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Identify each of the differential equations as to type (for example, separable, linear first order, linear second order, etc.), and then solve it. \(x\left(y y^{\prime \prime}+y^{\prime 2}\right)=y y^{\prime}\) Hint: Iet \(u=1 x\).

Short Answer

Expert verified
Nonlinear second-order differential equation, solve using substitution and integration for transformation of simpler equation

Step by step solution

01

Identify the type of differential equation

Given the differential equation: \[ x\left(yy^{\prime \prime} + y^{\prime 2}\right) = yy^{\prime} \] This is a nonlinear second-order differential equation due to the presence of the term \(yy^{\prime \prime}\) and the product of derivatives \(y^{\prime 2}\).
02

Apply the substitution

Use the hint provided, where \( u = y/x \). This implies that: \[ y = ux \quad and \quad y^{\prime} = u + xu^{\prime} \] Substituting these into the original equation to simplify.
03

Simplify the equation

Substitute \( y = ux \) and \( y^{\prime} = u + xu^{\prime} \) into the original equation: \[ x\left(y(y^{\prime \prime}) + y^{\prime 2} \right) = yy^{\prime} \] This becomes: \[ x\left((ux)(xu^{\text{\textbrokenbar}} + u) + (u + xu^{\text{\textbrokenbar}})^2\right) = (ux)(u + xu^{\text{\textbrokenbar}}) \]
04

Transform and solve the simplified equation

Further simplify and separate variables to solve for \( u \). First simplify the expressions within the equation: \[ x\left(uxxu^{\text{\textbrokenbar}} + uxu + u^2 + 2xu^2u^{\text{\textbrokenbar}} + (xu^{\text{\textbrokenbar}})^2\right)= xuu + x^2 u^{\text{\textbrokenbar}}) \]Combine like terms to manage the transformed differential equation.
05

Integrate to find the solution for the transformed differential equation

Solve the obtained differential by integrating and reversing the substitution \(u = y/x\). One receives: \[y/x =\int 1/dx \] leading \[ y = x^\textplainform \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonlinear Second-Order Differential Equations
In the given problem, we are dealing with a nonlinear second-order differential equation. These types of equations have derivatives that are not linear, and the highest derivative is of the second order. In our exercise, this is clearly seen in the equation: \[ x(yy^{\text{\textbrokenbar}} + y^{\text{\textbrokenbar} 2}) = yy^{\text{\textbrokenbar}}. \] Nonlinearity is indicated by the product of derivatives and the presence of terms like \( yy^{\text{\textbrokenbar}} \). Solving such equations often requires specific techniques and sometimes creative substitutions.
Substitution Method
Substitution is a powerful technique to simplify complex differential equations. Here, the hint suggests using \( u = y/x \). This transformation makes the equation more manageable. Rewriting \( y \) and its derivatives in terms of \( u \) gives: \[ y = ux \quad \text{and} \quad y^{\text{\textbrokenbar}} = u + xu^{\text{\textbrokenbar}}. \] By substituting these into the original equation, it changes the form and reduces its complexity. After substitution and simplifying, the new form of the equation often becomes more approachable.
Integration
Integration is a core step in solving differential equations, especially after simplifying through substitution. Here, once the equation is simplified, it is separated to allow integration: \[ \frac{dy}{dx} = f(u). \] Integrating with respect to \(x\) helps find solutions in terms of \(u\), and then reversing the substitution \( u = y/x \) reverts the solution back to the original variables. Integration bridges the gap between transforming the differential equation and getting back to the function of interest. It’s essential to perform each integration step carefully to ensure the solution aligns with the initial conditions and requirements of the problem.

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Most popular questions from this chapter

The differential equation for the path of a planet around the sun (or any object in an inverse square force field) is, in polar coordinates, $$ \frac{1}{r^{2}} \frac{d}{d \theta}\left(\frac{1}{r^{2}} \frac{d r}{d \theta}\right)-\frac{1}{r^{3}}=-\frac{k}{r^{2}} $$ Make the substitution \(u=1 / r\) and solve the equation to show that the path is a conic section.

Solve the following differential equations. \(y^{\prime \prime}+2 y^{\prime}+2 y=0\)

Identify each of the differential equations as to type (for example, separable, linear first order, linear second order, etc.), and then solve it. \(3 x^{3} y^{2} y^{\prime}-x^{2} y^{3}=1\)

Find the "general solution" (that is, a solution containing an arbitrary constant) of each of the following differential equations, by separation of variables. Then find a particular solution of each equation satisfying the given boundary conditions. \(x y^{\prime}=y\), \(y=3\) when \(x=2\).

The momentum \(p\) of an electron at velocity \(v\) near the velocity \(c\) of light increases according to the formula $$ p=\frac{m_{0} v}{\sqrt{1-v^{2} / c^{2}}} $$ where \(m_{0}\) is a constant (the rest mass). If an electron is subject to a constant force \(F\), Newton's second law describing its motion is $$ \frac{d p}{d t}=\frac{d}{d t}\left(\frac{m_{0} v}{\sqrt{1-v^{2} / c^{2}}}\right)=F $$ Find the velocity as a function of time and show that the limiting velocity as \(t\) tends to infinity is \(c\). Find the distance traveled by the electron in time \(t\) if it starts from rest.

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