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Show that the expectation of the sum of two random variables defined over the same sample space is the sum of the expectations. Hint: Let \(p_{1}, p_{2}, p_{3}, \cdots, P_{*}\) be the probabilitics associated with the \(n\) sample points; let \(x_{1}, x_{2}, \cdots, x_{n}\), and \(y_{1}, y_{2}, \cdots, y_{n}\), be the values of the random variables \(x\) and \(y\) for the \(n\) sample points. Write out \(E(x), E(y)\), and \(E(x+y)\).

Short Answer

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The expectation of the sum of two random variables is the sum of their expectations: \( E(x + y) = E(x) + E(y) \).

Step by step solution

01

Define the Expectation of a Random Variable

The expectation (or expected value) of a random variable is the weighted average of all possible values that the random variable can take, with the probabilities as weights. For a random variable \(x\) with values \(x_1, x_2, \, ... , x_n\) and corresponding probabilities \(p_1, p_2, \, ... , p_n\), the expectation is given by: \[ E(x) = \sum_{i=1}^{n} p_i x_i \]
02

Write Out the Expectation of \(x\)

Using the definition from Step 1, the expectation of the random variable \(x\) is: \[ E(x) = \sum_{i=1}^{n} p_i x_i \]
03

Write Out the Expectation of \(y\)

Similarly, for another random variable \(y\) with values \(y_1, y_2, \, ... , y_n\) and corresponding probabilities \(p_1, p_2, \, ... , p_n\), the expectation is given by: \[ E(y) = \sum_{i=1}^{n} p_i y_i \]
04

Define the Sum of the Two Random Variables

The sum of the two random variables \(x\) and \(y\) at each sample point can be written as \(x_i + y_i\). We need to find the expectation of the sum \( E(x + y) \).
05

Write Out the Expectation of \(x + y\)

Using the linearity of expectation, we have: \[ E(x + y) = \sum_{i=1}^{n} p_i (x_i + y_i) \]
06

Apply the Distributive Property

Apply the distributive property to the sum in the expression for \( E(x + y) \): \[ E(x + y) = \sum_{i=1}^{n} p_i x_i + \sum_{i=1}^{n} p_i y_i \]
07

Use Definition of Expectation

Recognize that the two sums can be rewritten as the expectations of \(x\) and \(y\) respectively: \[ E(x + y) = E(x) + E(y) \]
08

Conclusion: State the Result

We have shown that the expectation of the sum of two random variables is equal to the sum of the expectations of those two random variables, i.e., \[ E(x + y) = E(x) + E(y) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a branch of mathematics that deals with the analysis of random phenomena. The outcome of a random event can be one of several possible results, and the likelihood of each result is quantified by a probability. Probability values range from 0 (indicating an impossible event) to 1 (indicating a certain event). For instance, flipping a fair coin has two possible outcomes, heads or tails, each with a probability of 0.5.
A key part of probability theory involves understanding how different probabilities relate and interact, such as through the concepts of independent and dependent events. It's foundational for comprehending random variables and their behaviors, which leads us into the next important concept.
Linearity of Expectation
Linearity of expectation is a fundamental and very useful principle in probability theory. It states that for any two random variables, the expected value (also known as the expectation) of their sum is equal to the sum of their individual expected values. Mathematically, this can be expressed as: Note that this property does not require the random variables to be independent. This normalization makes expectation calculations much easier and is crucial in fields like statistics, economics, and data science.
Random Variables
A random variable is a numerical description of the outcome of a statistical experiment. There are two main types of random variables: discrete and continuous.

  • Discrete random variables can only take on a finite or countably infinite number of distinct values. Examples include the number of heads in a series of coin flips, or the outcome of rolling a six-sided die.
  • Continuous random variables can take an infinite number of possible values within a given range. Examples are the height of students in a class, or the time it takes for a computer algorithm to run.
For both types, the expectation (or expected value) is a weighted average of the possible values, with the weights being the probabilities of those values. Mathematically, for a discrete random variable, the expectation is given by:

For a continuous random variable, it is given by: Understanding these concepts is essential for analyzing how random variables behave and for calculating important metrics such as variances, covariances, and standard deviations.

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Most popular questions from this chapter

A circular garden bed of radius \(1 \mathrm{~m}\) is to be planted so that \(N\) seeds are uniformly distributed oser the circular area. Then we can talk about the number \(n\) of seeds in some particular area \(A\), or we can call \(n / N\) the probability for any one particular seed to be in the area \(A\). Find the probability \(F(r)\) that a seed (that is, some particular seed) is within \(r\) of the center.

You are trying to find instrument \(A\) in a laboratory. Unfortunately, someone has put both instruments \(A\) and another kind (which we shall call \(B\) ) away in identical unmarked boxes mixed at random on a shelf. You know that the laboratory has \(3 \mathrm{~A} \mathrm{~s}\) and \(7 \mathrm{~B}^{\prime} \mathrm{s}\). If you take down one box, what is the probability that you get an \(A\) ? If it is a \(B\) and you put it on the table and take down another box, what is the probability that you get an \(A\) this time?

Define the sample variance by \(s^{2}=(1 / n) \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)^{2} .\) Show that the expected value of \(s^{2}\) is \([(n-1) / n] \sigma^{2} .\) Hints: Write $$ \begin{aligned} \left(x_{i}-\bar{x}\right)^{2} &=\left[\left(x_{i}-\mu\right)-(\bar{x}-\mu)\right]^{2} \\ &=\left(x_{i}-\mu\right)^{2}-2\left(x_{i}-\mu\right)(\bar{x}-\mu)+(\bar{x}-\mu)^{2} \end{aligned} $$ Find the average value of the first term from the definition of \(\sigma^{2}\) and the average value of the third term from Problem 2, To find the average value of the middle term write $$ (\bar{x}-\mu)=\left(\frac{x_{1}+x_{2}+\cdots+x_{n}}{n}-\mu\right)=\frac{1}{n}\left[\left(x_{1}-\mu\right)+\left(x_{2}-\mu\right)+\cdots+\left(x_{n}-\mu\right)\right] $$ show by Problem \(7.12\) that $$ E\left[\left(x_{i}-\mu\right)\left(x_{j}-\mu\right)\right]=E\left(x_{i}-\mu\right) E\left(x_{j}-\mu\right)=0 \quad \text { for } \quad t \neq j $$ and evaluate \(E\left[\left(x_{i}-\mu\right)^{2}\right]\) (same as the first term). Collect terms to find $$ E\left(s^{2}\right)=\frac{n-1}{n} \sigma^{2} $$

Two dice are thrown. Given the information that the number on the first die is even, and the number on the second is \(<4\), set up an appropriate sample space and answer the following questions. (a) What are the possible sums and their probabilities? (b) What is the most probable sum? (c) What is the probability that the sum is even?

Two cards are drawn from a shuffled deck. What is the probability that both are aces? If you know that at least one is an ace, what is the probability that both are aces? If you know that one is the ace of spades, what is the probability that both are aces?

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