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Find each of the following in rectangular \((a+b i)\) form if \(z=2-3 i ;\) if \(z=x+i y\) $$z / \bar{z}$$

Short Answer

Expert verified
The expression in rectangular form is \(-\frac{5}{13} - \frac{12}{13}i\).

Step by step solution

01

Identify Conjugate of z

The conjugate of a complex number is found by changing the sign of the imaginary part. If the complex number is given by \(z = 2 - 3i\), then its conjugate is given by \(\bar{z} = 2 + 3i\).
02

Perform Division

Next, we need to divide \(z\) by \(\bar{z}\). This can be written as \(\frac{z}{\bar{z}} = \frac{2 - 3i}{2 + 3i}\). To simplify this, multiply the numerator and the denominator by the conjugate of the denominator. This gives: \(\frac{2 - 3i}{2 + 3i} \times \frac{2 - 3i}{2 - 3i}\).
03

Multiply Numerator and Denominator

Multiply the numerator and the denominator by the conjugate of the denominator. This results in: \[\frac{(2 - 3i)(2 - 3i)}{(2 + 3i)(2 - 3i)}\].
04

Apply Formula For Multiplying Conjugates

We use the formula for multiplying conjugates: \((a+bi)(a-bi) = a^2 + b^2\). For the denominator: \((2 + 3i)(2 - 3i) = 2^2 + 3^2 = 4 + 9 = 13\).
05

Expand Numerator

Expand the numerator: \((2 - 3i)^2 = 4 - 12i + 9i^2\). Remind that \(i^2 = -1\) gives: \((2 - 3i)^2 = 4 - 12i + 9(-1) = 4 - 12i - 9 = -5 - 12i\).
06

Simplify the Fraction

Plug the expanded numerator and calculated denominator back in to simplify the fraction: \[\frac{-5 - 12i}{13}\]. Thus \((x + yi)\) form of the expression is: \(-\frac{5}{13} - \frac{12}{13}i\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

complex number conjugate
The conjugate of a complex number changes the sign of the imaginary component. If you have a number like \(z = 2 - 3i\), the conjugate, represented as \(\bar{z}\), flips the sign of \i\. So in this case, \(\bar{z} = 2 + 3i\).
Conjugates are very useful in simplifying complex number operations, especially when dealing with division. By using conjugates, complex denominators can be turned into real numbers, which are much easier to handle.
rectangular form
Rectangular form is one way to express complex numbers, represented as \(a + bi\). Here, \a\ is the real part and \b\ is the imaginary part.
For example, in our problem, \(z = 2 - 3i\) means the real part is 2 and the imaginary part is -3. Converting complex numbers into rectangular form helps keep track of both real and imaginary components easily.
fraction simplification
Simplification often involves turning a complex fraction into a more manageable form. For our division problem, this means multiplying by the conjugate of the denominator.
Let's take \(\frac{2 - 3i}{2 + 3i}\). We multiply both the numerator and the denominator by the conjugate of the denominator (in this case, \(2 - 3i\)) to get: \(\frac{(2 - 3i)(2 - 3i)}{(2 + 3i)(2 - 3i)}\).
This method gets rid of the complex number in the denominator, making it easier to simplify.
complex number operations
Complex number operations might seem tricky, but breaking them down step-by-step helps. Let's focus on multiplication and division.
When multiplying complex numbers, use the distributive property: \((a + bi)(c + di) = ac + adi + bci + bdi^2 \). Don't forget that \(i^2 = -1\).
Division involves multiplying the numerator and the denominator by the conjugate of the denominator. For example, \( \frac{2 - 3i}{2 + 3i} \times \frac{2 - 3i}{2 - 3i} \). After multiplying, use the formula \((a+bi)(a-bi) = a^2 + b^2\) for the denominator. Finally, simplify the result, converting it back into rectangular form if necessary.

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Most popular questions from this chapter

Express the following complex numbers in the \(x+i y\) form. Try to visualize each complex number, using sketches as in the examples if necessary. The first twelve problems you should be able to do in your head (and maybe some of the others- -try it!) Doing a problem quickly in your head saves time over using a computer. Remember that the point in doing problems like this is to gain skill in manipulating complex expressions, so a good study method is to do the problems by hand and use a computer to check your answers. $$\left(\frac{2 i}{i+\sqrt{3}}\right)^{19}$$

Find each of the following in the \(x+i y\) form and check your answers by computer. $$\cos (i \pi)$$

Show that if a sequence of complex numbers tends to zero, then the sequence of absolute values tends to zero too, and vice versa. Hint: \(a_{n}+i b_{n} \rightarrow 0\) means \(a_{n} \rightarrow 0\) and \(b_{n} \rightarrow 0\).

Prove that \(\cos \theta+\cos 3 \theta+\cos 5 \theta+\cdots+\cos (2 n-1) \theta=\frac{\sin 2 n \theta}{2 \sin \theta}\), \(\sin \theta+\sin 3 \theta+\sin 5 \theta+\cdots+\sin (2 n-1) \theta=\frac{\sin ^{2} n \theta}{\sin \theta}\). Hint: Use Euler's formula and the geometric progression formula.

Express the following complex numbers in the \(x+i y\) form. Try to visualize each complex number, using sketches as in the examples if necessary. The first twelve problems you should be able to do in your head (and maybe some of the others- -try it!) Doing a problem quickly in your head saves time over using a computer. Remember that the point in doing problems like this is to gain skill in manipulating complex expressions, so a good study method is to do the problems by hand and use a computer to check your answers. $$\left(\frac{1-i}{\sqrt{2}}\right)^{40}$$

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