Chapter 2: Problem 34
Find each of the following in the \(x+i y\) form and check your answers by computer. $$\sin \frac{i \pi}{2}$$
Short Answer
Expert verified
\[ \text{sin}\left( \frac{i \pi}{2} \right) = i \left( \frac{e^{\frac{\pi}{2}} - e^{-\frac{\pi}{2}}}{2} \right). \]
Step by step solution
01
Write the given expression
The given expression to find is \(\frac{i \, \pi}{2}\). We need to find \(\text{sin} \, \frac{i \, \pi}{2}\) in the form of \(x + i y\).
02
Recall the definition of \(\text{sin}(z)\) for a complex number
The sine of a complex number \(z = x + i y\) where \(x\) and \(y\) are real numbers is given by:\[ \sin(z) = \sin(x + iy) = \sin(x) \cosh(y) + i \cos(x) \sinh(y) \]
03
Substitute \(z = \frac{i \, \pi}{2}\) into the definition
Here, \(x = 0\) and \(y = \frac{\pi}{2}\). Substituting these values in, we obtain:\[ \sin \left(0 + i \frac{\pi}{2} \right) = \sin(0) \cosh \left( \frac{\pi}{2} \right) + i \cos(0) \sinh \left( \frac{\pi}{2} \right) \]
04
Evaluate each trigonometric and hyperbolic function
We know from trigonometric and hyperbolic identities that:\(\sin(0) = 0\),\(\cos(0) = 1\),\(\cosh \left( \frac{\pi}{2} \right) = \frac{e^{\frac{\pi}{2}} + e^{-\frac{\pi}{2}}}{2}\),\(\sinh \left( \frac{\pi}{2} \right) = \frac{e^{\frac{\pi}{2}} - e^{-\frac{\pi}{2}}}{2}\).
05
Simplify the expression
By substituting these values back into the equation, we have:\[ \sin \left( \frac{i \pi}{2} \right) = 0 \cdot \cosh \left( \frac{\pi}{2} \right) + i \cdot 1 \cdot \sinh \left( \frac{\pi}{2} \right) = i \cdot \frac{e^{\frac{\pi}{2}} - e^{-\frac{\pi}{2}}}{2}\].
06
Final result
Recognizing that \(\sinh \left( \frac{\pi}{2} \right)\) is the same as expressing:\[ \sin \left( \frac{i \pi}{2} \right) = i \sinh \left( \frac{\pi}{2} \right) \implies \sin \left( \frac{i \pi}{2} \right) = i \left( \frac{e^{\frac{\pi}{2}} - e^{-\frac{\pi}{2}}}{2} \right). \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers are numbers that include both a real part and an imaginary part. They can be written in the form \(a + bi\) where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit with the property \(i^2 = -1\). Complex numbers are crucial in solving problems that cannot be addressed using just real numbers. They appear in various fields including engineering, physics, and applied mathematics.
When dealing with complex functions like sine or cosine, you need to handle the real and imaginary parts separately. This allows you to unravel more complex expressions and understand behaviors in different domains.
When dealing with complex functions like sine or cosine, you need to handle the real and imaginary parts separately. This allows you to unravel more complex expressions and understand behaviors in different domains.
Hyperbolic Functions
Hyperbolic functions are analogs of trigonometric functions but for the hyperbola rather than the circle. They include hyperbolic sine (sinh) and hyperbolic cosine (cosh).
Each hyperbolic function has a specific identity, similar to trigonometric ones, and they help solve a wide array of problems involving complex numbers. For instance, the hyperbolic sine and cosine of a value \(y\) can be defined as:
\[\text{sinh}(y) = \frac{e^y - e^{-y}}{2} \]
\[\text{cosh}(y) = \frac{e^y + e^{-y}}{2} \]
These relationships come in handy when transforming and simplifying expressions involving complex arguments, as seen in our exercise with the value \(\frac{i \, \pi}{2}\). By using these identities, you can change complex trigonometric expressions into more manageable forms.
Each hyperbolic function has a specific identity, similar to trigonometric ones, and they help solve a wide array of problems involving complex numbers. For instance, the hyperbolic sine and cosine of a value \(y\) can be defined as:
\[\text{sinh}(y) = \frac{e^y - e^{-y}}{2} \]
\[\text{cosh}(y) = \frac{e^y + e^{-y}}{2} \]
These relationships come in handy when transforming and simplifying expressions involving complex arguments, as seen in our exercise with the value \(\frac{i \, \pi}{2}\). By using these identities, you can change complex trigonometric expressions into more manageable forms.
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that hold true for different values of their variables. These identities are important as they enable the simplification and transformation of complex trigonometric expressions.
A few key identities used in the context of complex numbers include:
They connect the behavior of trigonometric functions with those of hyperbolic functions, providing a unified framework for analysis and computation.
A few key identities used in the context of complex numbers include:
- \[\text{sin}(0) = 0 \]
- \[\text{cos}(0) = 1 \]
- \[\text{sin}(x) = \text{cosh}(y) + i \text{cos}(x) \text{sinh}(y) \]
They connect the behavior of trigonometric functions with those of hyperbolic functions, providing a unified framework for analysis and computation.