Chapter 12: Problem 4
Show that \(\int_{-1}^{1} x^{m} P_{l}(x) d x=0\) if \(m
Short Answer
Expert verified
The integral evaluates to zero due to the orthogonality of Legendre polynomials when \( m < l \).
Step by step solution
01
- Understand Rodrigues' formula
Rodrigues' formula for Legendre polynomials is given by \[ P_l(x) = \frac{1}{2^l l!} \frac{d^l}{dx^l} (x^2 - 1)^l. \] This will be used for further steps.
02
- Initial integral setup
The integral to evaluate is \[ I = \int_{-1}^{1} x^m P_l(x) \, dx. \]
03
- Apply integration by parts
Use integration by parts where \[ u = x^m \text{ and } dv = P_l(x) \, dx. \] Then, \[ du = m x^{m-1} \, dx \text{ and } v = \frac{1}{2^l l!} \int P_l(x) \, dx. \]
04
- Repeatedly differentiate and integrate
Notice that differentiating powers of \( x \) decreases the degree, while integrating the polynomial retains the highest degree term. After repeatedly applying integration by parts, a term with \( P_{l-1}(x) \) will appear.
05
- Examine boundary conditions
Since \( P_l(x) \) is a polynomial of degree \( l \), and the Legendre polynomial satisfies orthogonality, any polynomial of lower degree, here \( x^m \) with \( m < l \), will result in the integral equating to zero.
06
- Conclusion
Therefore, \[ \int_{-1}^{1} x^m P_l(x) \, dx = 0 \] if \( m < l \). The orthogonality condition of Legendre polynomials confirms this.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rodrigues' formula
Rodrigues' formula is fundamental for understanding Legendre polynomials. It provides a way to generate these polynomials systematically. The formula states: \[ P_l(x) = \frac{1}{2^l l!} \frac{d^l}{dx^l} (x^2 - 1)^l \]Here,
This formula shows how to derive \(P_l(x)\) using the derivatives of \((x^2 - 1)^l\). Each Legendre polynomial can thus be expressed in terms of these derivatives, providing a powerful tool for further calculations.
By inserting into integrals or differential equations, Rodrigues' formula streamlines the process and lays the groundwork for more advanced mathematical operations.
- \(P_l(x)\) is the Legendre polynomial of degree \(l\)
- \(2^l\) indicates that the exponent corresponds to the polynomial’s degree
- \(l!\) is the factorial of \(l\)
- \(\frac{d^l}{dx^l}\) represents the \(l-\text{th}\) derivative with respect to \(x\)
This formula shows how to derive \(P_l(x)\) using the derivatives of \((x^2 - 1)^l\). Each Legendre polynomial can thus be expressed in terms of these derivatives, providing a powerful tool for further calculations.
By inserting into integrals or differential equations, Rodrigues' formula streamlines the process and lays the groundwork for more advanced mathematical operations.
Integration by Parts
Integration by parts is a key technique to solve integrals involving products of functions. The rule is generally articulated as: \[ \int u \, dv = uv - \int v \, du\]where
Use this method to tackle the problem where \[ I = \int_{-1}^{1} x^m P_l(x) \, dx \]Assign \(u = x^m\) and \(dv = P_l(x) \, dx\). Differentiating and integrating these parts repeatedly, recalling that differentiating powers of \(x\) decreases the degree, leads to simpler functions.
This gradual breakdown generates new integrals easier to solve or reveals boundary terms that evaluate to zero due to specific limits.
This rule is crucial to simplify and evaluate the integral provided in the exercise.
- \(u\) and its derivative \(du\) are parts of one function
- \(dv\) and its antiderivative \(v\) are parts of another function
Use this method to tackle the problem where \[ I = \int_{-1}^{1} x^m P_l(x) \, dx \]Assign \(u = x^m\) and \(dv = P_l(x) \, dx\). Differentiating and integrating these parts repeatedly, recalling that differentiating powers of \(x\) decreases the degree, leads to simpler functions.
This gradual breakdown generates new integrals easier to solve or reveals boundary terms that evaluate to zero due to specific limits.
This rule is crucial to simplify and evaluate the integral provided in the exercise.
Orthogonality
Orthogonality in the context of polynomials means that the integral of the product of two different polynomials over a specific interval is zero. For Legendre polynomials, this property is mathematically expressed as: \[ \int_{-1}^{1} P_l(x) P_m(x) \, dx = 0, \text{ for } l eq m \]In our exercise, it proves that \( \int_{-1}^{1} x^m P_l(x) \, dx = 0 \) if \( m < l \).
Since \(P_l(x)\) is a polynomial of degree \(l\), any polynomial of lesser degree, like \(x^m\) where \( m < l \), when multiplied and integrated over the same interval with \(P_l(x)\), results in zero.
This orthogonality is a major simplification when dealing with polynomial integrals and is widely used in solving differential equations, series expansions, and more.
These integral properties arise from the symmetry and definition of Legendre polynomials, making them invaluable in mathematical analysis.
Since \(P_l(x)\) is a polynomial of degree \(l\), any polynomial of lesser degree, like \(x^m\) where \( m < l \), when multiplied and integrated over the same interval with \(P_l(x)\), results in zero.
This orthogonality is a major simplification when dealing with polynomial integrals and is widely used in solving differential equations, series expansions, and more.
These integral properties arise from the symmetry and definition of Legendre polynomials, making them invaluable in mathematical analysis.