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Use a series you know to show that n=0(1+iπ)nn!=e.

Short Answer

Expert verified
n=0fty(1+iπ)nn!=e.

Step by step solution

01

- Identify the Series

Recognize that the given sum n=0fty(1+iπ)nn! represents an exponential series. In general, the exponential series is given by ex=n=0ftyxnn!.
02

- Compare with the Exponential Series

Understand that n=0fty(1+iπ)nn! matches the form of the exponential series ex. Here, x=1+iπ.
03

- Apply the Exponential Series Formula

Using the exponential series formula, substitute x=1+iπ into the formula to obtain e1+iπ.
04

- Simplify the Exponential Expression

Recall Euler's formula, which states eix=cos(x)+isin(x). Therefore, eiπ=1. Substituting this into the expression, we get e1+iπ=eeiπ=e(1)=e.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Euler's Formula
Euler's formula is a stunning result in mathematics, revealing a deep connection between complex exponentials and trigonometric functions. Euler's formula states that for any real number x, \br


Euler's formula is often used to solve problems involving complex numbers and trigonometry, making it a vital tool in various fields such as electrical engineering and physics. In the context of the given exercise, Euler's formula helps us simplify the complex exponential expression. For example, in Step 4 of the solution, we use the fact that eiπ=cos(π)+isin(π). Since cos(π)=1 and sin(π)=0, we get eiπ=1. This result is crucial for simplifying and solving the given series. Understanding Euler's formula allows students to handle a broader range of problems involving complex numbers and exponential functions.
Complex Numbers
Complex numbers might seem daunting, but let's simplify the concept. A complex number is of the form a+bi, where a and b are real numbers, and i is the imaginary unit, satisfying i2=1. This makes complex numbers an extension of the real numbers. To grasp them better:

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