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Find the steady-state temperature distribution inside a sphere of radius 1 when the surface temperatures are as given. $$\cos \theta-3 \sin ^{2} \theta$$.

Short Answer

Expert verified
The steady-state temperature distribution is found by solving the Laplace equation with the given boundary conditions and expressing the result in terms of spherical harmonics.

Step by step solution

01

Formulating the Problem

Consider the steady-state heat equation inside a sphere of radius 1. The general form of the Laplace equation in spherical coordinates is \[ abla^2 T = 0 \] where \( T \) is the temperature distribution.
02

Boundary Conditions

The boundary condition is given by the surface temperature: \[ T(1, \theta, \theta) = \theta \theta - 3 \theta \theta^2 \] where \( \theta \) is the colatitude and \( \theta \) is the azimuthal angle.
03

Solving the Laplace Equation

To solve the Laplace equation, we attempt a solution of the form \[ T(r, \theta, \theta) = R(r)Y(\theta, \theta) \] where \( R(r) \) is the radial function and \( Y(\theta, \theta) \) is a spherical harmonic that satisfies the angular part.
04

Separating Variables

Substitute the assumed solution into the Laplace equation and separate the variables: \[ \frac{1}{R} \frac{d}{dr} \left( r^2 \frac{dR}{dr} \right) + \frac{1}{Y} abla_{\Omega}^2 Y = 0 \] This gives two separate ordinary differential equations for \( R(r) \) and \( Y(\theta, \theta) \).
05

Solving the Radial Part

Solve the radial ODE: \[ \frac{d}{dr} \left( r^2 \frac{dR}{dr} \right) - l(l+1)R = 0 \] The solution is \[ R(r) = Ar^l + \frac{B}{r^{l+1}} \] where \( A \) and \( B \) are constants.
06

Solving the Angular Part

The angular part \( Y(\theta, \theta) \) satisfies the spherical harmonics equation: \[ abla_{\Omega}^2 Y + l(l+1)Y = 0 \] The solution is a linear combination of spherical harmonics \( Y_l^m(\theta, \theta) \).
07

Applying Boundary Conditions

Match the boundary condition \( T(1, \theta, \theta) = \cos \theta - 3 \sin^2 \theta \) to the general solution form: \[ T(r, \theta, \theta) = \sum_{l=0}^{\infty} \sum_{m=-l}^{l} \left( A_{lm}r^l + \frac{B_{lm}}{r^{l+1}} \right) Y_l^m(\theta, \theta) \].
08

Coefficient Matching

Determine the coefficients \( A_{lm} \) and \( B_{lm} \) by expanding \( \cos \theta - 3 \sin^2 \theta \) in terms of spherical harmonics and comparing terms.
09

Constructing the Solution

Combine the determined coefficients to construct the final steady-state temperature distribution inside the sphere.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laplace equation
The Laplace equation is a fundamental partial differential equation. It appears in many fields such as physics, engineering, and mathematics. Specifically, in this context, it helps us understand heat distribution within a sphere at equilibrium. The equation is given by \( abla^2 T = 0 \), where \( T \) denotes temperature. This equation implies there's no internal heat generation or dissipation, making it ideal for steady-state conditions. Here, the core challenge is solving Laplace's equation in spherical coordinates, as these naturally fit the geometry of the sphere.
spherical coordinates
Spherical coordinates are a three-dimensional coordinate system. They are particularly suited for spherical objects. The three key parameters in spherical coordinates are radius (\( r \)), colatitude (\( \theta \)), and azimuthal angle (\( \phi \)). Each point in space is represented uniquely with these three. This makes them especially convenient for problems like finding the temperature distribution in a sphere.
The radius (\( r \)) measures the distance from the origin to the point.
The colatitude (\( \theta \)) is the angle from the positive z-axis.
The azimuthal angle (\( \phi \)) is the angle in the xy-plane from the positive x-axis.
Using these coordinates, we can easily break down complex spatial problems into simpler parts.
boundary conditions
Boundary conditions are essential in solving differential equations. They provide necessary constraints. For our temperature problem in the sphere, the given boundary condition is at the sphere's surface (\( r = 1 \)). It's defined by the function \( T(1, \theta, \phi) = \cos \theta - 3 \sin^2 \theta \). Boundary conditions allow us to tailor the general solution. We match it to specific physical constraints.
In this problem, the temperature on the surface directly influences the temperature throughout the entire sphere. By matching this condition, we can integrate our solution to satisfy the physical reality of the scenario.
spherical harmonics
Spherical harmonics are special functions defined on the surface of a sphere. They are used for solving problems with spherical symmetry. In our temperature distribution exercise, they simplify the angular part of the Laplace equation.
Spherical harmonics are denoted by \( Y_l^m(\theta, \phi) \), where \( l \) and \( m \) are integers. These functions form an orthonormal basis for functions defined on the sphere. This means they allow for the expansion of arbitrary functions, like our boundary condition function \( \cos \theta - 3 \sin^2 \theta \), into series. Such expansion helps in analyzing and solving the temperature distribution problem.
This process not only provides a clearer insight into the solution structure but also facilitates the determination of coefficients needed for constructing the solution in practical scenarios.

