Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Find the rank of each of the following matrices. $$\left(\begin{array}{cccc} 2 & -3 & 5 & 3 \\ 4 & -1 & 1 & 1 \\ 3 & -2 & 3 & 4 \end{array}\right)$$

Short Answer

Expert verified
The rank of the matrix is 3.

Step by step solution

01

- Set Up the Matrix

Start with the matrix provided: \[ \left(\begin{array}{cccc} 2 & -3 & 5 & 3 \ 4 & -1 & 1 & 1 \ 3 & -2 & 3 & 4 \end{array}\right) \]
02

- Row Reduce to Echelon Form

Use row operations to convert the matrix to row echelon form. Start by making the element in the first column, second row zero by using row operation \(R2 = R2 - 2R1\) and \(R3 = R3 - \frac{3}{2}R1\): \[ \left( \begin{array}{cccc} 2 & -3 & 5 & 3 \ 0 & 5 & -9 & -5 \ 0 & \frac{5}{2} & \frac{-9}{2} & \frac{5}{2} \end{array} \right) \] Next, make the element in the second column, third row zero by doing \(R3 = R3 - \frac{1}{2}R2\): \[ \left( \begin{array}{cccc} 2 & -3 & 5 & 3 \ 0 & 5 & -9 & -5 \ 0 & 0 & 0 & 5 \end{array} \right) \]
03

- Identify Pivot Columns

Examine the row-reduced matrix to find pivot columns. A pivot column is a column that contains the leading entry (first non-zero entry) of a row. For the matrix after row reduction: \[ \left( \begin{array}{cccc} 2 & -3 & 5 & 3 \ 0 & 5 & -9 & -5 \ 0 & 0 & 0 & 5 \end{array} \right) \] the first, second, and fourth columns are pivot columns.
04

- Determine the Rank

The rank of the matrix is defined as the number of pivot columns. From the matrix, there are 3 pivot columns (the first, second, and fourth columns). Therefore, the rank of the matrix is 3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Row Reduction
Row reduction is a key technique in linear algebra used for simplifying matrices. It involves a series of row operations to transform a given matrix into a more convenient form, such as row echelon form or reduced row echelon form. These operations do not change the fundamental properties of the matrix.

There are three main types of row operations:
  • Swapping two rows
  • Multiplying a row by a non-zero scalar
  • Adding or subtracting a multiple of one row to another
To start, we take the original matrix and aim to create zeros below each leading 1 (pivot) in its columns. For instance, in the provided problem, we first nullified the element in the first column, second row by applying the row operation \( R2 = R2 - 2R1 \).

By strategically applying these operations, one can simplify the matrix to reveal crucial information such as rank and the number of pivot columns.
Echelon Form
The echelon form of a matrix is an upper triangular form where each leading entry (or pivot) in a row is to the right of the leading entry in the row above. It makes it easier to solve systems of linear equations or identify key matrix properties.

To achieve row echelon form (REF), we use row reduction techniques:
  • Convert the leftmost non-zero entry in each row to 1 (pivoting)
  • Make all elements below the pivots zero (using row operations)
  • Ensure each pivot is to the right of the pivot in the row above
In our example, after performing the necessary row operations, we obtain the matrix:
\[ \left( \begin{array}{cccc} 2 & -3 & 5 & 3 \ 0 & 5 & -9 & -5 \ 0 & 0 & 0 & 5 \end{array} \right) \]

This form gives us clear visibility of the pivot positions and allows us to proceed directly to identifying the number of pivot columns.
Pivot Columns
Pivot columns in a matrix are columns that contain the first non-zero entry (or pivot) of each row in row echelon form. Identifying pivot columns is essential in determining the rank of a matrix.

After transforming the given matrix to echelon form, we look for the columns where the first nonzero entries appear. These entries are known as pivots. For the example matrix transformed to:
\[ \left( \begin{array}{cccc} 2 & -3 & 5 & 3 \ 0 & 5 & -9 & -5 \ 0 & 0 & 0 & 5 \end{array} \right) \]

The first, second, and fourth columns contain the pivots.

The number of pivot columns directly corresponds to the rank of the matrix. In this scenario, we have three pivot columns, which tells us that the rank of the matrix is 3.

Understanding pivot columns not only helps in finding the rank but also in solving linear equations and understanding the span and linear independence of a set of vectors.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let each of the following matrices represent an active transformation of vectors in the (x, \(y\) ) plane (axes fixed, vectors rotated or reflected). As in Example \(3,\) show that each matrix is orthogonal, find its determinant, and find the rotation angle, or find the line of reflection. $$\frac{1}{2}\left(\begin{array}{cc}-\sqrt{3} & 1 \\\\-1 & -\sqrt{3}\end{array}\right)$$.

To see a physical example of non-commuting rotations, do the following experiment. Put a book on your desk and imagine a set of rectangular axes with the \(x\) and \(y\) axes in the plane of the desk with the \(z\) axis vertical. Place the book in the first quadrant with the \(x\) and \(y\) axes along the edges of the book. Rotate the book \(90^{\circ}\) about the \(x\) axis and then \(90^{\circ}\) about the \(z\) axis; note its position. Now repeat the experiment, this time rotating \(90^{\circ}\) about the \(z\) axis first, and then \(90^{\circ}\) about the \(x\) axis; note the different result. Write the matrices representing the \(90^{\circ}\) rotations and multiply them in both orders. In each case, find the axis and angle of rotation.

Show that each of the following matrices is orthogonal and find the rotation and/or reflection it produces as an operator acting on vectors. If a rotation, find the axis and angle; if a reflection, find the reflecting plane and the rotation, if any, about the normal to that plane. $$\frac{1}{3}\left(\begin{array}{rrr} -1 & 2 & 2 \\ 2 & -1 & 2 \\ 2 & 2 & -1 \end{array}\right)$$

The characteristic equation for a second-order matrix \(M\) is a quadratic equation. We have considered in detail the case in which M is a real symmetric matrix and the roots of the characteristic equation (eigenvalues) are real, positive, and unequal. Discuss some other possibilities as follows: (a) \(\quad \mathrm{M}\) real and symmetric, eigenvalues real, one positive and one negative. Show that the plane is reflected in one of the eigenvector lines (as well as stretched or shrunk). Consider as a simple special case $$M=\left(\begin{array}{rr} 1 & 0 \\ 0 & -1 \end{array}\right)$$ (b) \(\quad \mathrm{M}\) real and symmetric, eigenvalues equal (and therefore real). Show that \(\mathrm{M}\) must be a multiple of the unit matrix. Thus show that the deformation consists of dilation or shrinkage in the radial direction (the same in all directions) with no rotation (and reflection in the origin if the root is negative). (c) \(\quad M\) real, not symmetric, eigenvalues real and not equal. Show that in this case the eigenvectors are not orthogonal. Hint: Find their dot product. (d) \(\quad \mathrm{M}\) real, not symmetric, eigenvalues complex. Show that all vectors are rotated, that is, there are no (real) eigenvectors which are unchanged in direction by the transformation. Consider the characteristic equation of a rotation matrix as a special case.

Find the distance between the two given lines. $$\mathbf{r}=(4,3,-1)+(1,1,1) t \quad \text { and } \quad \mathbf{r}=(4,-1,1)+(1,-2,-1) t$$

See all solutions

Recommended explanations on Combined Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free