Chapter 2: Problem 6
Find one or more values of each of the following complex expressions and compare with a computer solution. $$(-e)^{i \pi}$$
Short Answer
Expert verified
The value of \[(-e)^{i\pi}\] is approximately \(5.242e^{-5}\).
Step by step solution
01
Understand the Expression
The expression \[(-e)^{i\pi}\] involves a negative base raised to a complex exponent. Note that the base here is the exponential function 'e', which is approximately equal to 2.718.
02
Express the Base in Polar Form
To handle the negative base, convert \(-e\) into its polar form. The magnitude of \(-e\) is \(|-e| = e\). The angle, or argument, of \(-e\) is \(\pi + 0 = \pi\) radians (since \(e\) lies on the negative x-axis). Therefore, \(-e = e^{i\pi}\).
03
Apply the Exponent
Use the property of exponents \((a^b)^c = a^{bc}\) to simplify the expression: \[(-e)^{i\pi} = (e^{i\pi})^{i\pi}\] simplifies to \[e^{i\pi \cdot i\pi} = e^{-\pi^2}\]
04
Compute the Value
Since \(e\) raised to any real number can be computed directly, the value of \[e^{-\pi^2} = e^{-9.869}\approx 5.242e^{-5}\]
05
Compare with a Computer Solution
A computer algebra system (CAS) or scientific calculator can be used to verify that \[(-e)^{i\pi}\] indeed simplifies to approximately \(5.242e^{-5}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Form
To work with complex numbers effectively, converting them to polar form is essential. The polar form represents a complex number \, \(z\), using magnitude \, \(r\), and angle \, \(\theta\) \((z=r e^{i \theta})\). This approach is useful as it provides a clear geometric interpretation. For any complex number \, \(z = x + iy\), where \, \(x\) and \, \(y\) are real, the polar form is found as follows:
- Calculate the magnitude \, \(r\) using \, \(|z|=\sqrt{x^2 + y^2}\).
- Determine the argument \, \(\theta\), which is the angle the number makes with the positive x-axis, using \, \(\theta=\arg(z) = \arctan\left(\frac{y}{x}\right)\).
Exponential Function
The exponential function is powerful when dealing with complex numbers. Euler's formula, \, \(e^{i \theta} = \cos(\theta) + i\sin(\theta)\), bridges exponential functions and trigonometry. When applied to complex exponents, it allows us to simplify expressions. For example, given a complex exponent \, \(i\pi\), Euler's formula lets us write:
- \(e^{i \theta}\) where \(\theta = \pi\) becomes \(e^{i\pi} = \cos(\pi) + i\sin(\pi)\). Given \(\cos(\pi)=-1\) and \(\sin(\pi)=0\), we get \(e^{i\pi} = -1\).
Euler's Formula
Euler's Formula, \, \(e^{i \theta} = \cos(\theta) + i\sin(\theta)\), is a cornerstone of complex number analysis. It connects exponential functions to trigonometric functions, simplifying many complex calculations. For any angle \, \(\theta\), Euler’s formula expresses the complex number on the unit circle in terms of its cosine and sine components. Key Interpretations:
- For \, \(\theta = \pi\), the formula becomes \(e^{i\pi} = -1\). This sophisticated relationship underpins many trigonometric identities and simplifies complex arithmetic.
- In solving \, \((-e)^{i\pi}\), converting \, \(-e\) into polar form using Euler’s formula is necessary. Recognizing \, \(-e = e^{i\pi}\) indicates utilizing \(e^{i\pi} = -1\).