Chapter 6: Problem 13
Calculate the Laplacian \(\nabla^{2}\) of each of the following scalar fields.\(x y\left(x^{2}+y^{2}-5 z^{2}\right)\)
Short Answer
Expert verified
\[ abla^{2} = 2xy \]
Step by step solution
01
- Understand the Laplacian Operator
The Laplacian of a scalar field \( abla^{2} \) is given by \( abla^{2} = \frac{\partial^{2}}{\partial x^{2}} + \frac{\partial^{2}}{\partial y^{2}} + \frac{\partial^{2}}{\partial z^{2}} \). For a scalar field \( f(x, y, z) \), this means you need to compute the second partial derivatives with respect to \( x \), \( y \), and \( z \) and sum them up.
02
- Compute First Partial Derivatives
Find the first partial derivatives of \( f(x, y, z) = x y (x^{2} + y^{2} - 5 z^{2}) \) with respect to \( x \), \( y \), and \( z \) respectively. For \( x \): \[ \frac{\partial f}{\partial x} = y (3x^{2} + y^{2} - 5z^{2}) \] For \( y \): \[ \frac{\partial f}{\partial y} = x (x^{2} + 3y^{2} - 5z^{2}) \] For \( z \): \[ \frac{\partial f}{\partial z} = -10 x y z \]
03
- Compute Second Partial Derivatives
Find the second partial derivatives of each of the first partial derivatives. For \( x \): \[ \frac{\partial^{2} f}{\partial x^{2}} = y (6x) = 6xy \] For \( y \): \[ \frac{\partial^{2} f}{\partial y^{2}} = x (6y) = 6xy \] For \( z \): \[ \frac{\partial^{2} f}{\partial z^{2}} = -10 x y \]
04
- Sum the Second Partial Derivatives
To find the Laplacian, add up all the second partial derivatives: \[ abla^{2} f = \frac{\partial^{2} f}{\partial x^{2}} + \frac{\partial^{2} f}{\partial y^{2}} + \frac{\partial^{2} f}{\partial z^{2}} = 6xy + 6xy - 10xy = 2xy \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Derivatives
Partial derivatives are a fundamental concept in multivariable calculus. They measure how a function changes as each variable changes, while keeping all other variables constant.
For example, if we have a scalar field function like \(f(x, y, z) = x y (x^{2} + y^{2} - 5 z^{2})\), we can find the partial derivatives with respect to each variable: \(x\), \(y\), and \(z\).
To find the partial derivative with respect to \(x\), we treat \(y\) and \(z\) as constants. This gives us: \[ \frac{\frac{\tau}{\tau x}} = y (3x^{2} + y^{2} - 5z^{2}) \]
Similarly, we find it for y by treating \(x\) and \(z\) as constants: \[ \frac{\tau f}{\tau y} = x (x^{2} + 3y^{2} - 5z^{2}) \]
Finally, for z: \[ \frac{\tau f}{\tau z} = -10 x y z \]
For example, if we have a scalar field function like \(f(x, y, z) = x y (x^{2} + y^{2} - 5 z^{2})\), we can find the partial derivatives with respect to each variable: \(x\), \(y\), and \(z\).
To find the partial derivative with respect to \(x\), we treat \(y\) and \(z\) as constants. This gives us: \[ \frac{\frac{\tau}{\tau x}} = y (3x^{2} + y^{2} - 5z^{2}) \]
Similarly, we find it for y by treating \(x\) and \(z\) as constants: \[ \frac{\tau f}{\tau y} = x (x^{2} + 3y^{2} - 5z^{2}) \]
Finally, for z: \[ \frac{\tau f}{\tau z} = -10 x y z \]
- Partial derivatives allow us to explore changes in the function in different directions.
- They are crucial for finding gradients, important in optimization, and essential in understanding physical phenomena like heat distribution and fluid flow.
Scalar Field
A scalar field assigns a scalar value (a single number) to every point in space. Scalars have magnitude but no direction.
For instance, consider a temperature map of a room. At each point in the room, you can measure the temperature. The temperature at any point is a scalar value, making temperature a scalar field.
In the given problem, our scalar field is defined by the function: \(f(x, y, z) = xy(x^{2} + y^{2} - 5z^{2})\).
For instance, consider a temperature map of a room. At each point in the room, you can measure the temperature. The temperature at any point is a scalar value, making temperature a scalar field.
In the given problem, our scalar field is defined by the function: \(f(x, y, z) = xy(x^{2} + y^{2} - 5z^{2})\).
- Scalar fields help model real-life phenomena such as temperature, pressure, and gravitational potential.
- The fact that scalar fields only have a magnitude makes them easier to handle than vector fields.
Second-Order Derivatives
Second-order derivatives provide information about the curvature or concavity of a function. They reflect how the rate of change of a function's derivative changes.
To calculate the second-order derivatives for our function, we first needed the first-order derivatives: \[ \frac{\tau^{2}f}{\tau x^{2}} = y(6x) = 6xy \] \[ \frac{\tau^{2}f}{\tau y^{2}} = x(6y) = 6xy \] \[ \frac{\tau^{2}f}{\tau z^{2}} = -10xy \]
Summing these gives us the Laplacian: \[ abla^{2} f = 6xy + 6xy - 10xy = 2xy \].
To calculate the second-order derivatives for our function, we first needed the first-order derivatives: \[ \frac{\tau^{2}f}{\tau x^{2}} = y(6x) = 6xy \] \[ \frac{\tau^{2}f}{\tau y^{2}} = x(6y) = 6xy \] \[ \frac{\tau^{2}f}{\tau z^{2}} = -10xy \]
Summing these gives us the Laplacian: \[ abla^{2} f = 6xy + 6xy - 10xy = 2xy \].
- Second-order derivatives help identify concavity and points of inflection in functions.
- They are used in optimization problems to determine maxima, minima, and saddle points.