Chapter 3: Problem 20
Find a vector perpendicular to both \(\mathbf{i}+\mathbf{j}\) and \(\mathbf{i}-2 \mathbf{k}\).
Short Answer
Expert verified
The vector is \(-2\textbf{j} - \textbf{k}\).
Step by step solution
01
Define the Vectors
Identify the given vectors. Let \(\textbf{A} = \textbf{i} + \textbf{j}\) and \(\textbf{B} = \textbf{i} - 2\textbf{k}\).
02
Use the Cross Product
To find a vector perpendicular to both \(\textbf{A} \) and \(\textbf{B}\), we use the cross product \( \textbf{A} \times \textbf{B} \).
03
Set up the Determinant
Set up the cross product determinant using the unit vectors \(\textbf{i}, \textbf{j}, \textbf{k}\): \(\begin{vmatrix} \textbf{i} & \textbf{j} & \textbf{k} \ \text{ 1 } & \text{1} & \text{0} \ \text{1} & \text{0} & -2 \ \end{vmatrix} \).
04
Calculate the Determinant
Compute the determinant. \(\textbf{A} \times \textbf{B} = \textbf{i} \begin{vmatrix} 1 & 0 \ 0 & -2 \end{vmatrix} - \textbf{j} \begin{vmatrix} 1 & -2 \ 1 & 0 \end{vmatrix} + \textbf{k} \begin{vmatrix} 1 & 1 \ 1 & 0 \end{vmatrix} \).
05
Solve the Determinants
Solve for each cofactor: \(\textbf{i}(0 \times -2 - 1 \times 0) - \textbf{j}(1 \times 0 - 1 \times -2) + \textbf{k}(1 \times 0 - 1 \times 1) \).
06
Simplify the Result
Simplify to get the resulting vector: \(\textbf{0i} - \textbf{2j} - \textbf{1k} \), or \(-2\textbf{j} - \textbf{k}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
When you need to find a vector that is perpendicular to two given vectors, the cross product is your go-to operation. It's represented by \(\textbf{A} \times \textbf{B}\), where \(\textbf{A}\) and \(\textbf{B}\) are the two vectors. The cross product yields another vector that is perpendicular to the original vectors. This is particularly useful in problems involving physics, engineering, and computer graphics.
The resulting vector's direction can be determined using the right-hand rule. Point your index finger of the right hand in the direction of \(\textbf{A}\), and your middle finger in the direction of \(\textbf{B}\). Your thumb will point in the direction of \(\textbf{A} \times \textbf{B}\). Simply put:
The resulting vector's direction can be determined using the right-hand rule. Point your index finger of the right hand in the direction of \(\textbf{A}\), and your middle finger in the direction of \(\textbf{B}\). Your thumb will point in the direction of \(\textbf{A} \times \textbf{B}\). Simply put:
- \textbf{A} \times \textbf{B}\ is perpendicular to both \(\textbf{A}\) and \(\textbf{B}\).
- Use the right-hand rule for the direction.
Determinant
To calculate the cross product, we use the determinant of a matrix formed by the unit vectors \(\textbf{i}, \textbf{j}, \textbf{k}\) and the components of the vectors \(\textbf{A}\) and \(\textbf{B}\). Setting up this matrix helps in systematically carrying out the operation.
In our case, the determinant looks like this:
\(\begin{vmatrix} \textbf{i} & \textbf{j} & \textbf{k} \ 1 & 1 & 0 \ 1 & 0 & -2 \ \end{vmatrix}\).
Each component of the resulting vector will be calculated using the minor determinants. For example, the \(\textbf{i}\) component is found by ignoring the row and column of \(\textbf{i}\), then calculating the determinant of the remaining 2x2 matrix. Each cofactor is similarly found, giving us the perpendicular vector.
In our case, the determinant looks like this:
\(\begin{vmatrix} \textbf{i} & \textbf{j} & \textbf{k} \ 1 & 1 & 0 \ 1 & 0 & -2 \ \end{vmatrix}\).
Each component of the resulting vector will be calculated using the minor determinants. For example, the \(\textbf{i}\) component is found by ignoring the row and column of \(\textbf{i}\), then calculating the determinant of the remaining 2x2 matrix. Each cofactor is similarly found, giving us the perpendicular vector.
- Set up a 3x3 determinant with vectors and unit vectors.
- Calculate minor determinants for each component using 2x2 matrices.
Vector Operations
Vector operations like addition, subtraction, and cross product help us manipulate vectors to get the desired results. In this exercise, we used the cross product, but understanding other operations is equally important:
- Addition: Combine corresponding components.
- Subtraction: Subtract corresponding components.
- Cross Product: Finds a vector perpendicular to the original ones.
Unit Vectors
Unit vectors, usually denoted as \(\textbf{i}, \textbf{j}, \textbf{k}\), are vectors with a magnitude of one. These unit vectors represent the standard axes in 3D space:
Always remember that understanding and visualizing unit vectors can simplify your work significantly.
- \textbf{i}\: Points along the x-axis
- \textbf{j}\: Points along the y-axis
- \textbf{k}\: Points along the z-axis
Always remember that understanding and visualizing unit vectors can simplify your work significantly.