y}^{4} dx \].
Since the integrand is 1, the integral of 1 with respect to \( x \) is simply \( x \). Hence, we have:
\[ x \bigg|_{2y}^{4} \]
Evaluating this from \( 2y \) to 4 gives \( 4 - 2y \). This result will be used in the outer integral.
outer integral
After evaluating the inner integral, substitute its result into the outer integral to continue the process. The outer integral is integrated with respect to its variable.
For our problem, the outer integral becomes:
\[ \int_{0}^{2} (4 - 2y) dy \].
We now integrate \( 4 - 2y \) with respect to \( y \), yielding:
\[ 4y - y^2 \bigg|_{0}^{2} \].
Evaluating this from 0 to 2 gives \( (8 - 4) - (0 - 0) = 4 \).
For our problem, the outer integral becomes:
\[ \int_{0}^{2} (4 - 2y) dy \].
We now integrate \( 4 - 2y \) with respect to \( y \), yielding:
\[ 4y - y^2 \bigg|_{0}^{2} \].
Evaluating this from 0 to 2 gives \( (8 - 4) - (0 - 0) = 4 \).
integration techniques
Using proper integration techniques simplifies the process, ensuring you'll arrive at the correct solution. For double integrals:
- Focus first on your inner integral, treating outer variables as constants.
- Carefully address the limits of integration.
- Handle one integral at a time, then substitute and integrate the result.