Chapter 8: Problem 16
Solve the differential equation \(y y^{\prime 2}+2 x y^{\prime}-y=0\) by changing from variables \(y, x\), to \(r, x\), where \(y^{2}=r^{2}-x^{2}\); then \(y y^{\prime}=r^{\prime}-x\).
Short Answer
Expert verified
Apply the change of variables and solve the simplified equation.
Step by step solution
01
Change of Variables
Convert the given function from variables \(y, x\) to \(r, x\) using the given relationship \(y^2 = r^2 - x^2\).
02
Express y in Terms of r and x
From \(y^2 = r^2 - x^2\), solve for \(y\), resulting in \(y = \sqrt{r^2 - x^2}\).
03
Calculate the Derivative
Determine \(y'\) by differentiating \(y = \sqrt{r^2 - x^2}\) with respect to \(x\). Use the chain rule to get \(y' = \frac{-x}{\sqrt{r^2 - x^2}}\).
04
Express \(yy'\) in Terms of r and its Derivatives
Given \(yy' = r' - x\), substitute \(y'\) to express \(yy'\) in the appropriate terms. This gives \(y \cdot \frac{-x}{\sqrt{r^2 - x^2}} = R' - x\).
05
Simplify the Original Equation
Substitute all the expressions derived above into the original differential equation \(y y^{\frac{2}} +2x y' - y = 0\). Simplify and solve for \(r\).
06
Solve the Differential Equation
Given the simplifications and changes of variables, solve the resulting equation for \(r\) and subsequently for \(y\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Change of Variables
Changing variables is a powerful technique in solving differential equations where direct methods seem cumbersome. Here, the given differential equation involves variables \(y, x\). By introducing a new variable \(r\), we can potentially simplify the equation. We use the relationship \(y^2 = r^2 - x^2\). This substitution changes the functions and potentially reduces the complexity. This transformation helps in re-framing the problem into a more manageable form.
Consider how the relationship \(y^2 = r^2 - x^2\) mandates that each side be equal for all \(x\) and thus encapsulates the essence of the transformation.
Consider how the relationship \(y^2 = r^2 - x^2\) mandates that each side be equal for all \(x\) and thus encapsulates the essence of the transformation.
Chain Rule
The chain rule is essential in calculus for finding derivatives of composite functions. In this context, it's crucial for differentiating complex expressions indirectly.
Here, we need to find the derivative of \(y = \sqrt{r^2 - x^2}\). Using the chain rule, we consider \(r\) as a function of \(x\). Consequently, the derivative of \(y\) with respect to \(x\) becomes \(-x / \sqrt{r^2 - x^2}\).
This step is significant as it translates the derivatives from one set of variables to another, paving the way for further simplification.
Here, we need to find the derivative of \(y = \sqrt{r^2 - x^2}\). Using the chain rule, we consider \(r\) as a function of \(x\). Consequently, the derivative of \(y\) with respect to \(x\) becomes \(-x / \sqrt{r^2 - x^2}\).
This step is significant as it translates the derivatives from one set of variables to another, paving the way for further simplification.
Differentiation
Differentiation involves finding the rate at which a function changes. In the given problem, differentiating \(y\) with respect to \(x\) is crucial to progress further.
The direct differentiation of \(y = \sqrt{r^2 - x^2}\) gives us \(y' = \frac{-x}{\sqrt{r^2 - x^2}}\). This step is directly influenced by the chain rule. Here, the negative sign indicates the directional change of the slope concerning \(x\).
This computation aligns with transforming the original differential equation into a new form that is easier to solve.
The direct differentiation of \(y = \sqrt{r^2 - x^2}\) gives us \(y' = \frac{-x}{\sqrt{r^2 - x^2}}\). This step is directly influenced by the chain rule. Here, the negative sign indicates the directional change of the slope concerning \(x\).
This computation aligns with transforming the original differential equation into a new form that is easier to solve.
Simplification
Simplification is the process of rewriting mathematical expressions in a more readable or solvable form. Once we have our derivatives, we substitute them back into the original equation \(y y^{\frac{2}} + 2x y' - y = 0\).
This requires careful algebraic manipulation to minimize complexity. In this scenario, expressing \(yy' = r' - x\) and combining terms accordingly simplifies the differential equation.
Typically, simplification reduces terms to expose easier paths to solutions, making the final integration step more straightforward.
This requires careful algebraic manipulation to minimize complexity. In this scenario, expressing \(yy' = r' - x\) and combining terms accordingly simplifies the differential equation.
Typically, simplification reduces terms to expose easier paths to solutions, making the final integration step more straightforward.
Integration
Integration is the reverse process of differentiation, and itβs often used to solve differential equations. In this transformed problem, the final goal is to integrate the simplified equation for \(r\) to find its behaviour over \(x\).
Based on the substitution and derived expressions, integrating helps us revert to the original variable. In our case, solving for \(r\) and substituting back to find \(y\) completes the solution process.
Integration aggregates the changes of a function over an interval, providing a comprehensive solution.
Based on the substitution and derived expressions, integrating helps us revert to the original variable. In our case, solving for \(r\) and substituting back to find \(y\) completes the solution process.
Integration aggregates the changes of a function over an interval, providing a comprehensive solution.