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Most popular questions from this chapter

Write the Schrödinger equation (3.22) if \(\psi\) is a function of \(x,\) and \(V=\frac{1}{2} m \omega^{2} x^{2}\) (this is a one-dimensional harmonic oscillator). Find the solutions \(\psi_{n}(x)\) and the energy eigenvalues \(E_{n}\). Hints: In Chapter 12 , equation (22.1) and the first equation in \((22.11),\) replace \(x\) by \(\alpha x\) where \(\alpha=\sqrt{m \omega / \hbar} .\) (Don't forget appropriate factors of \(\alpha\) for the \(x\) 's in the denominators of \(D=d / d x\) and \(\psi^{\prime \prime}=d^{2} \psi / d x^{2} .\) ) Compare your results for equation (22.1) with the Schrödinger equation you wrote above to see that they are identical if \(E_{n}=\left(n+\frac{1}{2}\right) \hbar \omega .\) Write the solutions \(\psi_{n}(x)\) of the Schrödinger equation using Chapter 12, equations (22.11) and (22.12).

Assume from electrostatics the equations \(\nabla \cdot \mathbf{E}=\rho / \epsilon_{0}\) and \(\mathbf{E}=-\nabla \phi(\mathbf{E}=\) electric field, \(\left.\rho=\text { charge density, } \epsilon_{0}=\text { constant, } \phi=\text { electrostatic potential }\right)\) Show that the electrostatic potential satisfies Laplace's equation (1.1) in a charge-free region and satisfies Poisson's equation (1.2) in a region of charge density \(\rho\)

Find the electrostatic potential outside a conducting sphere of radius \(a\) placed in an originally uniform electric field, and maintained at zero potential. Hint: Let the original field \(\mathbf{E}\) be in the negative \(z\) direction so that \(\mathbf{E}=-E_{0} \mathbf{k} .\) Then since \(\mathbf{E}=-\nabla \Phi,\) where \(\Phi\) is the potential, we have \(\Phi=E_{0} z=E_{0} r \cos \theta\) (Verify this!) for the original potential. You then want a solution of Laplace's equation \(\nabla^{2} u=0\) which is zero at \(r=a\) and becomes \(u \sim \Phi\) for large \(r\) (that is, far away from the sphere). Select the solutions of Laplace's equation in spherical coordinates which have the right \(\theta\) and \(\phi\) dependence (there are just two such solutions) and find the combination which reduces to zero for \(r=a\).

Find the temperature distribution in a rectangular plate \(10 \mathrm{cm}\) by \(30 \mathrm{cm}\) if two adjacent sides are held at \(100^{\circ}\) and the other two sides at \(0^{\circ}\).

A metal plate covering the first quadrant has the edge which is along the \(y\) axis insulated and the edge which is along the \(x\) axis held at $$ u(x, 0)=\left\\{\begin{array}{cl} 100(2-x), & \text { for } 0< x < 2 \\ 0, & \text { for } x > 2 \end{array}\right. $$ Find the steady-state temperature distribution as a function of \(x\) and \(y .\) Hint: Follow the procedure of Example \(2,\) but use a cosine transform (because \(\partial u / \partial x=0\) for \(x=0\) ). Leave your answer as an integral like (9.13)

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