Chapter 8: Problem 14
Find the general solution of each of the following differential equations.
Short Answer
Expert verified
\frac{3}{5} y^{5/3} - \frac{1}{2} y^2 = 3x + C
Step by step solution
01
Identify the form of the differential equation
The given differential equation is . It can be identified as a separable differential equation.
02
Rewrite the equation to separate variables
To separate the variables, rewrite the equation: . Multiply both sides by and to get .
03
Simplify and further separate the variables
Rearrange terms to isolate all terms involving on one side and all terms involving on the other. . Simplify to .
04
Integrate both sides
Integrate both sides to solve for . For the left-hand side, the integral becomes . For the right-hand side, the integral is . Combining these, we get .
05
Simplify the general solution
Combine and simplify the constants to write the general solution. The final form of the general solution will be .
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
differential equations
A differential equation is an equation that involves unknown functions and their derivatives. These equations play a crucial role in various fields like physics, engineering, and economics.
By finding solutions to these equations, we can predict how systems change over time. There are different types of differential equations, but one of the simplest forms is a first-order differential equation.
In this exercise, we are dealing with a first-order differential equation represented as .
Our goal is to find the general solution, which helps us understand how the dependent variable, y, changes concerning the independent variable, x.
By finding solutions to these equations, we can predict how systems change over time. There are different types of differential equations, but one of the simplest forms is a first-order differential equation.
In this exercise, we are dealing with a first-order differential equation represented as
Our goal is to find the general solution, which helps us understand how the dependent variable, y, changes concerning the independent variable, x.
integration
Integration is a fundamental concept in calculus that can be thought of as the reverse process of differentiation. In the context of differential equations, integration is used to solve equations involving derivatives.
When we integrate, we effectively find the original function given its derivative. For example, if we have , integrating both sides with respect to x will give us the original function y in terms of x.
In our exercise, after separating the variables, we perform integration on both sides of the equation. Specifically, we integrate with respect to y and 3 with respect to x. The integration results help us combine the terms to form the general solution.
When we integrate, we effectively find the original function given its derivative. For example, if we have
In our exercise, after separating the variables, we perform integration on both sides of the equation. Specifically, we integrate
variables separation
Separation of variables is a method for solving first-order differential equations. The idea is to rearrange the equation so that all terms involving the dependent variable (y) are on one side, and all terms involving the independent variable (x) are on the other.
For our differential equation , we multiply both sides by and to separate the variables. This step yields .
Next, we isolate the terms to get . This format allows us to integrate both sides easily.
For our differential equation
Next, we isolate the terms to get
general solution
The general solution to a differential equation is a family of functions that includes an arbitrary constant, usually denoted as C. This constant represents an infinite number of possible solutions, each corresponding to a different initial condition.
After performing the necessary integrations, we get a combined solution involving the constant C. In our exercise, after integrating both sides, we obtain . This is the general solution to our differential equation.
This form provides a complete description of all possible solutions and how y changes concerning x for various initial conditions.
After performing the necessary integrations, we get a combined solution involving the constant C. In our exercise, after integrating both sides, we obtain
This form provides a complete description of all possible solutions and how y changes concerning x for various initial conditions.