Chapter 4: Problem 11
Given \(L(q, \dot{q})\) such that \(d L=\dot{p} d q+p d \dot{q},\) find \(H(p, q)\) so that \(d H=\dot{q} d p-\dot{p} d q\) Comments: \(L\) and \(H\) are functions used in mechanics called the Lagrangian and the Hamiltonian. The quantities \(\dot{q}\) and \(\bar{p}\) are actually time derivatives of \(p\) and \(q\), but you make no use of the fact in this problem. Treat \(\dot{p}\) and \(\dot{q}\) as if they were two more variables having nothing to do with \(p\) and \(q\). Hint. Use a Legendre transformation. On your first try you will probably get \(-H .\) Look at the text discussion of Legendre transformations and satisfy yourself that \(g=q y-f\) would have been just as satisfactory as \(g=f-q y\) in (11.23).
Short Answer
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Key Concepts
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