Chapter 10: Problem 17
Write out the components of \(T_{j k}=A_{j} B_{k}-A_{k} B_{j}\) to show that \(T_{j k}\) is a \(2^{\text {nd }}\) -rank antisymmetric tensor with elements which are the components of \(\mathbf{A} \times \mathbf{B}\).
Short Answer
Expert verified
\(T_{jk} = A_{j}B_{k} - A_{k}B_{j}\) is a 2nd-rank antisymmetric tensor with components matching \(\mathbf{A}\times\mathbf{B}\).
Step by step solution
01
Title - Expand the given tensor expression
Start by writing down the given tensor expression explicitly. The expression for the tensor is given as:\[ T_{j k} = A_{j} B_{k} - A_{k} B_{j} \]
02
Title - Verify antisymmetry
To show antisymmetry, demonstrate that \(T_{jk} = -T_{kj}\). Compute \(T_{kj}\) and compare it to \(T_{jk}\):\[ T_{k j} = A_{k} B_{j} - A_{j} B_{k} \]As seen, \(T_{kj} = -(A_{j} B_{k} - A_{k} B_{j}) = -T_{jk}\). Hence, \(T_{jk}\) is antisymmetric.
03
Title - Expand and match with cross product components
Identify the components of the tensor in three dimensions for \(j, k = 1, 2, 3\). The components correspond to the components of the cross product \(\mathbf{A} \times \mathbf{B}\). For each pair \( (j, k) \):\[ T_{12} = A_{1} B_{2} - A_{2} B_{1} \]\[ T_{13} = A_{1} B_{3} - A_{3} B_{1} \]\[ T_{23} = A_{2} B_{3} - A_{3} B_{2} \]These expressions are the components of the vector \(\mathbf{A} \times \mathbf{B}\):\[ (\mathbf{A} \times \mathbf{B})_{3} = A_{1} B_{2} - A_{2} B_{1} \]\[ (\mathbf{A} \times \mathbf{B})_{2} = -(A_{1} B_{3} - A_{3} B_{1}) \]\[ (\mathbf{A} \times \mathbf{B})_{1} = A_{2} B_{3} - A_{3} B_{2} \]
04
Title - Validate the tensor rank
Since \(T_{jk}\) involves two indices and transforms following coordinate changes, it is a 2nd-rank tensor. The antisymmetric nature and its components linking to the cross product confirm its rank and properties.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Antisymmetric Tensor
An antisymmetric tensor, also known as a skew-symmetric tensor, is a tensor that changes sign when its indices are swapped. In other words, for a tensor to be antisymmetric, we must have:
- T_{jk} = -T_{kj}
Cross Product
The cross product, also known as the vector product, is an operation on two vectors in three-dimensional space. The result is a vector that is perpendicular to both of the original vectors. To find the cross product \( \textbf{A} \times \textbf{B} \) between vectors \( \textbf{A} = (A_1, A_2, A_3) \) and \( \textbf{B} = (B_1, B_2, B_3) \), we can use the following formula:
- \[ (\textbf{A} \times \textbf{B})_1 = A_2 B_3 - A_3 B_2 \]
- \[ (\textbf{A} \times \textbf{B})_2 = A_3 B_1 - A_1 B_3 \]
- \[ (\textbf{A} \times \textbf{B})_3 = A_1 B_2 - A_2 B_1 \]
Second-Rank Tensor
A second-rank tensor is an array of numbers arranged in a square matrix format, typically having two indices. These tensors describe linear relationships between two sets of vectors in various physical phenomena. The notation \( T_{jk} \) signifies that it has two indices: one row (j) and one column (k).To confirm that the given tensor is of the second rank, consider the tensor: \[ T_{jk} = A_j B_k - A_k B_j \]The presence of two indices explicitly (j and k) indicates it is indeed second rank. Second-rank tensors are essential in mechanics and physics as they represent stresses, strains, moments of inertia, and more.
Coordinate Transformation
Coordinate transformation is a mathematical tool used to convert the representation of vectors and tensors from one coordinate system to another. It ensures that the physical laws remain consistent regardless of the coordinate system used. For tensors, the transformation rules vary depending on their rank.For a second-rank tensor \( T_{jk} \), the transformation under a change of coordinates is given by: \[ T'_{jk} = \frac{\text{{∂} x^i}}{\text{{∂} x'^j}} \frac{\text{{∂} x^m}}{\text{{∂} x'^k}} T_{im} \]This transformation rule ensures that the form of the tensor remains consistent when shifting between reference frames. In the context of antisymmetric tensors, the transformation validates that the antisymmetric property is preserved across different coordinates.