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Show that adding a constant \(K\) to a random variable increases the average by \(K\) but does not change the variance. Show that multiplying a random variable by \(K\) multiplies both the average and the standard deviation by \(K\).

Short Answer

Expert verified
Adding \(K\) increases the mean by \(K\) but keeps the variance the same. Multiplying by \(K\) scales both mean and standard deviation by \(K\).

Step by step solution

01

Define the random variable and its properties

Let the random variable be denoted as \(X\) with the mean (expected value) \(E(X) = \mu_X\) and variance \(Var(X) = \sigma_X^2\). We'll consider two operations: adding a constant \(K\) and multiplying by a constant \(K\).
02

Adding a constant to the random variable

Consider the new random variable \(Y = X + K\). The mean of \(Y\) can be calculated as follows: \[E(Y) = E(X + K) = E(X) + K = \mu_X + K\]. Therefore, the mean of \(Y\) increases by \(K\).
03

Verify the variance when adding a constant

The variance of \(Y\) is calculated by: \[Var(Y) = Var(X + K) = Var(X) = \sigma_X^2\]. Constant \(K\) does not affect the variance.
04

Multiplying the random variable by a constant

Next, consider \(Z = KX\). The mean of \(Z\) is: \[E(Z) = E(KX) = K \times E(X) = K \times \mu_X\]. Hence, multiplying \(X\) by \(K\) multiplies its mean by \(K\).
05

Verify the variance when multiplying by a constant

The variance of \(Z\) is: \[Var(Z) = Var(KX) = K^2 \times Var(X) = K^2 \times \sigma_X^2\]. The standard deviation of \(Z\) is \sqrt{Var(Z)} = K \times \sigma_X\. Hence, multiplying \(X\) by \(K\) multiplies its standard deviation by \(K\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

mean of random variables
When dealing with random variables, understanding their mean (or expected value) is essential. The mean of a random variable provides a measure of its central tendency. It is similar to the average in a set of numbers and helps to identify the 'center' or 'typical' value around which the random variable tends to cluster. For a random variable \(X\), the mean is denoted as \(E(X)\) or \(\mu_X\).

Let's break it down:

- **Adding a Constant**: When you add a constant \(K\) to a random variable, the entire distribution shifts by that constant value. If \(Y = X + K\), then the mean of \(Y\) can be calculated as:

\[ E(Y) = E(X + K) = E(X) + K = \mu_X + K \]

This shows that the mean increases by the constant \(K\), but the shape of the distribution doesn't change.

- **Multiplying by a Constant**: When you multiply a random variable by a constant, the mean is scaled by that same constant. If \(Z = KX\), the mean of \(Z\) would be:

\[ E(Z) = E(KX) = K \times E(X) = K \times \mu_X \]

Thus, the mean is multiplied by \(K\). This operation scales all values of the random variable, but the 'center' of the distribution is adjusted accordingly.
variance of random variables
The variance of a random variable measures how spread out the values of the variable are around the mean. It gives us an idea about the variability or dispersion of the data. For a random variable \(X\), the variance is denoted as \(Var(X)\) or \(\sigma_X^2\).

Let's dive in:

- **Adding a Constant**: When a constant \(K\) is added to a random variable, the spread of the data does not change, only its position does. For \(Y = X + K\), the variance remains the same:

\[ Var(Y) = Var(X + K) = Var(X) = \sigma_X^2 \]

Thus, adding a constant does not change the variance.

- **Multiplying by a Constant**: When a random variable is multiplied by a constant, the variance is affected by the square of that constant. For \(Z = KX\), the variance of \(Z\) is given by:

\[ Var(Z) = Var(KX) = K^2 \times Var(X) = K^2 \times \sigma_X^2 \]

This means the variance is scaled by \(K^2\), indicating a larger spread if \(K > 1\) or a smaller spread if \(K < 1\).
standard deviation of random variables
The standard deviation of a random variable is the square root of its variance and offers a way of understanding the spread of the distribution in the same units as the random variable itself. For a random variable \(X\), the standard deviation is denoted as \(\sigma_X\).

Here's the breakdown:

- **Adding a Constant**: As with variance, adding a constant to a random variable does not change its standard deviation. For \(Y = X + K\):

\[ \sigma_Y = \sigma_X \]

The spread of the data remains the same; only the position of the data set shifts.

- **Multiplying by a Constant**: When multiplying a random variable by a constant, the standard deviation is scaled directly by that constant. For \(Z = KX\):

\[ \sigma_Z = K \times \sigma_X \]

Thus, the standard deviation is multiplied by \(K\), showing a direct scaling of the spread of the data based on the constant multiplier. This is particularly useful in fields like finance, where scaling risks and returns are common.

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Most popular questions from this chapter

(a) Find the probability that in two tosses of a coin, one is heads and one tails. That in six tosses of a die, all six of the faces show up. That in 12 tosses of a 12-sided die, all 12 faces show up. That in \(n\) tosses of an \(n\) -sided die, all \(n\) faces show up. (b) The last problem in part (a) is equivalent to finding the probability that, when \(n\) balls are distributed at random into \(n\) boxes, each box contains exactly one ball. Show that for large \(n,\) this is approximately \(e^{-n} \sqrt{2 \pi n}\)

Three coins are tossed; what is the probability that two are heads and one tails? That the first two are heads and the third tails? If at least two are heads, what is the probability that all are heads?

Consider the set of all permutations of the numbers \(1,2,3 .\) If you select a permutation at random, what is the probability that the number 2 is in the middle position? In the first position? Do your answers suggest a simple way of answering the same questions for the set of all permutations of the numbers 1 to \(7 ?\)

Show that the expected number of heads in a single toss of a coin is \(\frac{1}{2}\). Show in two ways that the expected number of heads in two tosses of a coin is 1: (a) Let \(x=\) number of heads in two tosses and find \(\bar{x}\). (b) Let \(x=\) number of heads in toss 1 and \(y=\) number of heads in toss 2 ; find the average of \(x+y\) by Problem \(9 .\) Use this method to show that the expected number of heads in \(n\) tosses of a coin is \(\frac{1}{2} n\).

Set up sample spaces for Problems 1 to 7 and list next to each sample point the value of the indicated random variable \(x,\) and the probability associated with the sample point. Make a table of the different values \(x_{i}\) of \(x\) and the corresponding probabilities \(p_{i}=f\left(x_{i}\right)\) Compute the mean, the variance, and the standard deviation for \(x\). Find and plot the cumulative distribution function \(F(x)\). A random variable \(x\) takes the values \(0,1,2,3,\) with probabilities \(\frac{5}{12}, \frac{1}{3}, \frac{1}{12}, \frac{1}{6}\).

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